Lab Report 5
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Apr 3, 2024
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Experiment 5: Qualitative and Quantitative Aspects of Equilibrium
Report Sheet
You are welcome to seek guidance on the content of this lab report from your TA during your lab session
and from the lab coordinator during lab office hours. You are also welcome to work constructively with
your peers on the general content and understanding of the material. However, the work submitted here
in this report sheet must be your own. For more details on academic integrity and potential penalties see
the
Code of Behaviour on Academic Matters
.
I certify that this submitted laboratory report represents entirely my own efforts. I have read and
understand the University of Toronto policies regarding, and sanctions for, academic honesty.
I regret that I violated the Code of Behaviour on this assessment and would like to admit that
now so that I can take responsibility for my mistake.
A. Heat capacity of calorimeter
1.
Insert your two plots of temperature vs. time for the calibration of the calorimeter and
complete the table.
Plot #1
Plot #2
Run #
Initial Temperature of HCl (
o
C)
Initial Temperature of NaOH (
o
C)
Extrapolated Final Temperature (
o
C)
1
18.6
20.4
26.6
2
19.5
20.2
26.3
2. Was your solution acidic or basic after the run was complete? What does this tell you about
the reaction?
After the run was complete the solution was highly basic at pH 12. This means the reaction was a strong
acid-base reaction and is exothermic which can be seen from the rise in the temperature at the beginning.
3. Show your calculation of the heat capacity of the calorimeter (for run #1).
C = n/V
∴
n = CV
n
HCl = (1.0 M) (0.75)
n
NaOH = (1.1 M) (0.75)
= 0.075 mol
= 0.0825 mol
(HCl = limiting reagent)
qReaction =
nΔH
0
H3O + OH
= (0.075 mol) (-58985 J/mol)
= 4423.88
(
-58985 J/mol is found using the table in lab manual page 5-7 for the initial temperature 18.6
o
C )
HEAT CAPACITY OF CALORIMETER -
nΔH
0
H3O + OH = - (C
CAL
ΔT
CAL
+
C
WATER
V
ACID
ΔT
ACID
+
C
WATER
V
BASE
ΔT
BASE
∴
- (4.13
J/
o
C
-1
mL
-1
* 28.1
o
C + 4.13
J/
o
C
-1
mL
-1
* 75 mL* 28.1
o
C + 4.183
J/
o
C
-1
mL
-1
* 75 mL * 28.1
o
C
= - 5431.91
nΔH =
- C
CAL
ΔT - 2C
ACID
VΔT
∴
- 4423.88 = - C
CAL
(6.9) - 2(4.18)(75 mL)(6.9)
∴
- 4423.88 = - C
CAL
(6.9) - 4326.3
∴
C
CAL
(6.9) / (6.9) = - 4326.3 + 4423.88 / 6.9
∴
C
CAL
= 14.14 J/
o
C
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Related Questions
Please upload your full solution to the following problem.
For the experimental isotherm data given below, determine the Freundlich and Langmuir isotherm
parameters. Apply linear regression to determine the isotherm parameters. A spreadsheet can be used
for this purpose. Which of the two isotherms better describes the data?
Experimental data:
Carbon type: F-400
Carbon size: 200 × 400
. Chemical: Trichloroethene, C₂HCl3 (131.39 g/mol)
Temperature: 13 C
pH: 7.5-8
Equilibrium time: 31 days
●
Ⓡ
B
B
Sample
number
123456
TCE Liquid-Phase
Concentration
CA. μmol/L
23.6
6.67
3.26
0.322
0.169
0.114
TCE Adsorbent-Phase
Concentration
9A, μmol/g
737
450
318
121
85.2
75.8
2
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Experiment 16-Pre-Lab Assignment
Name:
1. Design a preliminary procedure including sample calculations to determine the heat of
neutralization for the reaction between 1.0 M HCl and 1.0 M NAOH in kJ/mol. Use your knowledge
of the chemicals, their properties, and the laboratory techniques learned thus far in this course.
Any chemicals and equipment that you require will be provided in the lab. This procedure must
be approved by your instructor before you can begin experimentation.
unpe
16-3
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You continue with the Arrhenius Plot with the slope of the curve to be
approximately -12,500 K and the Arrhenius factor of 4.367 E10 hours^-1.
What is the shelf life of the drug at 22 C? What is the shelf life at 4 C?
Did your coworker achieve a century shelf life in either storage
condition? Be sure to show your calculations.
Arrhenius Plot
In (k)
-8
-10
-12
-14
-16
-18
0.0026
0.0028
0.0030
1/T
0.0032
0.003
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Question attached as photo.
This is not a exam/ test question:) you can see that our prof has written sth on this question, it is a question that he wants us to practice on our own in lecture. Thanks
Topic related to 1st order/ 2nd order kinetics, need excel/graph to do this question, need TWO plots to check whether they are 1st/2nd order
concentration = activity * m (concentration is proportional to activity plus a constant m)
1/[A] =1/[A]0 + Kt
1/[Activity* m] = 1/[Activity0 *m] +Kt
1/[Activity] =1/ [Activity]0 + mKt
Do we follow the equations of zeroth, 1st, 2nd order reactions?
What is the key idea to determine whether this data gives 1st or 2nd order kinetics?
Our prof was saying that if it's linear graph, means it is in correct order. BUT i have plotted 3 datas, two of them looks kinda linear to me. (the 2nd order and zeroth order graph are similar) If we are choosing from zeroth/2nd order, how do we determine its order if it's line is similar in linearity?
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1. This question is adapted from Harris 19-D.
Carnosine is a dipeptide whose antioxidant properties protect cells from free radicals. Carnosine was
determined by derivatization with naphthalene-2,3-dicarboxyaldehyde and cyanide followed by
fluorescence detection using excitation at 445 nm and emission at 490. Quantification was by standard
addition. To four aliquots of 20-ul cell lysate were added volumes of 100µM carnosine standard to
generate final concentrations of 0, 1.0, 2.5, and 5.0 µM added carnosine. Solutions were diluted to 70µl
before addition of 15µl of 5 mM naphthalene-2,3-dicarboxyaldehyde and 15µl of 10 mM NaCN.
H
H2N.
OH
Carnosine
HN.
Naphthalene-2,3-
dicarboxyaldehyde
Cyanide
OH
Fluorescent product
HN.
Fluorescence intensity
Concentration (uM) of added carnosine
in final 100 µL
0.0
0.465
1.0
0.698
2.5
1.029
5.0
1.651
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tal v
أنظمة التلم الإلكترولي
Old Courses
Time left 0:32:54
Using the following information in the table below, the best solvent to extract A from water
is
Compound
Solubility in g, per 100 g of solvent
Water
Dichloromethane
Ethanol
Acetone
2
8.
12
14
2
10
7.
11
O a. Dichloromethane
O b. Water
Oc.
Acetone
O d. Ethanol
TOSHIBA
INS
&
50 6 1
7 V
8A94
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You continue with the Arrhenius Plot with the
slope of the curve to be approximately -12,500
K and the Arrhenius factor of 4.367 E10
hours^-1. What is the shelf life of the drug at 22
C? What is the shelf life at 4 C? Be sure to
show your calculations.
Arrhenius Plot
-8
-10
-12
-14
-16
-18
0.0026
0.0028
0.0030
0.0032
0.003
1/T
In (k)
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Part C
Estimate AH for the reaction.
нн
H.
H-N-N-H+ Cl-CI2H-Ń-CI
Express your answer using one significant figure.
?
AH =
kJ
Submit
Request Answer
< Return to Assignment
Provide Feedback
Master..
Spotify..
Formal..
amazon
B.
88
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please show work or why you chose that answer
thankyou so much!
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Qno3 solve please dont reject. Fill all and asignmnt list also fill dont reject okk
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Reaction Cone, Nayd 0 Cine. HCI 4Als.
AIme (3)
0.10 M
I1.3085840
• 30M 0.4563164 |0.028 F0913
115 M 12267196|0.01870913
30M |1.5360817 O.300349
65.56796607
5. 11431671
0.10 M
3
d.050 M
4
0.025 M
0:30M
1.3686611
1.007568
1,358380874
2. Compare the rates of reactions 1 and 2. What is effect on the reaction rate of halving the acid
concentration? What is the order of the reaction in hydrochloric acid?
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X
app.101edu.co
#
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UL Week 7: Panopto
DII
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Identify the best conditions to complete the SN2 reaction shown below.
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گیا
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6
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Question 18 of 24
40
X
F6
&
7
C|Chegg.com
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F7
8
A) CH3I, THF
B) NaCN, DMSO
C) NaN3, ethylamine
D) KI, THF
X +
E) NaN3, DMF
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Table 2: Molarity of H2O2 and KI and Reaction Rate
Trial
H2O2 Concentration, M
KI Concentration, M
Reaction Rate(Reciprocal Slope)
1
0.29 M
0.40 M
14.08
2
0.29 M
0.20M
25
3
0.023 M
0.40 M
20
Please help me with this part, and please show me all steps
Order with respect to H2O2:
Order with respect to KI:
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Second-degree Equation
Step 1. Copy the given table on your graphing paper, after your student details.
X (% concentration)
0.50
1.00
1.50
2.00
2.50
3.00
Y (oil separation)
5.10
3.60
2.60
2.00
1.40
1.00
Log Y
Step 2. Initially plot the x and y values on a regular graphing paper (or millimeter graphing paper - if available, preferred for precision). Label then connect the points to observe curved line.
Step 3. Since the line is curved, the y-intercept cannot be easily determined because you can’t exactly determine the direction of the line once extrapolated. To obtain a straight line, first, compute the logarithm values of all the y values up to the 2nd decimal place (for the purpose of easy plotting later) and fill in the table.
Step 4. On another graphing paper, plot then label the x and log y. Using a dotted line, extrapolate the straight line to the y axis. Label this point as “a” for the y-intercept.
Step 5.…
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None
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In Experiment 4- Chemical Kinetics “The Rate of Chemical Reaction”, the following data were obtained: Rxn Mixture time(s) temperature (˚C) 1 190 23.0 2 378 23.0 3 97 23.0 4 205 23.0 5 44 23.0 6 90 35.0
Concentrations and portions for reaction mixture number one:
H2O
0.050 M
Buffer
0.050 M
KI
(mL)
0.1% Starch
(mL)
0.0450 MNa2S2O3(mL)
0.8525 M
H202
(mL)
75.0mL
30.0mL
25.0
5.00
5.00
10.00
Use the data above to answer the following questions where applicable.
(a) Write the formulas of the reactants, there are three, in the reaction being studied.Signs + or - or subscripts may be entered all on the same line; S2O32- can be entered as S2O3^2-, the symbol, ^, is not required if the…
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Using the graph below, determine the time it will take for half of the reagent present at t = 60 sec to react.
b.
196 s
c.
256 s
d.
120 s
e.
60 s
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Would the exponents, m and n, in your rate expression be larger than, smaller than, or unchanged from the correct values as a result of each of the following mistakes? Indicate clearly your reasoning.
Experiment 3: 20.0mL of 0.10M KI, 5.0mL of distilled water, 5.0mL H2O2
rate = k[H2O2]m[I-]n
a) A leak occurred around stopper A in the mouth of the Erlenmeyer flask during experiment 3.
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