580340 Determination of Water Hardness by Titration Q

Data for titration of 15.00 mL of vinegar with approximately 1.0 M NaOH. Note you must use the exact concentration of the standard NaOH solution to calculate the moles of NaOH. Quantity Еxample Trial 1 Trial 2 Trial 3 M NaOH (exact concentration) 0.992 M 0.953 M 0.953 M 0.953 M V initial buret reading = V, 0.20 mL 1.20 mL 0.52 mL 0.15 mL V final buret reading = V, 12.90 mL 14.22 mL 13.71 mL 13.31 mL %3D Vep = VNAOH added = V; - V, 12.70 mL 13.02 mL 13.19 mL 13.16 mL Vep = VNAOH in L 0.01270 L 0.01302 L 0.01319 L 0.01316 L moles NaOH = 0.0126 mol 0.0124 mol 0.0126 mol 0.0125 mol MNAOH X VNAOH moles AA = 0.0126 mol 0.0124 mol 0.0126 mol 0.0125 mol moles NaOH V sample = V acid 0.0150 L 0.0150 L 0.0150 L 0.0150 L (15.00 mL) (15.00 mL) (15.00 mL) Actual molarity 0.840 M 0.827 M 0.840 M 0.833 M of AA Average molarity for 3 trials => of AA 0.833 M 1. Report the acetic acid (AA) concentration of vinegar in units of molarity (M). 2. Use your average AA concentration to calculate the mass…

Data Table 3: Complexometric Titration of Soft Water 5 ml of water  1ml of buffer        Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 77ml 79ml 75ml Volume of EDTA Consumed (mL) .23ml .21ml .25ml Water Hardness ppm CaCO3 (mg/L)         Average ppm CaCO3 (mg/L):

Concentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (ml) Volume titration 2, (ml) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (mL) Standard deviation Number of moles sodium thiosulfate used, (mol) Number of moles calcium iodate in solution, (mol) Volume of calcium iodate used, (mL) Concentration of saturated calcium iodate solution (mol L-¹) Unrounded value 15.9750 0.26220 Rounded value 15.97 0.262 10.0

Concentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (mL) Volume titration 2, (mL) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (ml) Standard deviation Number of moles sodium thiosulfate used, (mol) Number of moles calcium iodate in solution, (mol) Volume of calcium iodate used, (mL) Concentration of saturated calcium iodate solution (mol L-¹) Unrounded value 15.9750 0.26220 0.00089400 0.00036700 A Rounded value 15.97 0.262 8.94 x 10-4 10.0 Minimize

Calculate the total volume of HCl titrant delivered to the equivalence point for each trial

How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations.

Concentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (ml) Volume titration 2, (mL) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (mL) Standard deviation Unrounded value Rounded value

Preparation and Standardization of KMnO4 solution Experimental data Complete the table below. Trial 1 0.2001 g Trial 2 0.2065 g Trial 3 Weight of sodium oxalate (Na2C2O4, MM= 134 g/mol) Titration data 0.2050 g Final reading Initial reading 29.86 mL 0.00 mL 30.66 mL 30.52 mL 0.00 mL 0.00 mL Total vol. of KMNO4 used Computed Molarity of KMNO4 solution Mean Molarity Computed Normality of KMNO4 Mean Normality of KMNO4 solution Reaction Involved: Calculations:

Table 2. Titration data   Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.19   2.26   2.39   Molarity of NaOH (M) 0.100   0.100   0.100   Volume of vinegar sample (mL) 5.00   5.00   5.00   Final burette reading (mL) 48.55   49.43   49.99   Expected color at end point             Volume of NaOH used (mL)           Average Volume of NaOH used in liters   Average moles of NaOH used (mol)   Average moles of acetic acid (mol)   Average molarity of acetic acid (M)     Average mass of acetic acid (g)   Average mass of vinegar (g) (assume the density of vinegar is 1.00 g/mL)   Average mass % of acetic acid in vinegar   Known mass % of acetic acid in vinegar is 5.45%   Percent Error

Determine the concentration of acetic acid and vinegar

Sample # 1 2 0.2425 0.2160 0.2274 Weighed mass of ascorbic acid (g) volume of KIO3 (mL) 18.86 17.91 17.37 0.02459 0.02462 0.02432 [KIO3] (mol L-1) Mean [KIO3] (based on titration) 0.02451 mol L-1 Standard deviation in the mean [KIO3] mol L-1 Confidence limit for the [KI03] mol L-1 Relative confidence limit for the [KIO3] ppt =

Part A: Standardization of a Sodium Hydroxide Solution   Titration 1 Titration 2 Titration 3 Mass of 125 mL flask 45.849g 46.715g 44.953g Mass of flask and KHP 46.849g 47.745g 46.003g Initial buret reading (mL) 0.5 ml 0.5 ml 0.5 ml Final buret reading (mL) 27.8 ml 26.5 ml 26.7 ml Volume of NaOH used (mL) 45.11 ml 45.06 ml 45.14 ml   Calculations   Titration 1 Titration 2 Titration 3 Moles of KHP       Moles of NaOH       Molarity of NaOH         Average Molarity of NaOH: _______________

Data Table 1: Complexometric Titration of Hard Water 6ml of water used (5ml of hard water and 1ml of buffer)      Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 0.55ml .50ml .33ml Volume of EDTA Consumed (mL) 0.45ml .50ml .77ml Water Hardness ppm CaCO3 (mg/L)         Average ppm CaCO3 (mg/L):     photo shows equation that needs to be used to solve

20 mL of 0.1M titrand titrated with 0.1M titrant. Data points at 1 mL increments. 14.0 12.0 10.0 HO 8.0 6.0 4.0 2.0 0.0 0.0 10.0 20.0 30.0 Volume of titrant (mL) 40.0 444444 50.0 (a) Is the species being titrated an acid or a base? (b) Is the species being titrated strong or weak? (c) What is the value of Ka (if a weak acid) or K (if a weak base) for the species being titrated? If the species is strong (100% dissociated), enter 999.

Hi, I just need to know the correct answer for these. Thank you

Data: Table 1: Titration of 1.00 mL H2O2 with KMNO4 0.1134M Concentration of KMNO4 Trial # Initial KMNO4 Volume (mL) Final KMNO4 Volume (mL) Volume KMnO4 Used (mL) 1 10 2 10 19.7 19.7 29.6 Pre-lab: 1. What is a titrant? What is the titrant in this lab? 2. What is an analyte? What is the analyte in this lab?

A student performed three aqueous layer titrations in Part 1 and they reported the following measurements: Final Burette Reading Initial Burette Reading Volume of Aqueous Aliquot Final Burette Reading Initial Burette Reading Volume of Sodium Thiosulfate Determination #1 16.33 mL 6.50 mL 9.83 m 31.98 mL 0.76 mL 31.22 mL Determination #2 Determination #3 26.76 mL 16.33 mL 10.43 mL 33.62 mL 0.88 mL 32.74 mL 36.95 mL 26.76 mL 10.19 mL 32.22 mL 0.41 mL 31.81 mL Which determinations were the student's 'best two'? Calculate the percent difference for the 'best two' and show the complete calculation. Note that the concentration of standard sodium thiosulfate, which the student used, is unknown.

Understanding of food analysis methods.  Principles of method described compared to other techniques.   1 The MOHR Titration, AOAC Method? What is it and how does it work? How can it be used to quantify salt in a sample. 2 Are there any advantages and/or disadvantages of this method?3 Are there any alternate methods better than the Mohr Titration toquantitatively determine salt in a sample? 4. Diseases with recent statistics? Refer to World Health Organisation? 5. Why analayse salt? 6. Consumption? 7.  Main aims of study?

Titration Experiment 1: Acid-Base Titration: Unknown HCl Write chemical equation *+ HClcags N s → Naclceg) + H,O Write NIE OH c) + HEogs → H2OC) Enter the data into the table and choose three titrations to find the molarity of the unknown HCI. Unknown # HCI Titration 1 Titration 2 Titration 3 Titration 4 Titration 5 Volume NaOH used to titrate unknown HCI solution 17.43ml 16.5O ml662 mll16.57ml16.6dmL Molarity of NaOH used for each titration 0.2564 0.1787/01692/0.1704/oiado1703 Molarity of HCI Average M HCI (avg ± standard deviation) 10.1717 1.63 % Precision Calculations 1. Provide one representative calculation that you used to determine the molarity of HCI. Be sure to show all units and use proper sig figs! V HCI-25mL MHCI =? VN2OH = 16.6lmL MNAOH=0.2564 MHCI VHCI=MNAOH VAa OH MHCI 25=O. 1564 16.61 MHCI= 0.2564.16.61 25 MHCI=0.1703 2. Average molarity of three titrations. 6.1787+0.1692+0.1704+0.1619+ O.1703 MACI= 0.117

Xanthurenic acid stock solution Absorbance     25 0.052 50 0.128 75 0.202 100 0.310 150 0.448 200 0.621 Plot a graph, from graph, y=mx (force the trend line to pass through origin since the blank with no xanthurenic acid was set to be zero absorbance) in which, y: Absorbance, x concentration

Calculate the average concentration of Vitamin C in each sample

Acid-Base titration: Standardization of 0.1 M NAOH Trial 1 Mass KHP used, g 0.297 g Final reading Volume NaOH, mL 15.59 mL Initial reading Volume NaOH, mL 0.23 mL Volume NaOH consumed, mL 15.36 mL Moles KHP used Moles NaOH used Molarity of NaOH solution

Students measured the concentration of HCl in a solution by titrating with different indicators to find the end point. (Use the table to find critical F values.) Mean HCl concentration (M) (+ standard deviation) Indicator Number of measurements 1. Bromothymol blue 0.09565 + 0.00170 28 2. Methyl red 0.08681 ± 0.00098 18 3. Bromocresol green 0.08641 + 0.00106 29 Is the difference between Indicators 1 and 2 significant at the 95% confidence level? O Yes O No Fenlculated clegrees of freedom Ecalculated Is the difference between indicators 2 and 3 significant at the 95% confidence level? O Yes O No Fealculated Spooled tcalculated