Module #2 Post-Lab Question Submission
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Module #2 Post-Lab Questions and Calibration Plot Bin#5
Evan Dangler
September 15, 2022
CHM 2045L-034
Serial Data:
Sample
Concentration(M)
Absorbance
Linear Equation
Stock
7.5 x 10^-5 M
.69
y = 7836.2x + 0.0906
A
(7.5 x 10^-5) (4) / 10 = 3.0 x 10^-5 M
.30
B
(3.0 x 10^-5) (4) / 10 = 1.2 x 10^-5 M
.19
C
(1.2 x 10^-5) (4) / 10 = 4.8 x 10^-6 M
.13
D
(4.8 x 10^-6) (4) / 10 = 1.9 x 10^-6 M
.10
Parallel Data
:
Sample
Concentration(M)
Absorbance
Linear Equation
Stock
7.5 x 10^-5 M
.69
y = 8120.6x + 0.0956
A
(7.5 x 10^-5) (1) / 10 = 7.5 x 10^-6 M
.12
B
(7.5 x 10^-5) (2) / 10 = 1.5 x 10^-5 M
.22
C
(7.5 x 10^-5) (3) / 10 = 2.3 x 10^-5 M
.30
D
(7.5 x 10^-5) (4) / 10 = 3.0 x 10^-5 M
.37
1.
What is the relationship between absorbance and concentration?
Depending on how concentrated the water is will determine how much it can absorb. If there is a
higher concentration it will have a higher absorbance.
2.
Which dilution technique is more suitable choice for the purpose of creating a
calibration curve?
The Serial dilution technique is better because it has a higher reliance level (0.9921).
3.
If a solution is blue-colored, what wavelength of light (in nm) is being absorbed?
If the solution is blue-colored, the wavelength is around 600. The color being absorbed is
orange so therefore the blue will be perceived.
5.
Why is the wavelength of light set at maximum absorbance when making a Beer’s
Law Plot?
It is able to absorbs the most light at the peak of the graph making it the most accurate
measurement of absorbance.
Calibration Curves
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A liquid sample was analyzed for Fe³+. A plot of absorbance (y-axis) vs. concentration
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y = 0.2256x -0.0903 (R² = 0.9973). The absorbance of the sample was 1.25. Determine
the amount of Fe³+ in the sample (in ppm).
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Absorbance vs. Molarity
18
y3 67024x-0.0343
16
14
12
1
0.8
0.6
0.4
0.2
01
0.2
0.000005 00001
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Concentration of solutions, mol/L
0.00002
0.000025 000003
0 163e-5
O 2.35e-6
0 163
0 235
Absorbance
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A calibration plot was constructed using x as the concentration for AB in M and y as the absorbance value of AB, it provided the linear equation : y=25x+0.0008.
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2. A linear standard curve of KMnO4 is prepared from a set of standard solutions by plotting
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spreadsheets [PDF]
Table 1: Data for the standard curve of KMnO4
Absorbance Concentration (M)
0.372
6.00 x 10-4
0.298
0.223
0.149
0.0744
After plotting the standard curve, enter its slope below (not the equation of the line). Report your
answer to 3 significant figures. If your answer ends in one or more zeros, use scientific notation.
Slope =
4.80 x 10-4
3.60 x 10-4
2.40 x 10-4
1.20 x 10-4
M-1
M
3. Suppose that an unknown sample is analyzed spectrophotometrically at the same wavelength that
was used for the standard curve and the absorbance was found to be 0.186. Use the standard curve
to find the concentration of the unknown. Hint:
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Table 1.0 of data showing calibration standards prepared by dilution and the absorbance
Concentration CuSO4 (M) Volume of 0.5M (ml) Volume of D/Water (ml) Absorbance
0.00
0.10
0.20
0.30
0.40
0.50
II.
0.00
1.00
2.00
3.00
4.00
5.00
5.00
4.00
3.00
2.00
1.00
0.00
1. Construct a graph of concentration against absorbance, clearly show a best fit line.
Find regression of your graph. Show how
0.000
0.406
0.638
0.854
1.202
1.276
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against concentration (M, x-axis) is determined to be
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In spectrophotometric analysis, the
relationship between the absorbance A and
the analyte's concentration C is:
A = ebC + Ablank
What is the molar extinction coefficient I
and its absolute uncertainty if A is 0.68 ±
0.06; Ablank is 0.06 ± 0.01; b is 1.00 cm;
and C is (0.45 ± 0.03)x10-5 mol/L?
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0.1237 (±0.0001) g of sodium carbonate (Na2CO3) required 22.46 (±0.02) cm3 of aqueous HCl for complete neutralisation. Determine the concentration of the HCl in mol dm–3 together with its uncertainty in mol dm–3 to an appropriate number of digits. You may assume the error in the molar mass of Na2CO3 is negligible.
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1.
Data & Results
4.0 mglmL
Concentration of stock solution (include units):
Table 1-Beer's Law Plot Data
V Volume of standard
solution dispensed (mL)
M, Diluted concentration
(include units)
Sample
Absorbance
A
2.00 mL
0.084
4.00 mL
0.173
l6.00 mL
0.259
8.00 mL
0.340
E
10.00 mL
0.418
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whats the diluted concentration and equation of
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AP Questions // Questions 10 - 11) A student creates four solutions with varying
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[FESCN]
Absorbance
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0.076
1.6 x 10-4 M
0.112
2.2 x 10-4 M
0.167
2.5 x 10-4 M
0.199
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below:
Standard soln #
1
2
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4
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36.00
48.00
60.00
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= 1
5
Absorbance vs. Concentration
y = 0.2755x
0.2-
0.1-
1.400
2.000
1.800
1.600
1.000
0.200
1.200
0.400
0.600
Concentration (M)
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Concentration = M
X
Sub
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0.7-
0.6-
0.5
0.4-
0.800
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Standard #1
Standard #2
Standard #3
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1.5 x 10 M
2.0 x 103 M
2.5 x 10 M
?
Absorbance
0.61
0.80
0.98
0.72
a) 1.6 x 10 M
b) 1.8 x 10° M
c) 2.1 x 103M
d) 2.2 x 10 M
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0.0002
0.774
0.0003
1.154
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1.527
0.0005
1.931
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Analysis Section 1
1. Open a spreadsheet program, like Excel or Desmos, and plot your data points, with Absorbance on
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3. Fill in your equation below.
Absorbance =
-Concentration +
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