POST LAB 3 CHM3120C
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Perla Bathani
CHM3120C Post lab 3
Mahmoud mohammed
Lab 3. Practice Titration, Potassium Hydrogen Phthalate (KHP)
Part 1: Preparation of 0.1 M carbonate-free NaOH solution, and drying KHP.
Part 2: Titration (Standardization of NaOH solution)
Trial 1
Trial 2
Trial 3
Mass of a weighing paper (or dish)
0.4140g
0.4132g
0.4125g
Mass of a weighing paper (or dish) and
dried
KHP
1.1210g
1.1143g
1.1860g
Mass of dried KHP
0.7070g
0.7021g
0.7061g
# of moles, KHP
0.0035 mol
0.0035 mol
0.0036 mol
Volume of NaOH (Initial buret reading)
0 ml
0 ml
0 ml
Volume of NaOH (Final buret reading)
34.80 ml
34.90 ml
34.92 ml
Volume of NaOH used
34.80 ml
34.90 ml
34.92 ml
Molarity of the NaOH solution
0.10057
0.10029
0.10023
% Error
NA
NA
NA
Average Molarity
of the NaOH solution and STD:_0.10036
±
__0.00018___________
Calculations:
Average=
0.10057+0.10029+0.10023
= 0.10036 mol
3
Standard deviation=
√
(
0.10057
−
0.10036
)
2
+
(
0.10029
−
0.0036
)
2
+
(
0.10023
−
0.10036
)
2
÷
√
3
−
1
=0.00018 ml
Post lab questions:
1-
What is the correct way to handle a burette and an Erlenmeyer flask during a
titration?
For accurate and secure titration procedures, it's essential to handle a burette and an
Erlenmeyer flask properly. Before filling the burette, first rinse it with the titrant solution
to remove any air bubbles. Take careful note of the beginning volume. To ensure
thorough mixing, hold the burette vertically with one hand on the stopcock and the other
hand swirling the flask. Slow down the titrant flow as you get closer to the desired
endpoint, then add it dropwise while whirling till the endpoint is reached. Take close
note of the ultimate volume. The Erlenmeyer flask should be placed on a stable surface,
any necessary reactants added, and placed beneath the burette. If you overshoot the
endpoint, keep the flask steady, stir gently to combine, and refrain from refilling the
contents. Clean the flask for future use and properly dispose of waste solutions after the
titration is finished. Always follow the precise procedure instructions and use the proper
safety equipment when handling chemicals. These methods are necessary for obtaining
accurate and secure titration results.
2-Provide at least 2 different examples of desiccant material and at least 2 different
styles of desiccator and explain how they function differently.
Desiccant materials:
1-
Silica gel is a type of desiccant that is frequently used. It is made up of tiny, porous silica
beads with a strong attraction to water molecules. By trapping water vapor inside of its
porous structure, silica gel absorbs moisture and effectively lowers the humidity in the
desiccator.
2-An additional desiccant substance is calcium chloride. It is a salt that rapidly absorbs
moisture from the air because it is very hygroscopic. When calcium chloride is exposed to
the air inside a desiccator, it dissolves in the water vapor that is taken in and creates a
concentrated brine solution that settles to the bottom of the desiccator.
Styles of Desiccators:
1-
Vacuum desiccator: Made to create a low-pressure or vacuum atmosphere inside the
desiccator. It often features a vacuum valve and thick walls that are airtight. When a
vacuum pump is connected and turned on, air from the desiccator is evacuated, reducing
pressure. As a result, the boiling point of water is lowered, which causes stored moisture
to evaporatively dry up inside-placed materials more quickly.
2-
Gas pure desiccator: It employs a steady stream of dry, inert gas to push moist air out of
the desiccator rather than producing a vacuum. Through an entrance and outlet, the gas
flow is controlled. The desiccator maintains a low-humidity environment by removing
moisture-laden air when the dry gas passes past it. Applications where maintaining an
inert environment is crucial are suited for gas purge desiccators.
3-
Why is water boiled prior to the preparation of NaOH standard solution? Explain
briefly.
There are two crucial reasons to boil water before creating a sodium hydroxide standard
solution. First, it assists in purifying the solution by removing dissolved gases and
contaminants from the water. Second, boiling water raises its temperature, which also
raises NaOH's solubility in the liquid. Hot water makes it simpler to dissolve more
sodium hydroxide in the solution, producing a more concentrated standard solution.
Sodium hydroxide is more soluble in hot water than in cold water. This is crucial when
precise measurements are necessary for experiments or analytical applications that call
for concentration precision.
The NaOH standard solution can be prepared with the
necessary concentration and purity thanks to boiling water.
4-
What is standardization in acid-base chemistry? What constitutes a standard in
analytical chemistry? Give types and examples
.
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By titrating a solution against a previously established standard solution of a different
substance, standardization in acid-base chemistry refers to the process of exactly
determining the concentration of a solution, frequently an acid or a base. This standard
solution, which is often a main standard with known purity, serves as a guide for
determining the correlation between the volume of the standard solution needed to
neutralize the analyte and its concentration. Standards are essential in analytical
chemistry because they serve as benchmarks for calibrating equipment and confirming
measurement accuracy. These standards can come in a variety of shapes, each fulfilling a
particular function in laboratory analysis and quality control, including primary
standards, secondary standards, certified reference materials, working standards, and
internal standards.
Standardization is a cornerstone of analytical chemistry in a variety of
businesses because it ensures the dependability and accuracy of analytical
measurements.
5-
In the following graph depicting a titration curve for weak acid vs strong base
(titrant), explain the chemistry occurring (in regard to chemicals and their states,
equilibria) at four points a, b, c, and d indicated.
At point a: Initial Solution
You begin with the weak acid CH3COOH. Most of its molecules are CH3COOH.
Some CH3COOH molecules have changed into H+ ions and CH3COO- ions, while the
majority are still CH3COOH molecules.
At point b:
Near the Equivalence Point
You get closer to the equivalence point as you keep adding the strong base (NaOH).
More CH3COO- ions and water (H2O) have been produced as a result of some CH3COOH
molecules reacting with NaOH. However, not all CH3COOH has yet responded.
At point c: Point of Equivalence
You've now added enough NaOH to completely react with all the CH3COOH.
All the CH3COOH has been converted to CH3COO- ions, and the water-based solution is
sodium acetate, a salt.
At point d: After the Equivalence Point
As you keep adding NaOH, the solution becomes more fundamental. The solution still
contains extra OH- ions from the NaOH. As you add more NaOH, the solution becomes
more basic.
Related Documents
Related Questions
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K2CO3 (aq)+ CaCl2 (aq)→ CaCO3 (s) + 2KCl (aq)
Data Sheet
Table 1: Data and Observations
Material
Mass
CaCl2
2.0g
K2CO3
2.5g
Filter Paper
1.6g
Watch Glass
35.8g
Filter Paper + Watch Glass + Precipitate
38.9
Precipitate
1.5g
Table 2: Mass of CaCl2 after 24 Hours
Initial Observations
24 hour Observation
Weigh Boat
Mass of Weigh Boat 0.5g
Mass of Weigh Boat
0.5g
CaCl2
2.0g
Mass of CaCl2
2.4g
Mass of CaCl2
Calculate the theoretical yield of the solid precipitate. Then use that to calculate the percent yield of the solid precipitate.
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Module 8: H X
7087483#/7087483/16/2
%
General Chemistry 4th Edition
McQuarrie Rock Gallogly
Question 25 of 35 - Module 7 Ho X
[13] =
x10
TOOLS
Topic: Week 4 Discussion
Resources
C Give Up?
The amount of I5 (aq) in a solution can be determined by titration with a solution containing a known concentration of
S₂O3(aq) (thiosulfate ion). The determination is based on the net ionic equation
2S₂O3(aq) + 13(aq) →SO (aq) +31-(aq)
Given that it requires 41.0 mL of 0.450 M Na₂S₂O3(aq) to titrate a 20.0 mL sample of I3 (aq), calculate the molarity of 15 (aq) in
the solution.
Hint
University Science Books
presented by Macmillan Learning
M
Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry
C
C
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Name:
Date:
Section:
Data Report Sheet: Analysis of an Unknown Chloride
Unknown #
-2
Molarity of Standard Ag(NO), 5.2167x10 M
Trial I
Trial II
Trial III
Mass of Unknown
0.237
o. 232 g
g
Initial Burette
Reading
0.00
mL
7.90
mL
mL
Final Burette
Reading
31.00 mL
42.00 mL
mL
Vol. Ag(NO3)
Added
31.00 mL
34.10 mL
mL
Moles Ag(NO,)
1.617177y10 mol.
1,7789 v10 mol.
Moles CI
1.617177x103mdl.
Mass Cl
0.05741 8
0g
24.22 %
27.22%
Cl in Unknown
Average % Cl in unknown 25.720%
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Pls do fast and i will rate instantly for sure
Solution must be in typed form
A 25.0 mL volume of 0.0106 M KIO3 is pipetted into a 250-mL Erlenmeyer flask. The solution is titrated to the stoichiometric point with 16.25 mL of a sodium thiosulfate solution. What is the molar concentration of the sodium thiosulfate solution?
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Could you please solve the synthesized aspirin?
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Calculate Trial I, Trial II, Trial III Vol.Ag(NO3)Added.
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Based on this student data, calculate the average molarity of the NaOH solution. Standard: KHP =
potassium hydrogen phthalate, MM 204.4 g/mol
Student Data Trial 1
E KHP
mL initial: NaOH
mL final: NaOH
2.02
0.57
19.25
Trial 2
2.05
19.25
39.80
Trial 3
1.99
1.65
20.75
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Foreattt part of iTIS qtestfoni; tonsider FOHOWIHg Btetat:
You need to make a stock solution of Ca( C2H3O2 )2 with a concentration of
6.50 M. You have a 850.0 mL volumetric flask available to make this stock solution
in.
You are then tasked with using this stock solution to prepare a sample for use in an
experiment. The experimental sample should have a final volume of 15.0 mL and a
concentration of 0.350 M Ca(C2H3O2)2.
a) What is the molar mass of Ca(C2H3O2)2?
b) How many moles of the solute would be needed to create the stock solution using
the volumetric flask available?
c) How many grams of the solute should be added to the volumetric flask to create
the stock solution?
d) What volume, in mL, of the stock solution should be used to prepare the
experimental solution through dilution?
US
目
M
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3:59 PM Wed Mar 15
...
ap here or pull up for additional resources
Question 74 of 75
A 25.0 mL solution of HNO3 is
neutralized with 16.5 mL of 0.250 M
Ba(OH)2. What is the concentration of
the original HNO3 solution?
1
4
7
+/-
1
M
2 3
5
6
8
9
O
LTE 32%
Submit
XC
с
x 100
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1- The mercury present in a sample with a
mass equal to 0.8142 g was precipitated
with an excess of paraperiodic acid
(H5I06) according to the reaction below:
5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10H*
The precipitate was filtered, washed free of
precipitating agent, dried and weighed to
give 0.4114 g. Calculate the % of Hg and of
Hg2Cl2 in the sample.
Data:
Hg = 200.59
H = 1.008
Cl = 35.45
| = 126.90
%3D
O = 16.00
%3D
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II
5:44 PM Fri Oct 8
AA
www-awn.aleks.com
G periodic table -.
Favorites - YouT...
TV fuboTV - Watch...
ALEKS - Caliyah...
G kno3 acid or ba...
G linear program...
G write formulas f...
C Solu
O CHEMICAL REACTIONS
Predicting precipitation
Caliyah -
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical
formula in the last column.
Does a
precipitate form
when A and B
empirical
formula of
solution A
solution B
precipitate
are mixed?
potassium hydroxide
iron(III) nitrate
O yes
ou
iron(II) nitrate
sodium sulfide
ou O sək O
sodium acetate
ammonium nitrate
ou O sək O
Check
Explanation
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Standardization of NaOH
Trial 1
Trial 2
Trial 3
Trial 4
Trial 5
D. 785
O.l690g
0. 8239
Mass of KHP
Final buret
16.30mL: 14.05ML 17.10ML
reading
Initial buret
0,00mL 0.0vmL
O.comL
reading
Volume of NaOH
Calculate the molarity of the NaOH for each trial:
Trial 1
Trial 2
Trial 3
Trial 4
Trial 5
Calculated
Molarity
Average Molarity
M
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Do you know how to solve #2????
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Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.
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E Read
[References]
Use the References to access important values if needed for this question.
In the laboratory, a student dilutes 26.6 mL of a 11.7 M nitric acid solution to a total volume of 200.0 mL. What is the concentration of the diluted
solution?
Concentration =
M
Submit Answer
Try Another Version
1 item attempt remaining
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Name:
Date:
Section:
Data Report Sheet: Analysis of an Unknown Chloride
Unknown #
-2
Molarity of Standard Ag(NO), 52167/10 M
Trial I
Trial II
Trial III
Mass of Unknown
0.237
o. 232 g
Initial Burette
Reading
7.90 mL
0.00
mL
mL
Final Burette
Reading
31.00 mL
42.00 mL
mL
Vol. Ag(NO,)
Added
mL
mL
mL
Moles Ag(NO;)
Moles Cl
Mass CI
% Cl in Unknown
Average % CF in unknown
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6. Silver bromide can be precipitated through the following reaction. What mass of
precipitate can be produced starting with 34.3 g of NaBr?
NaBr + AGN03 NaNO3 + AgBr
7. How many moles of sodium bromide could be produced from 25.0 g of liquid
Bromine?
Bromine + Sodium iodide Sodium bromide + lodine
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16
You need to make an aqueous solution of 0.237 M cobalt(II) fluoride for an experiment in lab, using a 250 mL volumetric flask. How much solid cobalt(II)
fluoride should you add?
grams
Submit Answer
Review Topics]
[References]
Use the References to access important values if needed for this question.
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Related Questions
- Please helparrow_forwardK2CO3 (aq)+ CaCl2 (aq)→ CaCO3 (s) + 2KCl (aq) Data Sheet Table 1: Data and Observations Material Mass CaCl2 2.0g K2CO3 2.5g Filter Paper 1.6g Watch Glass 35.8g Filter Paper + Watch Glass + Precipitate 38.9 Precipitate 1.5g Table 2: Mass of CaCl2 after 24 Hours Initial Observations 24 hour Observation Weigh Boat Mass of Weigh Boat 0.5g Mass of Weigh Boat 0.5g CaCl2 2.0g Mass of CaCl2 2.4g Mass of CaCl2 Calculate the theoretical yield of the solid precipitate. Then use that to calculate the percent yield of the solid precipitate.arrow_forwardModule 8: H X 7087483#/7087483/16/2 % General Chemistry 4th Edition McQuarrie Rock Gallogly Question 25 of 35 - Module 7 Ho X [13] = x10 TOOLS Topic: Week 4 Discussion Resources C Give Up? The amount of I5 (aq) in a solution can be determined by titration with a solution containing a known concentration of S₂O3(aq) (thiosulfate ion). The determination is based on the net ionic equation 2S₂O3(aq) + 13(aq) →SO (aq) +31-(aq) Given that it requires 41.0 mL of 0.450 M Na₂S₂O3(aq) to titrate a 20.0 mL sample of I3 (aq), calculate the molarity of 15 (aq) in the solution. Hint University Science Books presented by Macmillan Learning M Question Source: McQuarrie, Rock, And Gallogly 4e-General Chemistry C Carrow_forward
- Name: Date: Section: Data Report Sheet: Analysis of an Unknown Chloride Unknown # -2 Molarity of Standard Ag(NO), 5.2167x10 M Trial I Trial II Trial III Mass of Unknown 0.237 o. 232 g g Initial Burette Reading 0.00 mL 7.90 mL mL Final Burette Reading 31.00 mL 42.00 mL mL Vol. Ag(NO3) Added 31.00 mL 34.10 mL mL Moles Ag(NO,) 1.617177y10 mol. 1,7789 v10 mol. Moles CI 1.617177x103mdl. Mass Cl 0.05741 8 0g 24.22 % 27.22% Cl in Unknown Average % Cl in unknown 25.720%arrow_forwardPls do fast and i will rate instantly for sure Solution must be in typed form A 25.0 mL volume of 0.0106 M KIO3 is pipetted into a 250-mL Erlenmeyer flask. The solution is titrated to the stoichiometric point with 16.25 mL of a sodium thiosulfate solution. What is the molar concentration of the sodium thiosulfate solution?arrow_forwardCould you please solve the synthesized aspirin?arrow_forward
- Calculate Trial I, Trial II, Trial III Vol.Ag(NO3)Added.arrow_forwardBased on this student data, calculate the average molarity of the NaOH solution. Standard: KHP = potassium hydrogen phthalate, MM 204.4 g/mol Student Data Trial 1 E KHP mL initial: NaOH mL final: NaOH 2.02 0.57 19.25 Trial 2 2.05 19.25 39.80 Trial 3 1.99 1.65 20.75arrow_forwardForeattt part of iTIS qtestfoni; tonsider FOHOWIHg Btetat: You need to make a stock solution of Ca( C2H3O2 )2 with a concentration of 6.50 M. You have a 850.0 mL volumetric flask available to make this stock solution in. You are then tasked with using this stock solution to prepare a sample for use in an experiment. The experimental sample should have a final volume of 15.0 mL and a concentration of 0.350 M Ca(C2H3O2)2. a) What is the molar mass of Ca(C2H3O2)2? b) How many moles of the solute would be needed to create the stock solution using the volumetric flask available? c) How many grams of the solute should be added to the volumetric flask to create the stock solution? d) What volume, in mL, of the stock solution should be used to prepare the experimental solution through dilution? US 目 Marrow_forward
- 3:59 PM Wed Mar 15 ... ap here or pull up for additional resources Question 74 of 75 A 25.0 mL solution of HNO3 is neutralized with 16.5 mL of 0.250 M Ba(OH)2. What is the concentration of the original HNO3 solution? 1 4 7 +/- 1 M 2 3 5 6 8 9 O LTE 32% Submit XC с x 100arrow_forward1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2Cl2 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3Darrow_forwardII 5:44 PM Fri Oct 8 AA www-awn.aleks.com G periodic table -. Favorites - YouT... TV fuboTV - Watch... ALEKS - Caliyah... G kno3 acid or ba... G linear program... G write formulas f... C Solu O CHEMICAL REACTIONS Predicting precipitation Caliyah - Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column. Does a precipitate form when A and B empirical formula of solution A solution B precipitate are mixed? potassium hydroxide iron(III) nitrate O yes ou iron(II) nitrate sodium sulfide ou O sək O sodium acetate ammonium nitrate ou O sək O Check Explanation 22 COiaw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center IAarrow_forward
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