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Review Test Submission: Additional Practice Exam 2 with feedback ( A Remix)
2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
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Review Test Submission: Additional Practice Exam 2 with feedback ( A Remix)
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2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
Test
Additional Practice Exam 2 with feedback ( A Remix)
Started
4/2/21 5:36 PM
Submitted
4/2/21 6:40 PM
Status
Completed
Attempt
Score
21 out of 22 points Time
Elapsed
1 hour, 3 minutes out of 1 hour and 23 minutes
Instructions
For multiple choice questions, select the best answer from those provided.
For Ñll-in the blank questions, spelling counts, and atomic symbols must start with capital
letters.
For numerical entry problems:
The default scoring method checks that your input value
agrees within plus or minus 2% of the expected value. Therefore unless otherwise
speciÑed, you should report at least three signiÑcant Ñgures and enter your value with no
units.
Some questions may ask you to enter your answer in scientiÑc notation.
This must be
done as exponential notation, using
a capital "E"
.
For example, 1921 would be entered
as 1.921
E
3; 0.00789 would be 7.89
E
-3.
Some questions may specify the number of decimal places to be used for an answer.
For
example, the value 6789.123 has three decimal places.
Some questions may specify that the log-base 10 of the calculated values should be
entered as the answer with at least two decimal places.
For example, a calculated value
of
0.00789 would be entered as
log(0.00789) = -2.103.
If an image doesn't appear, try reloading the question using the reload icon (i.e. circular arrow)
at the top of the Browser.
Please read and answer each question carefully following any formatting instructions
given:
Library
Writing Center
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Home
Results
Displayed
Submitted Answers, Correct Answers, Feedback
Question 1
Selected Answer:
Correct Answer:
Response
Feedback:
The molecular geometry of the XeF
4
molecule is ________, and this molecule is ________. square planar, nonpolar
square planar, nonpolar
(Hint: start by drawing the Lewis dot structure, use the electronegativity
difference to determine the bond polarity, and finally consider how the dipoles
(vectors) combine to determine the overall molecular polarity.)
Question 2
Selected Answer:
Correct Answer:
Response Feedback:
Consider the following reaction and its equilibrium constant: 4 CuO(s) + CH
4
(g) CO
2
(g) + 4 Cu(s) + 2 H
2
O(g) K
c
= 1.10 A reaction mixture contains 0.22 M CH
4
, 0.67 M CO
2
and 1.3 M H
2
O. Which of the following
statements is TRUE concerning this system?
The reaction will shift in the direction of reactants.
The reaction will shift in the direction of reactants.
IF
Q
> K
reverse direction
1 out of 1 points
1 out of 1 points
Q
= K
at equilibrium
Q
< K
forward direction
Question 3
Selected Answer:
2.51E0
Correct Answer:
2.51E0 ± 2%
Response
Feedback:
At a given temperature, the K
eq
for the equilibrium below is 0.399. SO
2
(g) + O
2
(g) SO
3
(g) What is the value of K
eq
at this temperature for the following reaction? SO
3
(g) SO
2
(g) + O
2
(g) If you multiply an equation by a number, you raise the equilibrium
constant to that power.
If you reverse a reaction, you take the reciprocal of the equilibrium
constant.
If you add two equations, you multiply their equilibrium constants.
Question 4
Selected Answer:
6.18E-2
Correct Answer:
6.18E-2 ± 2%
Response Feedback:
Given the following reaction at equilibrium, if K
p
= 2.45 at 210 °C, K
c
= ________. PCl
5
(g) PCl
3
(g) + Cl
2
(g)
, with R = 0.0821 atm L / (mol K) and T in K.
Question 5
Selected Answer:
3.73E-5
At a given temperature, the reaction,
H
2
(g) + I
2
(g)
2HI (g), has a value of K
eq
= 771.
If the hydrogen concentration is 0.00541 M
and the hydrogen iodide concentration is 0.01248
M, what is the molar concentration of the iodine at equilibrium? 1 out of 1 points
1 out of 1 points
1 out of 1 points
Correct Answer:
3.73E-5 ± 2%
Response
Feedback:
The equilibrium constant is equal to the products over the reactants raised to
the stoichiometric ccoeÔcients (leaving out pure liquids and solid). Once your
write the equilibrium equation, you then substitute in the given values and
solved for the unknown concentration.
Question 6
Selected Answer:
9.352E1
Correct Answer:
9.35E1 ± 2
Response
Feedback:
Iodine and bromine react as shown below:
I
2
(g) + Br
2
(g) 2IBr (g). If 0.531 mol of I
2
and 0.531 mol of Br
2
are placed into a sealed 1.00 L Òask, and at
equilibrium the Òask contains 0.88 mol of IBr, what is the
value of the equilibrium constant,
K
eq
? (Hint: you will needed to Ñgure out the amounts of each substance at equilibrium using
stoichiometry, before you can substitute into the equilibrium expression. An ICE table can
help you organize this type of data. )
First calculate the concentrations at equilibrium using stoichiometry. They
substitute the concentrations into the equilibrium expression to Ñnd the value
of K
eq
.
Question 7
Selected Answer:
Correct Answer:
Response
Feedback:
The equilibrium constant is given for two of the reactions below. Determine the value of the
missing equilibrium constant. A(g) + 2B(g) AB
2
(g) Kc = 59 AB
2
(g) + B(g) AB
3
(g) K
c
= ? A(g) + 3B(g) AB
3
(g) K
c
= 478
8.1
8.1
If you multiply an equation by a number, you raise the equilibrium
constant to that power.
If you reverse a reaction, you take the reciprocal of the equilibrium
constant.
If you add two equations, you multiply their equilibrium constants.
1 out of 1 points
1 out of 1 points
Question 8
Selected
Answer:
Correct
Answer:
Response
Feedback:
Consider the following reaction at equilibrium. What eÖect will adding some graphite have on
the system? CO
2
(g) + C(graphite) 2 CO(g)
No eÖect will be observed since C is not included in the equilibrium
expression.
No eÖect will be observed since C is not included in the equilibrium
expression.
Because the equilibrium is heterogeneous, the solid does not appear in the
equilibrium expression and therefore adding and subtracting graphite will not
shift the equilibrium.
Question 9
Selected Answer:
Correct Answer:
Response
Feedback:
An aqueous solution of ________ will produce an acidic solution.
NH
4
NO
3
NH
4
NO
3
Conjugate bases of strong acids are neutral (i.e. not bases).
(Based on the list of seven strong acids, this mean the ions HSO
4
-
, NO
3
-
, I
-
, Br
-
,
Cl
-
, ClO
3
-
, and ClO
4
-
can form neutral salts.
Group I and II cations form neutral salts, but since ammonium is the conjugate
base of a weak acid (ammonia) it forms an acidic salt.
Anions that are conjugate bases of weak acids form basic salts.
Question 10
Selected Answer:
Correct Answer:
Response
Feedback:
What is the conjugate acid of HCO
3
-
?
H
2
CO
3
H
2
CO
3
An acid donates a proton which is accepted by the lone pair of the
base.
Therefore,
the substance with the added proton is the
conjugate
acid.
1 out of 1 points
1 out of 1 points
1 out of 1 points
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Calculate the difference between AH and AU when 1.0 mol Sn (gray) of density 5.75 g cm3
changes to Sn (white) of density 7.31 g•cm3 at 10.0 bar. Molar mass of Sn = 118.71 g•mol-!.
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How would each of the following change the rate the reaction shown here?
2NO (g) + 2H2 (g)
(8)
a. Adding some NO (g)
, N2(g)+2H,0(g)
(8)
b. Decreasing the temperature
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d. Adding a catalyst
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Ammonium phosphate ((NH4), PO4)
is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid (H, PO,)
liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.10 mol of ammonia. Be sure your answer has a unit symbol, if
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Write the corresponding letters to the following descriptions. Each proposal can be associated with 0 or
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b. 1s 2s2p63s23p3
c. 1s2s2p2
d. [Ne] 3s23ps
e. [Ar] 4s23d10
f. 1s22s!
g. None of those answers
1. I am a halogen
2. I am a transition metal
3. I am alkaline
4. I have exactly 2 single electrons
5. I am the smallest of the atoms presented here
6. I have exactly 3 valence electrons
7.I am the most paramagnetic of the atoms presented here
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Use the References to access important values if needed for this question.
A sample of gas contains 0.1118 mol of H2(g) and 5.590×10² mol of O2(g) and occupies a volume of 8.55 L. The following reaction takes place:
2H2(g) + O2(g)–2H2O(g)
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In(VP)
353
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348
- o 06191
343
=0.00296
338
333=0.0300
323-0.0030u
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=0.00309
323
273=0.006
0.00366
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Using the balanced equation for the combustion of ethanol:
C2H60+302 -> 2CO2+3H20
a.How many grams of CO2 are formed from 0,50mol of ethanol?
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b.How many moles of H20 are formed from 24 g of ethanol?
c.How many grams of 02 are needed to react with 0.25 mol of ethanol? 24
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The real gases do not follow the ideal gas law of PV= nRT, where P is the pressure, V is the
volume, n is the amount of gas, R is the Universal gas constant, and T is the absolute
temperature.
(a)
Identify the variables in the ideal gas that are responsive for the deviation and draw
their respective diagrams.
(b)
Explain the reasons for deviation of the behaviour of the real gases from the ideal gas
law.
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6. Draw the arrow-pushing mechanism and propose the product(s). When appropriate, make
sure to indicate the appropriate stereo-/regio-chemistry of the product(s). Note that the
mechanism(s) by which the product(s) form in reactions A and B are shown in pink. For
reactions C, D, and E you need to deduce the mechanism by carefully analyzing your
reagents and conditions.
A.
Br
OH
E1 and SN1
B.
H₂O
SN1
Hint: A mixture of two allylic alcohols forms.
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Solving moles-to-moles limiting reactant problems
Nitrogen dioxide (NO2) gas and liquid water (H,O)
react to form aqueous nitric acid (HNO,) and nitrogen monoxide (NO)gas. Suppose you have 2.0 mol of
NO, and 5.0 mol of H,O in a reactor.
Calculate the largest amount of HNO, that could be produced. Round your answer to the nearest 0.1 mol.
| mol
Explanation
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C12H22O11 + O₂
CO₂ + H₂O
Mg(OH)2 + H₂SO4
MgSO4 + H₂O
NaOH + CuSO4 -Na2SO4 + Cu(OH)2
CH2 + Oz = H2O + CO2
Fe + 0₂ Fe₂O3
Mg3(PO4)2 + H₂ Mg + H3PO4
NH4NO3-N₂O + H₂O
Cl₂ + KBr KCI + Br₂
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Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water (H,0) and carbon dioxide (CO, chemically
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What mass of carbon dioxide is consumed by the reaction of 8,82 g of water?
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4. Determine and draw the structure corresponding to the spectral information provided
below. As you make this determination, complete the table below. Explain what clues you
used to determine the structure.
B
C10H12O
Signal
б
ABCDE
~7.8
~7.2
~2.7
~2.6
~1.2
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3
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E
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d
d
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O GASES
Calculating partial pressure in a gas mixture
Jacqueline
A 5.00 L tank at 7.37 °C is filled with 18.2 g of chlorine pentafluoride gas and 3.28 g of boron trifluoride gas. You can assume both gases behave as ideal gases
under these conditions.
Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Round each of your answers to 3 significant digits.
圖
mole fraction:
chlorine pentafluoride
partial pressure:
| atm
mole fraction:
boron trifluoride
partial pressure:
| atm
Total pressure in tank:
| atm
Explanation
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Calculating the wavelength of a spectral line from an energy..
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This energy diagram shows the allowed energy levels of an electron in a certain atom. (Note: the SI prefix 'zepto' means 10
any SI prefix in the ALEKS Data tab.)
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1000 -
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What is the energy of the electron in the ground state?
What is the energy of the electron in the first excited
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O absorbed
If the electron makes the transition shown by the red
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chem 132 Exam 1 2022 • Saved -
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23. Which of the following compounds contain a hemiacetal functional group?
OCH3
OH
но.
OCH3
A
OCH3
В
OCH3
C
a. A and B b. B and C
c. B only
d. C only
24. Which of the following compounds contains an acetal functional group?
OCH3
-OCH3
-OH
OCH3
A
B
a. A and B
c. B and C
b. A and C
d. C only
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CHEM 3428 Worksheet 3
Name
TA/Section
Score
/27
All of this work will be incorporated into your lab report. Show all work, hand write legibly, and
use complete sentences. Use correct units when applicable.
Rubric Scoring
For 3-point questions:
3 points - complete, correct without errors
2 points - on the right track, minimal omissions, or errors
1 point - attempt made, omissions and errors
0 points - no answer
1. (3 pts) Draw a scheme for the epoxidation with Oxone reaction. Include all reagents and
reaction conditions.
2. (3 pts) What is the theoretical yield of this reaction as described in the procedure section
of the module page in mmol and in g? Report the theoretical yield using proper format.
Show all your calculations.
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S, Amaya K - Outlo x
B Chapter 5- CHEM-1110-941- x
Question 20 - Chapter 5- Con x
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Enter your answer in the provided box.
It takes 155 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of N2
gas to effuse at the same temperature and pressure. What is the molar mass of the unknown gas?
g/mol
...
115
MAR
1664
18
ottv A
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my Lessons 18 & 19 Worksneet
☆由 @
TURN IN
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D0% -
BIUA
三===|= |=▼=-EE|X
Nomal text
Calibri
12
1.
2 I 3. I 4 I 5 I 6 7 8 I 9 10
Potassium,
Calcium,
Gallium,
Germanium
Bromine,
Krypton,
Kr
Arsenic,
Selenium,
Ca
Ga
Ge
As
Se
Br
Alchemy Lesson 18: Life on the Edge & Lesson 19: Noble Gas Envy (Valence & Core Electrons)Page 3 of 4
PART 2: Use your completed table to answer the questions below.
1. List three things that all the atoms of the elements in period 3 have in common.
2. Explain why the number of electrons in the third shell changes from 8 to 18 between the element calcium, Ca, and the element gallium, Ga.
. 3. Summarize at least three patterns you discovered during this lesson.
4. Predict the electron arrangement of tin, Sn. Draw a shell model of it.
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SPECTRA FOR HOMEWORK 11, CHE 230 002
This page is not to be submitted to Gradescope. Use these spectra as you answer questions on the Homework 11 document.
Spectra for Problem 1
100
%T
80
60
40
20
Relative Intensity
4000
100-
80
8
60-
40-
20-
0
20
2H 2H
3000
m/z
50.0
75.0
76.0
155.0
157.0
183.0
185.0
212.0
214.0
100.0
97.5
11.8
11.7
1686 cm
40 60 80
2000
rel, intensity
11.9
16.9
17.6
28.8
27.8
Wavenumber[cm-1]
100
120
m/z
1500
7.90 7.85 7.80 7.75 7.70 7.65 7.60 7.55
1588 cm²
20 20 ₂
مسلسل..............للمسلسل
ppm
140 160 180 200 220
2H
1000
3.12
3.00 2.95 2.90
3H
500 400
A. Propose a
molecular
formula
for this
compound
B. Propuse.
a structure
selected
1.25 1.20 1.15
201
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