PiQ Exam 2
pdf
keyboard_arrow_up
School
University of Houston *
*We aren’t endorsed by this school
Course
1332
Subject
Chemistry
Date
Apr 3, 2024
Type
Pages
13
Uploaded by CorporalCatPerson859
Review Test Submission: Additional Practice Exam 2 with feedback ( A Remix)
2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
Course Content Folders
...
Prior weeks' PiQs
Review Test Submission: Additional Practice Exam 2 with feedback ( A Remix)
User
Course
2021SP-22142-CHEM1332-Fundamentals of Chemistry 2
Test
Additional Practice Exam 2 with feedback ( A Remix)
Started
4/2/21 5:36 PM
Submitted
4/2/21 6:40 PM
Status
Completed
Attempt
Score
21 out of 22 points Time
Elapsed
1 hour, 3 minutes out of 1 hour and 23 minutes
Instructions
For multiple choice questions, select the best answer from those provided.
For Ñll-in the blank questions, spelling counts, and atomic symbols must start with capital
letters.
For numerical entry problems:
The default scoring method checks that your input value
agrees within plus or minus 2% of the expected value. Therefore unless otherwise
speciÑed, you should report at least three signiÑcant Ñgures and enter your value with no
units.
Some questions may ask you to enter your answer in scientiÑc notation.
This must be
done as exponential notation, using
a capital "E"
.
For example, 1921 would be entered
as 1.921
E
3; 0.00789 would be 7.89
E
-3.
Some questions may specify the number of decimal places to be used for an answer.
For
example, the value 6789.123 has three decimal places.
Some questions may specify that the log-base 10 of the calculated values should be
entered as the answer with at least two decimal places.
For example, a calculated value
of
0.00789 would be entered as
log(0.00789) = -2.103.
If an image doesn't appear, try reloading the question using the reload icon (i.e. circular arrow)
at the top of the Browser.
Please read and answer each question carefully following any formatting instructions
given:
Library
Writing Center
Launch lp
Home
Results
Displayed
Submitted Answers, Correct Answers, Feedback
Question 1
Selected Answer:
Correct Answer:
Response
Feedback:
The molecular geometry of the XeF
4
molecule is ________, and this molecule is ________. square planar, nonpolar
square planar, nonpolar
(Hint: start by drawing the Lewis dot structure, use the electronegativity
difference to determine the bond polarity, and finally consider how the dipoles
(vectors) combine to determine the overall molecular polarity.)
Question 2
Selected Answer:
Correct Answer:
Response Feedback:
Consider the following reaction and its equilibrium constant: 4 CuO(s) + CH
4
(g) CO
2
(g) + 4 Cu(s) + 2 H
2
O(g) K
c
= 1.10 A reaction mixture contains 0.22 M CH
4
, 0.67 M CO
2
and 1.3 M H
2
O. Which of the following
statements is TRUE concerning this system?
The reaction will shift in the direction of reactants.
The reaction will shift in the direction of reactants.
IF
Q
> K
reverse direction
1 out of 1 points
1 out of 1 points
Q
= K
at equilibrium
Q
< K
forward direction
Question 3
Selected Answer:
2.51E0
Correct Answer:
2.51E0 ± 2%
Response
Feedback:
At a given temperature, the K
eq
for the equilibrium below is 0.399. SO
2
(g) + O
2
(g) SO
3
(g) What is the value of K
eq
at this temperature for the following reaction? SO
3
(g) SO
2
(g) + O
2
(g) If you multiply an equation by a number, you raise the equilibrium
constant to that power.
If you reverse a reaction, you take the reciprocal of the equilibrium
constant.
If you add two equations, you multiply their equilibrium constants.
Question 4
Selected Answer:
6.18E-2
Correct Answer:
6.18E-2 ± 2%
Response Feedback:
Given the following reaction at equilibrium, if K
p
= 2.45 at 210 °C, K
c
= ________. PCl
5
(g) PCl
3
(g) + Cl
2
(g)
, with R = 0.0821 atm L / (mol K) and T in K.
Question 5
Selected Answer:
3.73E-5
At a given temperature, the reaction,
H
2
(g) + I
2
(g)
2HI (g), has a value of K
eq
= 771.
If the hydrogen concentration is 0.00541 M
and the hydrogen iodide concentration is 0.01248
M, what is the molar concentration of the iodine at equilibrium? 1 out of 1 points
1 out of 1 points
1 out of 1 points
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Correct Answer:
3.73E-5 ± 2%
Response
Feedback:
The equilibrium constant is equal to the products over the reactants raised to
the stoichiometric ccoeÔcients (leaving out pure liquids and solid). Once your
write the equilibrium equation, you then substitute in the given values and
solved for the unknown concentration.
Question 6
Selected Answer:
9.352E1
Correct Answer:
9.35E1 ± 2
Response
Feedback:
Iodine and bromine react as shown below:
I
2
(g) + Br
2
(g) 2IBr (g). If 0.531 mol of I
2
and 0.531 mol of Br
2
are placed into a sealed 1.00 L Òask, and at
equilibrium the Òask contains 0.88 mol of IBr, what is the
value of the equilibrium constant,
K
eq
? (Hint: you will needed to Ñgure out the amounts of each substance at equilibrium using
stoichiometry, before you can substitute into the equilibrium expression. An ICE table can
help you organize this type of data. )
First calculate the concentrations at equilibrium using stoichiometry. They
substitute the concentrations into the equilibrium expression to Ñnd the value
of K
eq
.
Question 7
Selected Answer:
Correct Answer:
Response
Feedback:
The equilibrium constant is given for two of the reactions below. Determine the value of the
missing equilibrium constant. A(g) + 2B(g) AB
2
(g) Kc = 59 AB
2
(g) + B(g) AB
3
(g) K
c
= ? A(g) + 3B(g) AB
3
(g) K
c
= 478
8.1
8.1
If you multiply an equation by a number, you raise the equilibrium
constant to that power.
If you reverse a reaction, you take the reciprocal of the equilibrium
constant.
If you add two equations, you multiply their equilibrium constants.
1 out of 1 points
1 out of 1 points
Question 8
Selected
Answer:
Correct
Answer:
Response
Feedback:
Consider the following reaction at equilibrium. What eÖect will adding some graphite have on
the system? CO
2
(g) + C(graphite) 2 CO(g)
No eÖect will be observed since C is not included in the equilibrium
expression.
No eÖect will be observed since C is not included in the equilibrium
expression.
Because the equilibrium is heterogeneous, the solid does not appear in the
equilibrium expression and therefore adding and subtracting graphite will not
shift the equilibrium.
Question 9
Selected Answer:
Correct Answer:
Response
Feedback:
An aqueous solution of ________ will produce an acidic solution.
NH
4
NO
3
NH
4
NO
3
Conjugate bases of strong acids are neutral (i.e. not bases).
(Based on the list of seven strong acids, this mean the ions HSO
4
-
, NO
3
-
, I
-
, Br
-
,
Cl
-
, ClO
3
-
, and ClO
4
-
can form neutral salts.
Group I and II cations form neutral salts, but since ammonium is the conjugate
base of a weak acid (ammonia) it forms an acidic salt.
Anions that are conjugate bases of weak acids form basic salts.
Question 10
Selected Answer:
Correct Answer:
Response
Feedback:
What is the conjugate acid of HCO
3
-
?
H
2
CO
3
H
2
CO
3
An acid donates a proton which is accepted by the lone pair of the
base.
Therefore,
the substance with the added proton is the
conjugate
acid.
1 out of 1 points
1 out of 1 points
1 out of 1 points
Question 11
Selected Answer:
4.66
Correct Answer:
4.66 ± 0.02
Response
Feedback:
What is the expected pH of a nitric acid solution , HNO
3
, with a concentration of 2.21 x 10
-5
M?
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice Exam 2.2
Practice Exam 2.2
Question 12
Selected Answer:
Correct Answer:
Use the following table of data in answering the question below the table:
Acid Name
Formula
pK
a
pK
b
Conjugate
Base
Hydrofluoric acid
HF
3.17
10.83
F
-
Nitrous acid
HNO
2
3.25
10.75
NO
2
-
Hypochlorous acid
HOCl
7.54
6.46
OCl
-
Hypobromous acid
HOBr
8.62
5.38
OBr
-
Hydrocyanic acid
HCN
9.21
4.79
CN
-
Ammonium
NH
4
+
9.24
4.76
NH
3
The acid HN
3
has a pK
a
of 4.72. How many of the conjugate bases shown in the table are stronger
bases than the base N
3
-
?
4
4
1 out of 1 points
1 out of 1 points
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Response
Feedback:
Practice exam 2.4
Practice exam 2.4
Question 13
Selected Answer:
12.34
Correct Answer:
12.34 ± 0.02
Response
Feedback:
At 25º C , what is the pH of a solution prepared by dissolving 0.00823 mol of Ca(OH)
2
in water to give
756.5 mL of solution?
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 5
Practice exam 2 5
Question 14
A weak acid, HA, is dissolved in water given a solution concentration of 0.152 M. The percent dissociation
(ionization) is measured and found to be 8.4%. Based on these data, what is the value of K
a
for this weak
acid?
1 out of 1 points
1 out of 1 points
Selected Answer:
1.17E-3
Correct Answer:
1.17E-3 ± 5%
Response
Feedback:
Enter your answer in exponential format using a capital "E"
(example 1.23E-4) and no units (value ± 5%).
Practice exam 2 6
Practice exam 2 6
Question 15
Selected Answer:
12.26
Correct Answer:
12.27 ± 0.02
Response
Feedback:
Calculate the pH of a 0.362 M solution of a base with a base dissociation constant of K
b
= 9.78 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 7
Practice exam 2 7
1 out of 1 points
Question 16
Selected Answer:
11.12
Correct Answer:
11.12 ± 0.02
Response
Feedback:
At 25º C, what is the pOH of a buÖer that consists of 0.651 M HA and 0.472 M NaA?
HA represents a weak acid with a K
a
of is 9.45 x 10
-4
and NaA represents the conjugate base.
Enter your answer in decimal format with two decimal places (value ± 0.02). Practice exam 2 8
Practice exam 2 8
Question 17
Selected Answer:
8.16
Correct Answer:
8.16 ± 0.02
Response
Feedback:
At 25º C, what is the pH of a 0.152 M aqueous solution of potassium Òuoride (KF) given that the K
a
of
hydroÒuoric acid (HF) is 7.24 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
1 out of 1 points
1 out of 1 points
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Practice exam 2 9
Practice exam 2 9
Question 18
Selected Answer:
False
Correct Answer:
False
Response
Feedback:
True or false:
The pH at the equivalence point is always pH = 7.
If a weak acid is titrated with a strong base, at the equivalence point, the pH will be greater
than 7, (pH > 7).
If a strong acid is titrated with a strong base, at the equivalence point, the pH will be equal
to 7, (pH = 7).
If a weak base is titrated with a strong acid, at the equivalence point, the pH will be less
than 7, (pH < 7).
Practice exam 2.10
Practice exam 2.10
Question 19
1 out of 1 points
1 out of 1 points
Selected Answer:
25.51
Correct Answer:
25.51 ± 1%
Response
Feedback:
Determine the volume in mL of 0.378 M HClO
4
(aq) needed to reach the half-equivalence (stoichiometric)
point in the titration of 53.71 mL of 0.359 M ammonia, NH
3
. The K
b
of ammonia is 1.8 x 10
-5
.
Enter your answer in decimal format with two decimal places (value ±1%).
Practice Exam 2 11
Practice Exam 2 11
Question 20
Selected Answer:
4.07
Correct Answer:
4.07 ± 0.02
Response
Feedback:
A 25.00 mL sample of 0.150 M monoprotic organic acid is titrated with aqueous sodium hydroxide. After
6.42 mL of 0.150 M NaOH is added, what is the pH of the solution?
The K
a
of the acid is 2.97 x 10
-5
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
1 out of 1 points
Practice Exam 2 12
Practice Exam 2 12
Question 21
Selected Answer:
10.42
Correct Answer:
10.61 ± 0.04
Response
Feedback:
One liter of a buÖer is prepared with concentrations of 0.250 M C
2
H
5
NH
2
and 0.250 M C
2
H
5
NH
3
Cl. If
2.13 g of NaOH is then added, what is the resulting pH?
Assume the solution volume does not change
and that K
b
of C
2
H
5
NH
2
is 2.64 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.04).
Practice exam 2 13
Practice exam 2 13
Question 22
0 out of 1 points
1 out of 1 points
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Thursday, May 6, 2021 3:37:55 PM CDT
Selected Answer:
5.55
Correct Answer:
5.55 ± 0.02
Response
Feedback:
The weak base methylamine, CH
3
NH
2
, is titrated with HI
. What is the pH at the equivalence point, if the
concentration of methylammonium iodide, CH
3
NH
3
I
, is known to be 0.348 M?
The K
b
of CH
3
NH
2
is 4.4 x 10
-4
.
Enter your answer in decimal format with two decimal places (value ± 0.02).
Practice exam 2 14
Practice exam 2 14
←
OK
Related Questions
Answer question number 7 on the attached document
arrow_forward
Which one is it?
arrow_forward
Could you please help me format this question, I've been stuck on it for some time now.
arrow_forward
Part c
arrow_forward
口
A docs.google.com
Classroom | Google for Education
Alchemy Lesson 20 & 21 Worksheet
Andres Carrill
Andres Carrillo - Alchemy Lessons 20 & 21 Worksheet
Update Apple ID S
Some account servi
available until you sig
File Edit View Insert Format Tools Add-ons Help
Last edit was 2 days ago
100%
Normal text
Arial
11
BIUA
E = E = EE E - E E X
1
2
3
4
.. 6 I 7 O 8 1 IC
5
AIV-20: Getting Connected (Writing lonic Compounds)
Part 1: Putting together lonic Compounds
lonic compound
Metal
Number of
cation
nonmetal
number of
anion
total
total charge = 0
valence
valence
number of
electrons
electrons
valence
electrons
NaF, sodium fluoride
Na
Na +
(+1)+(-1) = 0
F-
8.
MgO, magnesium oxide
Mg
02-
(+2) + (-2) = 0
MgCl2, magnesium
chloride
Mg
CI
7
16
(+2) + 2(-1) = 0
Ne, neon
Ne
8
BeF2, beryllium fluoride
Be
MgS, magnesium sulfide
CaCl,, calcium chloride
Na
Br
K
Se
Al
Al203, aluminum oxide
Al
Al
F
arrow_forward
image
arrow_forward
100% 7
Tue 5:5
File
Edit
View
History
Bookmarks
Profiles
Tab
Window
Help
Chrome
$550 mustang x
O S550 Mustanc X
(2 unread) - d x
ALEKS - Davi
ALEKS
WPAL 101_ 23
Purple/Black
A Gloss Purple
D Paused
A www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-IvdWKW_BBZZ16tTytly4Fcfu6zOtOf80MM9sefhQp9QAYI8idN-02kVSt27lmROEJa_z..
O CHEMICAL REACTIONS
David
O 1/5
Using a chemical equation to find moles of product from moles ...
with
Ammonium phosphate ((NH4), PO4)
is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid (H, PO,)
liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.10 mol of ammonia. Be sure your answer has a unit symbol, if
necessary, and round it to the correct number of significant digits.
Explanation
Check
Acc
O 2022 McGraw Hill LLC. AlI Rights Reserved. Terms of Use | Privacy Center
olo %
arrow_forward
What safety rules did Andrew break?
arrow_forward
AutoSave
Off
Document1 - Word
P Search
Savannah Hankins SH
File
Home
Insert
Design
Layout
References
Mailings
Review
View
Help
A Share
P Comments
X Cut
O Find -
E
AaBbCcDc AaBbCcDc AaBbC AaBbCcC AaB
I No Spac. Heading 1 Heading 2
Calibri (Body) v 11 - A A" Aa- A
B Copy
Replace
A Select
Paste
BIU v ab x, x A Iv A v
1 Normal
Dictate
Editor
Title
S Format Painter
Clipboard
Styles
Font
Paragraph
Editing
Voice
Editor
Using the balanced equation for the combustion of ethanol:
C2H60+302 -> 2CO2+3H20
a.How many grams of CO2 are formed from 0,50mol of ethanol?
ww
b.How many moles of H20 are formed from 24 g of ethanol?
c.How many grams of 02 are needed to react with 0.25 mol of ethanol? 24
Page 1 of 1
50 words
D Focus
100%
12:35 AM
O Type here to search
a
99+
a 4)
19
2/3/2021
arrow_forward
LIS 0 x Cee res te erE
O Esoe 2011
O Empower 2021
A educate lindsay.k12.ca.us/iframe.aspx?Ctrl STUDENT BASE HOME CONTROL
dsay Bookmarks
A Classes O Google Sides
O Empower 2020 E Google Docs
t Lindsay High School R Phynics Safety & Sk
E Guided practice 3L
Flag for follow-up
Group-12 )436 9 10 11 12 13 14 15 16 17 10
Irerlod
The Perlodic Table of the Elements
Elements in the same group tend to have similar characteristics, but some things like tendency to gain or lose electrons can still vary
even within a group Which of the following is true regarding the elements in group 2?
O A Be, Beryllium is the largest and has the greatest tendency to gain electrons.
OB Be Beryllium and Ba, Barium will have the same tendancy to lose electrons
OC Ra, Radium is the smallest and will have the greatest tendency to lose electrons.
O D. Ba, Barium will have a greater tendency to lose electrons than Mg, Magnesium.
DELL
%23
E
S
A
C
arrow_forward
W
AutoSave
Off 周り
Assignment 3-1 Saved to this PC ✓
Search
Review View Help
File
Home Insert Draw Design
Aptos (Body)
Layout References Mailings
▾ 11
A A Aav
Ро
Paste
B
I
U
く
ab
x² A
✓
く
Clipboard
Page 8 of 10
1 82°F
Sunny
254 words
ㄈㄨˋ
Font
☑
く
Paragraph
Christiana Taylor CT
Comments
Editing ✓ Share
Find
✓
T
Normal
No Spacing Heading Heading 2
Replace
Select ▾
☑
Styles
Editing
6. Draw the arrow-pushing mechanism and propose the product(s). When appropriate, make
sure to indicate the appropriate stereo-/regio-chemistry of the product(s). Note that the
mechanism(s) by which the product(s) form in reactions A and B are shown in pink. For
reactions C, D, and E you need to deduce the mechanism by carefully analyzing your
reagents and conditions.
A.
Br
OH
E1 and SN1
B.
H₂O
SN1
Hint: A mixture of two allylic alcohols forms.
叹
Text Predictions: On
Accessibility: Investigate
2
17
Q Search
W
Focus
Dictate Editor
Add-ins
Voice
Editor
Add-ins
>
+ 100%
3:15 PM
4/2/2024
arrow_forward
3 Micros X
6 Modul X
I Course X
S What i Te219 x
G intelle x
Intelle x
com/course.html?courseld%=16985674&OpenVellumHMAC=a46387336edc299b16 49c591bf9ad36#10001
Provide Feedback
11:18 AM
75°F Partly sunny
O O 4x a
12/10/2021
36
arrow_forward
O : Q 8
File
Edit
View
History
Bookmarks
Profiles
Tab
Window
Help
O Psychology Research Sign-Up x
WPAL 101 233 Spring 202
ALEKS
A ALEKS - Reyna Garcia
Watch Gilmore Girls | Netflix
A www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-lvdWKW_BBZZ16tTytly4Fcfu6zOtOf8oMM9smRgOXk4zql8rHN-B4Sv7Er8YkAkkZH6IMU... O * G
Spotify Web Playe. M Common Ethical D.
O CHEMICAL REACTIONS
0/5
Solving moles-to-moles limiting reactant problems
Nitrogen dioxide (NO2) gas and liquid water (H,O)
react to form aqueous nitric acid (HNO,) and nitrogen monoxide (NO)gas. Suppose you have 2.0 mol of
NO, and 5.0 mol of H,O in a reactor.
Calculate the largest amount of HNO, that could be produced. Round your answer to the nearest 0.1 mol.
| mol
Explanation
Check
OU Rinhts Reserved. Terms of Use I Privacy Center Accessib
arrow_forward
ent
arch
X
Aktiv Chemistry
ADD FACTOR
x( )
4.82 × 104
10¹2
A laser pulse is 4.82 x 10-2 milliseconds How many nanoseconds is this?
10-⁰
4.82 x 10-8
10⁰
ns
10 º
4.82 × 10²
X
Question 30 of 31
4.82 x 10-14
ART
ms
PeopleSoft session expired
10-12
4.82 x 10-5
10⁰
ANSWER
4.82 x 1016
4.82 x 10-²
4.82 x 101⁰
min
1015
X ? Anthropology and Archaeolo X
μs
10³
4.82 × 10-11
RESET
5
10-3
P
1
arrow_forward
Chrome
File
Edit
View History
Bookmarks People
Tab
Window Help
78% O
Thu 10:02 PM
A ALEKS - Jacqueline Hoppenrey x
A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQİHQRDYV_6Ux63SypJXz0Coxvwqgg4JkWI7XM99oekXTcojkLT31OZqp4772m0XOsdozQ5qMD3aRdEyOGQe33sgOsaJ.
O GASES
Calculating partial pressure in a gas mixture
Jacqueline
A 5.00 L tank at 7.37 °C is filled with 18.2 g of chlorine pentafluoride gas and 3.28 g of boron trifluoride gas. You can assume both gases behave as ideal gases
under these conditions.
Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. Round each of your answers to 3 significant digits.
圖
mole fraction:
chlorine pentafluoride
partial pressure:
| atm
mole fraction:
boron trifluoride
partial pressure:
| atm
Total pressure in tank:
| atm
Explanation
Check
O2021 McGraw-Hill Education All Rights Reserved Terms of Use Privacy Accessibility
MacBook Air
山回
arrow_forward
Chrome
File
Edit
View
History
Bookmarks People Tab
Window
Help
89%
Mon 9:32 PM
Student Students
Homework DUE Monday, April X
Madeline Carlo - CHM 112 HW X
+
A docs.google.com/document/d/10m8ZGoSGXKFFcl4KWhwOLh8bFpbtPAmvTWjJPnj15U4/edit
Madeline Carlo - CHM 112 HW DUE Monday April 12, 2021 ☆ D
TURN IN
Share
File Edit View Insert Format Tools Add-ons Help
Last edit was 3 days ago
100%
Normal text
Arial
11
B IU A
Editing
31
1
III I
3 III
I 4
III| I
5 II II
I 7 II I|
.1. Refer to the table of standard reduction potentials.
Standard Reduction Potentials at 25 C
Reduction Half-Reaction
(V)
FAg + 2 €
H2O{aq) + 2 H*(aq)+ 2 6
Mno,taq) + 8 H*(aq) + 5 &
Clalg) + 2 e
CrOFMaq)+ 14 H*(aq) + 6 6-
Ozlg + 4 H*(aq) + 4 &
Bra() + 26
Ag*(aq) + e
Fe*(aq) + e
Ozl9) + 2 H'(aq) + 2 €
2(s)+ 26
Ozlg) + 2 HO) + 46
Cu (aq) + 2 €
Sn" (ag)+ 2 6
2 P(aq)
2 H2O()
→ Mn(aq) + 4 H;0()
→2 cr(aq)
2 Cr (aq)+ 7 H0()
→2 HO()
2 Br(aq)
Ag(s)
» Fe*(aq)
→H;Oz(aq)
→2 F(aq)
→4 OH"(aq)
2.87
1.78
1.51
1.36
1.33
3.
1.23
1.09
0.80
0.77…
arrow_forward
hrome
File
Edit
View History Bookmarks People
Tab
Window Help
17% O
Tue 9:35 PM
A ALEKS - Esther Octave Learn X
+
A www-awa.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IBcn9hvCfbYq_fi3Zsn8H2oW_5PTMI0acVC-FOMLOK3cK7T6K1BWbc47sbYw. *
Paused
E Apps M Gmail
YouTube Maps
BC Broward College |.
Sample Source An...
O New Tab
G What does Duckw.. E Untitled documen...
O ELECTRONIC STRUCTURE
OO
Esther
Calculating the wavelength of a spectral line from an energy..
-21
". You can find the meaning of
This energy diagram shows the allowed energy levels of an electron in a certain atom. (Note: the SI prefix 'zepto' means 10
any SI prefix in the ALEKS Data tab.)
1400 -
1200 -
-C
dlo
1000 -
800
Ar
energy (z)
B
600 -
-A
400.
200-
Use this diagram to complete the table below.
What is the energy of the electron in the ground state?
What is the energy of the electron in the first excited
state?
O absorbed
If the electron makes the transition shown by the red
arrow, from C to A, will a photon be…
arrow_forward
Chrome
File
Edit
View
History
Bookmarks People Tab
Window Help
89%
Mon 9:33 PM
Student Students
Homework DUE Monday, April X
Madeline Carlo - CHM 112 HW X
+
A docs.google.com/document/d/10m8ZGoSGXKFFcl4KWhwOLh8bFpbtPAmvTWjJPnj15U4/edit
Madeline Carlo - CHM 112 HW DUE Monday April 12, 2021 ☆ D
TURN IN
Share
File Edit View Insert Format Tools Add-ons Help
Last edit was 3 days ago
100%
В IUA
Normal text
Arial
11
+
Editing
31
1
III I
III 1 I
2
3 1
I 4
5 II II
6 1
III |
.5.
For a reaction in which E° = -0.100 V and n = 1 mol electrons / mol, calculate AG°. State
+
your assumptions, if any, about temperature.
.6.
For a reaction in which E° = 0.100 V andn = 1 mol electrons / mol, calculate AG° at 25°C.
Dictionary
CC
Aa
...
!!!
II
III
arrow_forward
Chrome
File
Edit
View
History
Bookmarks People
Tab
Window Help
89%
Mon 9:33 PM
Student Students
Homework DUE Monday, April X
Madeline Carlo - CHM 112 HW X
+
A docs.google.com/document/d/10m8ZGoSGXKFFcl4KWhwOLh8bFpbtPAmvTWjJPnj15U4/edit
Madeline Carlo - CHM 112 HW DUE Monday April 12, 2021 ☆ D
TURN IN
Share
File Edit View Insert Format Tools Add-ons Help
Last edit was 3 days ago
100%
В IUA
Normal text
Arial
11
+
Editing
31
1
III I
III 1 I
2
3 1
I 4
5 II II
6 1
III |
MnO, (aq) + 8H*(aq) + 5e → Mn²*(aq) + 4 H,O(1)
Al(s) → Alš*(aq) + 3 e
+
.ЗА.
Assign oxidation numbers to all metals whether they be elemental, monatomic ion, or in
a polyatomic ion, in questions (1) and (2),
.3B. Tell what is being oxidized and what is being reduced in each reaction in questions (1) and
(2).
.3C. Identify each half-reaction in question (2) as oxidation half-reaction or reduction
half-reaction.
.4. Do you need to know the temperature to calculate AG° from E°? Explain.
>
Dictionary
CC
Aa
...
!!
II
arrow_forward
Chrome
File Edit
View History Bookmarks People Tab
Window Help
74%
Sat 2:20 PM
Kayley Valentine
OneLogin
x O Microsoft Office Home
Content
New Tab
AALEKS-Kayley Valentin x
A www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNsikr7j8P3jH-IBI5ahvJxLWwcNXdqGDIniqicnbb-P2iXO0filILEyqsWt8DxNO...
E Apps
HPrechecks: Test 2.
O MATTER
Calculating mass density
Try again.
Kayley v
A chemist v v
as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of
pentane, dimethyl sulfoxide, acetone, methyl acetate, and chloroform.
The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from his collection of Material Safety
Data Sheets (MSDS), the chemist finds the following information:
liquid
density
0.63
mL
pentane
db
dimethyl sulfoxide
1.1
0.79
acetone
0.93
mL
methyl acetate
1.5
chloroform
3
Next, the chemist measures the volume of the unknown liquid as 1797.…
arrow_forward
There is one incorrect answer here. Can you help me figure out which one?
arrow_forward
View
History
Bookmarks
People
Tab
Window
Help
S, Amaya K - Outlo x
B Chapter 5- CHEM-1110-941- x
Question 20 - Chapter 5- Con x
education.com/ext/map/index.html?_con%3con&external_browser%3D0&launchUrl=https%253A%252F%252Flms
Saved
3 attempts left
Check my work
Enter your answer in the provided box.
It takes 155 s for an unknown gas to effuse through a porous wall and 97 s for the same volume of N2
gas to effuse at the same temperature and pressure. What is the molar mass of the unknown gas?
g/mol
...
115
MAR
1664
18
ottv A
arrow_forward
1:14 PM Fri 20 Dec
67%
Grade 7 CBE 03/12/2024 (OOW_7D 2024-25 Ms Sunita Harikesh)
Activity
Hi, Nimish. When you submit this form, the owner will see your name and email address.
Teams
Assignments
*
Required
Camera
Calendar
Files
...
More
Skill: Advanced or complex data
representation or interpretation.
Vidya lit a candle and covered it with a glass.
The candle burned for some time and then went
off. She wanted to check whether the length of
the candle would affect the time for which it
burns. She performed the experiment again after
changing something.
Which of these would be the correct
experimental setup for her to use? * (1 Point)
She wanted to check whether the length of the candle would affect the time for which it burns.
She performed the experiment again after changing something.
Which of these would be the correct experimental setup for her to use?
A
Longer candle;
No glass
C
B
Longer candle;
Longer glass
D
D
B
Longer candle;
Same glass
Same candle;
Longer glass
arrow_forward
Course Home
8 https://openvellum.ecollege.com/course.html?courseld=16516363&OpenVellumHMAC=6607995b61ef1ebc798fc86a6680d4f.
O My Courses
Submit
Request Answer
Part B
Calculate the molarity of 70.0 g of HCl in 1.50 L of an HCl solution.
Express your answer with the appropriate units.
HÁ
?
molarity =
Value
Units
Submit
Request Answer
8:37 PM
P Type here to search
%23
O O G 4)
4/29/2021
近
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Related Questions
- Part carrow_forward口 A docs.google.com Classroom | Google for Education Alchemy Lesson 20 & 21 Worksheet Andres Carrill Andres Carrillo - Alchemy Lessons 20 & 21 Worksheet Update Apple ID S Some account servi available until you sig File Edit View Insert Format Tools Add-ons Help Last edit was 2 days ago 100% Normal text Arial 11 BIUA E = E = EE E - E E X 1 2 3 4 .. 6 I 7 O 8 1 IC 5 AIV-20: Getting Connected (Writing lonic Compounds) Part 1: Putting together lonic Compounds lonic compound Metal Number of cation nonmetal number of anion total total charge = 0 valence valence number of electrons electrons valence electrons NaF, sodium fluoride Na Na + (+1)+(-1) = 0 F- 8. MgO, magnesium oxide Mg 02- (+2) + (-2) = 0 MgCl2, magnesium chloride Mg CI 7 16 (+2) + 2(-1) = 0 Ne, neon Ne 8 BeF2, beryllium fluoride Be MgS, magnesium sulfide CaCl,, calcium chloride Na Br K Se Al Al203, aluminum oxide Al Al Farrow_forwardimagearrow_forward
- 100% 7 Tue 5:5 File Edit View History Bookmarks Profiles Tab Window Help Chrome $550 mustang x O S550 Mustanc X (2 unread) - d x ALEKS - Davi ALEKS WPAL 101_ 23 Purple/Black A Gloss Purple D Paused A www-awu.aleks.com/alekscgi/x/lsl.exe/1o_u-IgNslkr7j8P3jH-IvdWKW_BBZZ16tTytly4Fcfu6zOtOf80MM9sefhQp9QAYI8idN-02kVSt27lmROEJa_z.. O CHEMICAL REACTIONS David O 1/5 Using a chemical equation to find moles of product from moles ... with Ammonium phosphate ((NH4), PO4) is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid (H, PO,) liquid ammonia. Calculate the moles of ammonium phosphate produced by the reaction of 0.10 mol of ammonia. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits. Explanation Check Acc O 2022 McGraw Hill LLC. AlI Rights Reserved. Terms of Use | Privacy Center olo %arrow_forwardWhat safety rules did Andrew break?arrow_forwardAutoSave Off Document1 - Word P Search Savannah Hankins SH File Home Insert Design Layout References Mailings Review View Help A Share P Comments X Cut O Find - E AaBbCcDc AaBbCcDc AaBbC AaBbCcC AaB I No Spac. Heading 1 Heading 2 Calibri (Body) v 11 - A A" Aa- A B Copy Replace A Select Paste BIU v ab x, x A Iv A v 1 Normal Dictate Editor Title S Format Painter Clipboard Styles Font Paragraph Editing Voice Editor Using the balanced equation for the combustion of ethanol: C2H60+302 -> 2CO2+3H20 a.How many grams of CO2 are formed from 0,50mol of ethanol? ww b.How many moles of H20 are formed from 24 g of ethanol? c.How many grams of 02 are needed to react with 0.25 mol of ethanol? 24 Page 1 of 1 50 words D Focus 100% 12:35 AM O Type here to search a 99+ a 4) 19 2/3/2021arrow_forward
- LIS 0 x Cee res te erE O Esoe 2011 O Empower 2021 A educate lindsay.k12.ca.us/iframe.aspx?Ctrl STUDENT BASE HOME CONTROL dsay Bookmarks A Classes O Google Sides O Empower 2020 E Google Docs t Lindsay High School R Phynics Safety & Sk E Guided practice 3L Flag for follow-up Group-12 )436 9 10 11 12 13 14 15 16 17 10 Irerlod The Perlodic Table of the Elements Elements in the same group tend to have similar characteristics, but some things like tendency to gain or lose electrons can still vary even within a group Which of the following is true regarding the elements in group 2? O A Be, Beryllium is the largest and has the greatest tendency to gain electrons. OB Be Beryllium and Ba, Barium will have the same tendancy to lose electrons OC Ra, Radium is the smallest and will have the greatest tendency to lose electrons. O D. Ba, Barium will have a greater tendency to lose electrons than Mg, Magnesium. DELL %23 E S A Carrow_forwardW AutoSave Off 周り Assignment 3-1 Saved to this PC ✓ Search Review View Help File Home Insert Draw Design Aptos (Body) Layout References Mailings ▾ 11 A A Aav Ро Paste B I U く ab x² A ✓ く Clipboard Page 8 of 10 1 82°F Sunny 254 words ㄈㄨˋ Font ☑ く Paragraph Christiana Taylor CT Comments Editing ✓ Share Find ✓ T Normal No Spacing Heading Heading 2 Replace Select ▾ ☑ Styles Editing 6. Draw the arrow-pushing mechanism and propose the product(s). When appropriate, make sure to indicate the appropriate stereo-/regio-chemistry of the product(s). Note that the mechanism(s) by which the product(s) form in reactions A and B are shown in pink. For reactions C, D, and E you need to deduce the mechanism by carefully analyzing your reagents and conditions. A. Br OH E1 and SN1 B. H₂O SN1 Hint: A mixture of two allylic alcohols forms. 叹 Text Predictions: On Accessibility: Investigate 2 17 Q Search W Focus Dictate Editor Add-ins Voice Editor Add-ins > + 100% 3:15 PM 4/2/2024arrow_forward3 Micros X 6 Modul X I Course X S What i Te219 x G intelle x Intelle x com/course.html?courseld%=16985674&OpenVellumHMAC=a46387336edc299b16 49c591bf9ad36#10001 Provide Feedback 11:18 AM 75°F Partly sunny O O 4x a 12/10/2021 36arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY