critical article review

The absorbance of sample A is higher than the absorbance of sample B.    Therefore, sample A has (circle the correct one)   more   /   less      dissolved solute than sample B. The absorbance is (circle the correct one)   directly    /    inversely      related to the transmittance of a sample.

medicinal chemistry

sp sp? sp3 sp3 109.5° 'H. H. H 109.5° 120° 180° Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining

Q4.2 Sensitivity If 13C data were collected at this field using a protein concentration of 500 µM what is the effective protein concentration that gives rise to the measured NMR signal? Enter your answer here

A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.11. Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.

"Better resolution" means... a) detected peaks are separated from each other as much as possible and are as narrow as possible b) something in HPLC, but nothing in GC c) detected peaks are separated from each other as little as possible and are as wide as possible d) detected peaks are separated from each other as little as possible and are as narrow as possible e) detected peaks are separated from each other as much as possible and are as wide as possible

Each peak in the spectrum below can be used to provide a measure of the mass of this protein, you can work out the charge associated with each peak, and measures can be averaged to find the overall mass. Use simultaneous equations to find the charge associated with each peak in the spectra below, which will allow you to calculate the average mass of each species. Include an estimate of the error associated with this measure.

How would a 95% Z-interval compare to a 95% T-interval?

24

chemical shifts?

A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.144. Assuming that the best fit linear line of the standard curve was y=0.04144x+0.01521 (μgmL), calculate the percent protein by mass in the original protein powder.

Intensity (a.u.) 4000 3352 cm¹ 3500 3000 UNKNOWN B 1710 cm¹ 2000 1668 cm¹ 2500 Wavenumber (cm¹¹) 1500 1101 cm 1000 500

A direct enzyme-linked immunosorbent assay (ELISA) test on a patient's sample is shown below. Development of a strong (dark) color reaction would indicate: 1 Antibody is adsorbed to well. 2 Patient sample is added; complementary antigen binds to antibody. 3 Enzyme-linked antibody specific 4 Enzyme's substrate () is added, for test antigen is added and binds and reaction produces a product that causes a visible color change (O). to antigen, forming sandwich. A low concentration of a specific antigen in the patient's sample O A high concentration of a specific enzyme in the patient's sample The patient's antibody is specific for the enzyme's substrate O A high concentration of a specific antigen in the patient's sample A high concentration of a specific antibody (against the test antigen) in the patient's sample

True or False.  1. The absorbance of a sample is equal to the negative logarithm of the transmittance. 2. Winkler method of dissolve oxygen determination is an example of iodometry. 3. A diazo compound is produced when nitrite is reacted with sulfanilamide in acidic solution. 4. Atomic Absorption Spectroscopy can be used to analyze the functional groups of organic substances. 5. A diode array spectrometer use an absorption or interference filters for wavelength selection and a photoelectric device for measuring radiant power. 6. The oxidation state for the manganese in the brown solid which precipitate in Winkler method is +3 7. In Winkler method, the iodine produced is oxidized during sodium thiosulfate titration to iodide ion. 8. When the pH of the solution is adjusted to pH greater than 12, the EDTA reacts with magnesium ions only, because calcium precipitates as calcium hydroxide.

sp sp? sp3 120° sp3 109.5° 120° 180° Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining You labeled 4 of 5 targets incorrectly.

لا © Macmillan Learning H H-C-OH H₂/Pt HO-C-H $ % do LO 5 H₂C-OH OCT 11 <6 Y MacBook Pro Resources Q2Q Erase Select Draw Templates More /// C 0 H G c 2Q & * ( 7 8 9 0 ) U 0 P SUD

What structural features of Hydroxypropyl Acrylate (HPA) allow it to be detected by HPLC?

Copy o B S2 Perfo Student Indeper B Quizzes X Jal [Copy c B 7th Per t.k12.ga.us/d21/Ims/quizzing/user/attempt/quiz_start_frame_auto.d21?ou%=2591470&isprv3D&drc3D0&qi3D2428695&cfql-1&dnb- mochemistry Exam Angel Licona Rivera: Attempt 1 A 71.0 gram gold bar was heated in an experiment and 3,000 J of energy was transferred to the bar. What was the change in temperature for the bar in °C? Specific Heat: (CGold =0.126 J/g°C) Your Answer: Answer units

This question uses the same data as the previous question. The calibration curve is a graph of absorbance versus concentration. Absorbance is a dimensionless quantity. The slope of the calibration curve is m = 2.24 x 10^4 M^-1. Find the concentration detection limit.

The ppm concentration of Pb2+ in a blood sample were measured with Spectrophotometry. 5.00 mL of a blood sample were taken and this sample gave a signal of 0.301 a.u.. Another 5.00 mL of a blood sample were mixed with 0.50 mL og 1.75 ppm Pb2+. Then, this mixture was diluted to 25.00 mL and this diluted mixture gave a signal of 0.406 a.u.. What is the ppm concentration of a blood sample?

ica O CHEM-3A-81091-2... ead W ical Part A PCl5 (g) PC13 (1) + Cl2(g) Use A for [PC15], B for [PC13], C for [Cl2]. ΜΕ ΑΣΦ Keq AC1.8 Submit Previous Answers Request Answer × Incorrect; Try Again; 3 attempts remaining Part B 2KNO3(s) = 2KNO2 (s) + O2(g) Use A for [KNO3], B for [KNO2], C for [02]. Keq = ΜΕ ΑΣΦ Submit Part C Request Answer Pollen tomorrow ? ?

Which window size gives you a better signal-to-noise ratio? 7-residue window 15-residue window Under what circumstances would it be important to use a narrower window? Smaller range windows alter the sensitivity of the analysis, increasing the signal-to-noise ratio. Narrow windows permit identification of membrane-spanning regions at either end of the protein. Narrow windows allow hydropathy analysis of very small peptides that have less than 10 amino acid residue Smaller window ranges identify hydrophilic regions of the protein that are likely surface-exposed.

5. Why might IR be a useful tool for the analysis of food products in the fight against EMA?What impact would damaged plates have on your spectra? Be specific and justify your answer in a scientifically relevant manner.

Each peak in the spectrum below can be used to provide a measure of the mass of this protein, you can work out the charge associated with each peak, and measures can be averaged to find the overall mass. Use simultaneous equations to find the charge associated with each peak in the spectra below, which will allow you to calculate the average mass of each species. Include an estimate of the error associated with this measure

Name of Experiment: Fluorescence Spectroscopy Q1: Purpose of experiment Q2: Introduction

Which matches the data?

A.) Which parameter between "solvent polarity function" and dielectric constant show better correlation with the peak positions? B.) When a chromophore binds to proteins, the binding site is generally more hydrophobic than the solution. Then, what kind of shift do you expect to observe in the absorption peak position compared to the peak observed when the chromophore is free in solution?

analyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio)   1 4.47 69.58 How to get the concentration of the mixture in this case?

Magnetic resonance contrast agent relaxivity is defined as the proportionality constant relating the relaxation time induced by a contrast agent with the concentration of that contrast agent. * True O False

3. If you wished to study the molecule below by measuring absorbance, what wavelength should you set your spectrophotometer to? 1.6 Absorbance 1.4 1.2 1.0 0.8 0.6 0.4- 0.2- ME 0.0 300 400 600 Wavelength (nm) 500 Solutions and Mol....pdf 2 700 20221027_141317.jpg 800

FOLLOW UP QUESTION:   Hello! Thank you for your urgent answer.    Please answer the LEARNING TASK 4!   Please review and verify also your previous answers if either it's right or wrong.    Please take note to not handwritten your answer, pure typewritten only. Thank you!

What functional groups might be present in this molecule? (Image attached)

In an experiment to determine the riboflavin by fluorescence spectrometry, a series of riboflavin standards was analyzed and gave a calibration with a slope of 1000 ppm-1 and a y intercept of 25. If a sample gave a fluorescence reading of 750, what is the riboflavin concentration (in ppm) of the sample?   A. 0.725   B. 0.775   C. 0.0750   D. 7.50