PiQ Final Exam
pdf
School
University of Houston *
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Course
1332
Subject
Chemistry
Date
Apr 3, 2024
Type
Pages
17
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Review Test Submission: Additional Practice Final Exam Remix (with feedback) Sp 2021
2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
Course Content Folders
Pace Incentive Quizzes (PiQ's)
Review Test Submission: Additional Practice Final Exam Remix (with feedback) Sp 2021
User
Course
2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
Test
Additional Practice Final Exam Remix (with feedback) Sp 2021
Started
5/2/21 11:30 PM
Submitted
5/3/21 12:22 AM
Status
Completed
Attempt
Score
23.66666 out of 35 points Time
Elapsed
52 minutes out of 1 hour and 43 minutes
Instructions
Results
Displayed
Submitted Answers, Correct Answers, Feedback
If an image doesn't appear, try reloading the question.
For multiple choice questions, select the best answer from those provided. Follow the rules of signiÑcant Ñgures in calculations; round to the
correct number of sig Ñgs at the end unless the question speciÑes otherwise. NOTE: in questions where a logarithmic value (pH, POH, pKa, log,
etc.) is calculated, express your answer with 2 decimal places. Some questions may ask you to put your answer in scientiÑc notation. This must be
done as E-notation. Thus, 1321 would be entered as 1.321E3; 0.00123 would be 1.23E-3. WARNING: You must enter answers with exponents by
using uppercase “E”
rather than lowercase “e”; for example, 1.23E-22 rather than 1.23e-22. Your numerically correct answers might be marked as
incorrect by Bb if you use lowercase “e”.
proton mass = 1.67262 x 10
-27
kg or 1.00728 amu, neutron mass = 1.67493 x 10
-27
kg or 1.00866 amu, 1 amu = 1.66056 x 10
-27
kg = 931.5 MeV/c
2
Question 1
Library
Writing Center
Launch Home
1 out of 1 points
Selected Answer:
Correct Answer:
Response Feedback:
Use VSEPR theory to predict the molecular geometry of
XeF
4
.
square planar
square planar
Practice Exam 2 1a
Practice Exam 2 1a
Question 2
Selected Answer:
[None Given]
Correct Answer:
6.82E2 ± 2%
Response
Feedback:
A 252.9 mL sample of an aqueous solution at 25°C contains 78.3 mg of an unknown nonelectrolyte compound. If the solution has an
osmotic pressure of 8.44 torr, what is the molar mass (in g/mol) of the unknown compound?
Enter your value with three signiÑcant Ñgures .
Recall that the equation for osmotic pressure looks very similar to the ideal gas equation.
Π
V=nRT
. WIth
the given
information you
can Ñrst solve for n to obtain the moles of the compound. Then since you know both the mass and the moles of the compound
you can calculate the molar mass.
Question 3
Selected Answer:
Correct Answer:
Response
Feedback:
Which one of the following substances would be the
least soluble in cyclohexane, C
6
H
12
?
K
3
PO
4
K
3
PO
4
"Like prefers like. "
Since
cyclohexane, C
6
H
12
, is a nonpolar molecule, substances that are very polar will not dissolve. An ionic
substance is extremely polar due to the charges associated with its cations and anions.
Question 4
Experimental
Initial A
Initial B
Initial rate
Trial
(M)
(M)
(M s
-1
)
1
0.15
0.30
0.000701
2
0.30
0.30
0.000701
3
0.15
0.15
0.000175
4
0.45
0.45
0.001578
Suppose you have measured the kinetics of the reaction,
2 A + B
C + 2 D at room temperature using the method of initial rates.
A table summarizing the results of four diÖerent experimental trials is shown below:
First determine the orders of
[A] and [B] in the rate law.
Then based on these data and your rate law, what is the value of the rate constant k (in units of
M
-1
s
-1
).
{Enter your value with three signiÑcant Ñgures.}
0 out of 1 points
1 out of 1 points
1 out of 1 points
Selected Answer:
0.00779
Correct Answer:
0.007794349
Answer range +/- 0.002 (0.005794349 - 0.009794349)
Response Feedback:
The rate law can be found to be
rate = k [B]
2
,
the known values in a trial can be substituted, and the value of k can be calculated.
Question 5
SpeciÑed Answer for: a
half
SpeciÑed Answer for: b
zero
SpeciÑed Answer for: c
second
Correct Answers for: a
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
half
Exact Match
square root
Correct Answers for: b
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
zero
Exact Match
zeroth
Correct Answers for: c
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
zero
Exact Match
zeroth
Response Feedback:
Given a mechanism consisting of the following two elementary steps: A (g) 2 B (g) fast equilibrium B (g) 2 C(g) slow step write the rate law of the rate determining step, and then use the equilibrium condition to eliminate any intermediates. Give the orders of the following substances which appear in the overall reaction: {A} is [a]
order. {B} is [b]
order. {C} is [c]
order.
For example, zero, half, Ñrst, second, third, etc.
(If it is negative, you would write, negative Ñrst, negative second, etc)
1. Write rate law of slow step.
2. Write equilibrium expression and solve for intermediate (in this case B).
3. Substitute into rate law to remove B from Ñnal rate law.
4. Write orders of each substance.
Question 6
Experimental
Initial A
Initial B
Initial rate
Trial
(M)
(M)
(M s
-1
)
1
0.15
0.30
0.000857
2
0.30
0.30
0.001714
3
0.15
0.15
0.000428
4
0.45
0.45
0.003856
Suppose you have measured the kinetics of the reaction,
2 A + B
C + 2 D at room temperature using the method of initial rates.
A table summarizing the results of four diÖerent experimental trials is shown below:
First determine the orders of
[A] and [B] in the rate law.
0.66666 out of 1 points
1 out of 1 points
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Selected Answer:
0.0190
Correct Answer:
0.019039615
Answer range +/- 0.002 (0.017039615 - 0.021039615)
Response Feedback:
Then based on these data and your rate law, what is the value of the rate constant k (in units of
M
-1
s
-1
).
{Enter your value with three signiÑcant Ñgures.}
The rate law can be found to be
rate = k [A] [B],
the known values in a trial can be substituted, and the value of k can be calculated.
Question 7
Selected Answer:
-7.80E2
Correct Answer:
7.80E2 ± 4
Response
Feedback:
The rate constant for a reaction is measured as a function of time.
A plot is created by graphing ln(k) on the y-axis and 1/T on the x-axis, and a best Ñt line wit
R= 8.314 J/(K mol)
Enter your value with three signiÑcant Ñgures.
(with R = 8.314 J/(K mol), E in J. Convert the Ñnal answer to kJ/mol.
For additional help see:
https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical
Question 8
The reaction energy diagram below represents a two step reaction mechanism.
0 out of 1 points
1 out of 1 points
SpeciÑed Answer for: z
C
SpeciÑed Answer for: x
D
Correct Answers for: z
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
C
Correct Answers for: x
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
D
Response
Feedback:
To determine the activation energy of the second step in the reaction , the energy of species [z]
would be subtracted from the energy of species
[x]
.
Enter the letter that represents the appropriate chemical species.
The diÖerence D-C in this diagram represents the activation energy of the second step of the reaction.
For further information see:
https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chem
Question 9
Selected Answer:
1.71E-27
Correct Answer:
1.710000000000000000000000000E27 ± 2%
Response Feedback:
At a given temperature, the K
eq
for the equilibrium below is 4.14 × 10
13
. 2NO (g) + O
2
(g) 2NO
2
(g) What is the value of K
eq
at this temperature for the following reaction? 4NO (g) + 2O
2
(g) 4NO
2
(g) If you multiply an equation by a number, you raise the equilibrium constant the the power of that number.
Question 10
Selected Answer:
6.42E-7
Correct Answer:
6.42E-7 ± 2%
Response Feedback:
The reaction below has a K
p
value of 4.2 x 10
-5
. What is the value of K
c
for this reaction at 797 K? 2 SO
3
(g) 2 SO
2
(g) + O
2
(g)
, with R = 0.0821 atm L / (mol K) and T in K.
Question 11
Selected Answer:
B. Correct Answer:
B. Response Feedback:
A 10.0-g sample of solid NH
4
Cl is heated in a 5.00-L container to 900°C. At equilibrium the pressure of NH
3
(
g
) is 1.52 atm.
NH
4
Cl(
s
) NH
3
(
g
) + HCl(
g
)
The equilibrium constant, K
p
, for the reaction is:
2.31.
2.31.
Notice the amount of solid does not enter the calculation since the equilibrium is heterogeous.
Question 12
0 out of 1 points
1 out of 1 points
1 out of 1 points
1 out of 1 points
Selected Answer:
E. Correct Answer:
E. Response
Feedback:
I.
Increasing the temperature
II.
Decreasing the temperature
III.
Increasing the volume
IV.
Decreasing the volume
V.
Removing some NH 3
VI.
Adding some NH 3
VII.
Removing some N 2
VIII.
Adding some N 2
Consider the following system at equilibrium: N
2
(
g
) + 3H
2
(
g
) 2NH
3
(
g
) with ∆H= -92.94 kJ.
Which of the following changes will shift the equilibrium to the right?
II, IV, V, VIII
II, IV, V, VIII
I. Because the reaction is exothermic, when heat is added by increasing the temperature the reaction shifts left.
II. Because the reaction is exothermic, when heat is removed by decreasing the temperature the reaction shifts right
.
III. Because there are more moles of reactants than products, increasing the volume favors the side with more moles of
gas, which in this
case shifts left.
IV. Because there are more moles of reactants than products, decreasing the volume favors the side with fewer moles of
gas, which in this case shifts right.
V. Removing a product (NH
3
) shifts the reaction right.
VI. Adding a product (NH
3
) shifts the reaction left.
VII. Removing a reactant (N
2
) shifts the reaction left.
VIII. Adding a reactant ( N
2
) shifts the reaction right.
Question 13
Selected Answer:
[None Given]
Correct Answer:
8.09 ± 0.02
Response Feedback:
At 25º C, what is the pH of a 0.111 M aqueous solution of potassium Òuoride (KF) given that the K
a
of hydroÒuoric acid (HF) is 7.24 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 9
Practice exam 2 9
Question 14
Use the following table of data in answering the question below the table:
Acid Name
Formula
pK
a
pK
b
Conjugate
Base
Hydrofluoric acid
HF
3.17
10.83
F
-
Nitrous acid
HNO
2
3.25
10.75
NO
2
-
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0 out of 1 points
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Selected Answer:
Correct Answer:
Response Feedback:
Hypochlorous acid
HOCl
7.54
6.46
OCl
-
Hypobromous acid
HOBr
8.62
5.38
OBr
-
Hydrocyanic acid
HCN
9.21
4.79
CN
-
Ammonium
NH
4
+
9.24
4.76
NH
3
The acid HN
3
has a pK
a
of 4.72. How many of the conjugate bases shown in the table are stronger bases than the base N
3
-
?
2
4
Practice exam 2.4
Practice exam 2.4
Question 15
Selected Answer:
[None Given]
Correct Answer:
12.28 ± 0.02
Response Feedback:
At 25º C , what is the pH of a solution prepared by dissolving 0.00653 mol of Ca(OH)
2
in water to give 678.2 mL of solution?
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 5
Practice exam 2 5
Question 16
Selected Answer:
Correct Answer:
Response Feedback:
Of the following, which is the weakest acid?
HIO
HIO
For oxyacids
, for a given central atom, the acidity increases with increasing number of oxygen atoms.
0 out of 1 points
1 out of 1 points
Question 17
Selected Answer:
[None Given]
Correct Answer:
4.07 ± 0.02
Response Feedback:
A 25.00 mL sample of 0.150 M monoprotic organic acid is titrated with aqueous sodium hydroxide. After 6.42 mL of 0.150 M NaOH is added,
what is the pH of the solution?
The K
a
of the acid is 2.97 x 10
-5
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice Exam 2 12
Practice Exam 2 12
Question 18
Selected Answer:
[None Given]
Correct Answer:
5.73 ± 0.02
Response Feedback:
The weak base methylamine, CH
3
NH
2
, is titrated with HI
. What is the pH at the equivalence point, if the concentration of
methylammonium iodide, CH
3
NH
3
I
, is known to be 0.152 M?
The K
b
of CH
3
NH
2
is 4.4 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 14
Practice exam 2 14
Question 19
Selected Answer:
[None Given]
Correct Answer:
10.98 ± 0.04
One liter of a buÖer is prepared with concentrations of 0.250 M C
2
H
5
NH
2
and 0.250 M C
2
H
5
NH
3
Cl. If 2.61 g of NaOH is then added, what is
the resulting pH?
Assume the solution volume does not change and that K
b
of C
2
H
5
NH
2
is 5.61 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.04).
0 out of 1 points
0 out of 1 points
0 out of 1 points
Response Feedback:
Practice exam 2 13
Practice exam 2 13
Question 20
Selected Answers:
Correct Answers:
The K
sp
of Al(OH)
3 at 25
o
C is 2.0 x 10
-33
. If a solution contains 1.0 x 10
-5
M Ca(OH)
2
and 1.0 x 10
-16
M in Al(NO
3
)
3
, what is the best
description of the resulting solution.
The solution is supersaturated and a precipitate is expected to form (Q>K
sp
).
The solution is supersaturated and a precipitate is expected to form (Q>K
sp
).
Question 21
Selected Answer:
1.53E-32
Correct Answer:
1.53E-32 ± 9%
Response Feedback:
At a given temperature, the solubility of Ca
3
(PO
4
)
2
is 1.7 x 10
-7
mol/L what is its K
sp
value?
Enter your answer in exponential format using a capital "E" (example 1.23E-4) and no units (value ± 9%).
Practice exam 2 16
Practice exam 2 16
Question 22
Selected Answer:
-105
Correct Answer:
-105 ± 1
Response Feedback:
At 25 °C, a reaction has value of
Δ
G° = -84.4 kJ at and Δ
H° = -48.4 kJ. What is the value of the change in Gibbs energy of the reaction (in kJ) at a
temperature of 193.7 °C ?
Enter your value as an integer (value ± 1).
1 out of 1 points
1 out of 1 points
1 out of 1 points
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pe3.5
pe3.5
Question 23
Selected Answer:
19
Correct Answer:
19 ± 1
Response Feedback:
Δ
G
f
º
( NO(g) ) = 87.
Δ
G
f
º
( NO
2
(g) ) = 49.
Δ
G
f
º
( HNO
3
(l) ) = -79.
Δ
G
f
º
( H
2
O(l) ) = -237.
Given the values of Δ
G
f
º
given below in kJ/mol , calculate the value of Δ
G
º
in kJ for the reaction:
3 NO
2
(g) + H
2
O(l) 2 HNO
3
(l) + NO(g)
Enter your value as a integer (value ± 1).
pe3.8
pe3.8
Question 24
Selected Answer:
212
Correct Answer:
212 ± 1
Response Feedback:
At what temperature (in K) will a reaction become spontaneous if
Δ
H° = +66.2 kJ and
Δ
S° = +313 J/K?
Enter value as a whole number (value ± 1).
1 out of 1 points
1 out of 1 points
pe3.4
pe3.4
Question 25
Selected Answer:
-88.2
Correct Answer:
-88.2 ± 0.5
Response Feedback:
Substance S (J/K*mol)
C
2
H
2
(g)
199.8
CO
(g)
197.5
CO
2
(g)
214.3
O
2
(g)
205.6
H
2
O
(l)
69.1
Use the table below of standard entropy (298.15K) to answer the question that follows.
The partial oxidation of acetylene yields carbon monoxide and water:
2C
2
H
2
(g) + 3O
2
(g)
4CO
(g)
+ 2H
2
O
(l).
The value of Δ
S° for this reaction is __________ J/K. (Enter in decimal formation with one decimal, value ± 0.5)
pe3.6
pe3.6
Question 26
Selected Answer:
Balance the following equation in basic solution using the lowest possible whole numbers.
[a]
ClO
3
-
(aq) + [b]
MnO
4
-
(aq) +
[c]
H
2
O(l)
[d]
ClO
4
-
(aq)
+ [e]
Mn
2+
(aq)
+ [f]
O
H
-
(aq)
FYI: on the exam multiple choice or Ñll in the blank style questions would be used rather than drop down menu.
Balance the following equation in basic solution using the lowest possible whole numbers.
1 out of 1 points
1 out of 1 points
Correct Answer:
Response Feedback:
5
ClO
3
-
(aq) + 2
MnO
4
-
(aq) +
3
H
2
O(l)
5
ClO
4
-
(aq)
+ 2
Mn
2+
(aq)
+ 6
O
H
-
(aq)
FYI: on the exam multiple choice or Ñll in the blank style questions would be used rather than drop down menu.
Balance the following equation in basic solution using the lowest possible whole numbers.
5
ClO
3
-
(aq) + 2
MnO
4
-
(aq) +
3
H
2
O(l)
5
ClO
4
-
(aq)
+ 2
Mn
2+
(aq)
+ 6
O
H
-
(aq)
FYI: on the exam multiple choice or Ñll in the blank style questions would be used rather than drop down menu.
pe3.12
pe3.12
Question 27
SpeciÑed Answer for: a
Cd
SpeciÑed Answer for: Eo
0.15
Correct Answers for: a
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
Cd
Exact Match
Cd(s)
Exact Match
Cadmium
Exact Match
Cd (s)
Correct Answers for: Eo
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
0.15
Exact Match
+0.15
Exact Match
.15
Exact Match
+.15
Response Feedback:
Consider a voltaic cell based on the half-cells:
Ni
2+
(aq) + 2 e
-
Ni(s) E° = -0.25 V
Cd
2+
(aq) + 2 e
-
Cd(s) E° = -0.40 V
The anode would be [a]
and the cell voltage under standard conditions would be [Eo]
V.
1 out of 1 points
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pe3.13
pe3.13
Question 28
Selected Answer:
Correct Answer:
Response Feedback:
A galvanic cell was constructed using the reaction below.
Fe(s) + 3 CuNO
3
(aq) Fe(NO
3
)
3
(aq) + 3 Cu(s)
What is the shorthand notation for a galvanic cell?
[is]
| [ii]
∣∣
[ci]
| [cs]
FYI: this style of drop down menu selection is not used on the exam. A multiple choice style would most likely be used.
A galvanic cell was constructed using the reaction below.
Fe(s) + 3 CuNO
3
(aq) Fe(NO
3
)
3
(aq) + 3 Cu(s)
What is the shorthand notation for a galvanic cell?
Fe(s)
| Fe3+(aq)
∣∣
Cu+(aq)
| Cu(s)
FYI: this style of drop down menu selection is not used on the exam. A multiple choice style would most likely be used.
A galvanic cell was constructed using the reaction below.
Fe(s) + 3 CuNO
3
(aq) Fe(NO
3
)
3
(aq) + 3 Cu(s)
What is the shorthand notation for a galvanic cell?
Fe(s)
| Fe3+(aq)
∣∣
Cu+(aq)
| Cu(s)
FYI: this style of drop down menu selection is not used on the exam. A multiple choice style would most likely be used.
pe3.3
pe3.3
Question 29
1 out of 1 points
1 out of 1 points
Selected Answer:
-1,059
Correct Answer:
-1,059 ± 2%
Response Feedback:
A voltaic cell (same as a galvanic cell) is created from a Cu/Cu
2+
half-cell (E
red
= +0.27 V) and an Al/Al
3+
half-cell (E
red
= -1.56 V). Calculate the value of ∆
G for this cell in kilojoules.
Enter your value as an integer (value ± 2%)
pe3.9
pe3.9
Question 30
Selected Answer:
0.00000173
Correct Answer:
0.0000018 ± 6%
Response Feedback:
The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn (s) + 2H
+
(aq) Zn
2+
(aq) + H
2
(g) With P
H2
= 1.0 atm and Zn
2+
concentration of 1.0 M, the cell potential is 0.42 V. The concentration of H
+
in the cathode compartment is ________
M.
Recall
and in this case there are two electrons transferred.
When you solve for concentration remember the inverse function of ln() is e
x
and the inverse function of log() is 10
x
.
Question 31
SpeciÑed Answer for: name
Mg-25
Correct Answers for: name
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
Mg-25
Case Sensitive
Response Feedback:
If sodium-25 decays by emitting a beta particle, the isotope formed would be [name]
.
Enter as the element symbol hyphen whole number, for example, He-4.
1 out of 1 points
1 out of 1 points
pe3.18
pe3.18
Question 32
Selected Answer:
5
Correct Answer:
5
Response Feedback:
How many neutrons are emitted when a californium-249 nucleus (Z=98) is bombarded with a nitrogen-16 nucleus to produce a
nucleus?
Enter your value as a whole number.
pe3.17
pe3.17
Question 33
SpeciÑed Answer for: name
Mg-25
Correct Answers for: name
Evaluation Method
Correct Answer
Case Sensitivity
Exact Match
Mg-25
Case Sensitive
Response Feedback:
If sodium-25 decays by emitting a beta particle, the isotope formed would be [name]
.
Enter as the element symbol hyphen whole number, for example, He-4.
1 out of 1 points
1 out of 1 points
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Thursday, May 6, 2021 3:39:20 PM CDT
pe3.18
pe3.18
Question 34
Selected Answer:
[None Given]
Correct Answer:
8.3 ± 0.1
Response Feedback:
210
Pb has a half-life of 22.3 years and decays to produce
206
Hg. If you start with 10.0 g of
210
Pb, how many
grams of
206
Hg
will you have after 59.2 years?
Enter your value in decimal format with one decimal, (value ± 0.1).
pe3.16
pe3.16
Question 35
Selected Answer:
8.38
Correct Answer:
8.16 ± 0.01
Response
Feedback:
If the mass of one neutron is 1.00866 amu, the mass of one proton is 1.00728 amu, and the mass of
124
Cs nucleus is 123.912258 amu, calculate
the binding energy for the
124
Cs nucleus (MeV/nucleon).
1 amu = 931.5 MeV/c
2
Enter your answer in decimal format with two decimal placed, (value ± 0.01).
By Ñnding the diÖerence in mass between the isotope, and the mass of the corresponding protons (55) and neutrons (124-55), the
mass deÑcite can be found. The mass deÑcit can then be converted to energy in Mev using the equivalence, 931.5 MeV = 1 amu.
This gives the binding energy in MeV. Finally, the binding energy is divided by the number of nucleons (i.e. protons + neutrons), to
determine the binding energy per nucleon. (The binding energy is the positive value which is why the sign change is needed).
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Write the corresponding letters to the following descriptions. Each proposal can be associated with 0 or
1 match and each letter is not necessarily associated with a proposal.
a. [Ar] 4s?
b. 1s 2s2p63s23p3
c. 1s2s2p2
d. [Ne] 3s23ps
e. [Ar] 4s23d10
f. 1s22s!
g. None of those answers
1. I am a halogen
2. I am a transition metal
3. I am alkaline
4. I have exactly 2 single electrons
5. I am the smallest of the atoms presented here
6. I have exactly 3 valence electrons
7.I am the most paramagnetic of the atoms presented here
8. I am the copper
9.I am isoelectronic with Ti2+
IF
cessibility: Good to go
IA
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S, Amaya K - Outlo x
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It takes 155 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of N2
gas to effuse at the same temperature and pressure. What is the molar mass of the unknown gas?
g/mol
...
115
MAR
1664
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Complete the balanced neutralization equation for the reaction below:
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How would each of the following change the rate the reaction shown here?
2NO (g) + 2H2 (g)
(8)
a. Adding some NO (g)
, N2(g)+2H,0(g)
(8)
b. Decreasing the temperature
C.
Removing some H2 (g)
d. Adding a catalyst
D Focus
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7. You can see an MSDS below. Please answer the following questions related to the MSDS.
a) What is the name of this chemical?
b) What should you do if someone drinks the chemical?
c) Would this chemical catch on fire if it was exposed to flames?
d) If this chemical gets in your eye what should you do?
e) What color is this chemical?
f) What should you do if someone spills a small amount of the chemical?
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chem 132 Exam 1 2022 • Saved -
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23. Which of the following compounds contain a hemiacetal functional group?
OCH3
OH
но.
OCH3
A
OCH3
В
OCH3
C
a. A and B b. B and C
c. B only
d. C only
24. Which of the following compounds contains an acetal functional group?
OCH3
-OCH3
-OH
OCH3
A
B
a. A and B
c. B and C
b. A and C
d. C only
ards
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Table 1. pH of water samples
Sample No.
Water Samples
pH
1
Tap water from household
6.59
2
Water from creek
7.35
3
Water from river
7.35
4
Unknown sample
7.00
Table 2. Absorbance of Samples
Table 3. Calibration Curve Data*
Sample No.
Absorbance
Absorbance
3-
Concentration of PO4
Ions, ppm
(1 pt each)
1
1.33
1.0
0.050
2
3.26
2.0
0.093
0.89
3.0
0.137
4
0.099
4.0
0.185
5.0
0.230
*Provided by the instructor
II. Graph
Determination of Phosphate Concentration
3-
1. Using Excel, plot the concentration of PO4* (x-axis) vs. absorbance (refer to Table 3) The olot
must show the equation of the best-fit (or trend) line of the graph. Attach the graph below
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O CHEMICAL REACTIONS
David
O 1/5
Using a chemical equation to find moles of product from moles ...
with
Ammonium phosphate ((NH4), PO4)
is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid (H, PO,)
liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.10 mol of ammonia. Be sure your answer has a unit symbol, if
necessary, and round it to the correct number of significant digits.
Explanation
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Be sure to answer all parts.A sample of natural gas contains 6.626 moles of methane (CH.), 1.335 moles
of ethane (C2H6), and 0.380 moles of propane (C3Hg). If the total pressure of the gases is 3.86 atm, what
are the partial pressures of the gases?
PCH, =
atm
atm
%3D
Pc,H3 =
atm
116
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Calculating the wavelength of a spectral line from an energy..
-21
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This energy diagram shows the allowed energy levels of an electron in a certain atom. (Note: the SI prefix 'zepto' means 10
any SI prefix in the ALEKS Data tab.)
1400 -
1200 -
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dlo
1000 -
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Ar
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Use this diagram to complete the table below.
What is the energy of the electron in the ground state?
What is the energy of the electron in the first excited
state?
O absorbed
If the electron makes the transition shown by the red
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Background
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C12H22O11 + O₂
CO₂ + H₂O
Mg(OH)2 + H₂SO4
MgSO4 + H₂O
NaOH + CuSO4 -Na2SO4 + Cu(OH)2
CH2 + Oz = H2O + CO2
Fe + 0₂ Fe₂O3
Mg3(PO4)2 + H₂ Mg + H3PO4
NH4NO3-N₂O + H₂O
Cl₂ + KBr KCI + Br₂
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CHEM 3428 Worksheet 3
Name
TA/Section
Score
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All of this work will be incorporated into your lab report. Show all work, hand write legibly, and
use complete sentences. Use correct units when applicable.
Rubric Scoring
For 3-point questions:
3 points - complete, correct without errors
2 points - on the right track, minimal omissions, or errors
1 point - attempt made, omissions and errors
0 points - no answer
1. (3 pts) Draw a scheme for the epoxidation with Oxone reaction. Include all reagents and
reaction conditions.
2. (3 pts) What is the theoretical yield of this reaction as described in the procedure section
of the module page in mmol and in g? Report the theoretical yield using proper format.
Show all your calculations.
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O SIMPLE REACTIONS
Identifying precipitation, combustion and acid-base reactions
Classify each chemical reaction:
type of reaction
(check all that apply)
reaction
O precipitation
O combustion
O combination
кон (аq) + нсIо, (аq) - ксіо, (аg) + н, о()
O single replacement
O double replacement
O acid-base
decomposition
O combination
O precipitation
O single replacement
O double replacement
O decomposition
O combustion
Feso, (aq) + PbCL, (aq) →
FeCl, (aq) + PbSO,(s)
O acid-base
O combination
O precipitation
2K (s) + Br, (1) → 2K Br(s)
O single replacement
O combustion
double replacement
O acid-base
O decomposition
O combination
O precipitation
Baco, (s)
Ba0(s) + Co, (g)
O single replacement
O combustion
O double replacement
O acid-base
decomposition
Explanation…
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Group-12 )436 9 10 11 12 13 14 15 16 17 10
Irerlod
The Perlodic Table of the Elements
Elements in the same group tend to have similar characteristics, but some things like tendency to gain or lose electrons can still vary
even within a group Which of the following is true regarding the elements in group 2?
O A Be, Beryllium is the largest and has the greatest tendency to gain electrons.
OB Be Beryllium and Ba, Barium will have the same tendancy to lose electrons
OC Ra, Radium is the smallest and will have the greatest tendency to lose electrons.
O D. Ba, Barium will have a greater tendency to lose electrons than Mg, Magnesium.
DELL
%23
E
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A
C
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AND 290) NISYNISOL
Aktiv Chemistry - Numeric Entry x
→ C
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A chemist has a block of gold metal (density is 19.3 g/mL). The block
weighs 3.10 g. What is the volume of the gold block in ml?
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Question 19 of 36
5
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2+
d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9)
Oke
O Ke
=
=
O Ke =
2+
[Mn²+ ][C1₂]
[H3O+] * [CI-1²
[Mn²+][H₂O][C1₂]
2+
[H³O+][CI¯]²[MnO₂2]
[Mn²+ ] [H₂O1] [C1₂]
2+
[H3O+] * [CI-1²[MnO₂]
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Table 1.0 of data showing calibration standards prepared by dilution and the absorbance
Concentration CuSO4 (M) Volume of 0.5M (ml) Volume of D/Water (ml) Absorbance
0.00
0.10
0.20
0.30
0.40
0.50
II.
0.00
1.00
2.00
3.00
4.00
5.00
5.00
4.00
3.00
2.00
1.00
0.00
1. Construct a graph of concentration against absorbance, clearly show a best fit line.
Find regression of your graph. Show how
0.000
0.406
0.638
0.854
1.202
1.276
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- View History Bookmarks People Tab Window Help S, Amaya K - Outlo x B Chapter 5- CHEM-1110-941- x Question 20 - Chapter 5- Con x education.com/ext/map/index.html?_con%3con&external_browser%3D0&launchUrl=https%253A%252F%252Flms Saved 3 attempts left Check my work Enter your answer in the provided box. It takes 155 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of N2 gas to effuse at the same temperature and pressure. What is the molar mass of the unknown gas? g/mol ... 115 MAR 1664 18 ottv Aarrow_forwardO Homework in Chem101 - due Su X My Questions | bartleby ( Periodic Table – Royal Society of how to take a screenshot on an + A learn.maricopa.edu/courses/1132256/modules/items/19018052 CHM151 17003 > Modules > Weeks 8 & 9 - Chapter 7 > Homework in Chem101 - due Sunday night CG 2020 FALL CRED Question 37 of 4 Submit Account Home Complete the balanced neutralization equation for the reaction below: Announcements Dashboa |Modules HCIO-(aq) + CSОН(ag) — rd Concourse Syllabus Courses Grades D2+ N3+ D4+ Cisco Webex Groups 1 2 3 4 7 8 9. Tutoring/Learning Center Calendar Os Do Inbox (s) (1) (g) (aq) History Cs H CI Help • Previous Next » Library 1:03 PM O Type here to search 10/18/2020 +arrow_forwardWhich one is it?arrow_forward
- Chapter 10 homework Word O Search File Home Insert Draw Design Layout Juliann References Mailings Review View Help Calibri (Body) 11 - A^ A Aa v A E-E v'Ę, EE ¿ T ACCDC AaBbCcDc AaBbCc AABBCCC AaB OF Paste B I U - ab x, x A- dv Ar ==== E- &v - 1 Normal 1 No Spac. Heading 1 Heading 2 Title in Clipboard Font Paragraph Styles Ec How would each of the following change the rate the reaction shown here? 2NO (g) + 2H2 (g) (8) a. Adding some NO (g) , N2(g)+2H,0(g) (8) b. Decreasing the temperature C. Removing some H2 (g) d. Adding a catalyst D Focus Page 1 of 4 403 words 71% P Type here to search 12 1> 1>arrow_forwardCould you please help me format this question, I've been stuck on it for some time now.arrow_forward7. You can see an MSDS below. Please answer the following questions related to the MSDS. a) What is the name of this chemical? b) What should you do if someone drinks the chemical? c) Would this chemical catch on fire if it was exposed to flames? d) If this chemical gets in your eye what should you do? e) What color is this chemical? f) What should you do if someone spills a small amount of the chemical?arrow_forward
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