file Lab 3 - Pure Bending Test

The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mm diameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stressstrain diagram determine the followings properties of the material (Poisson’s ratio of the material is 0.32) :

An aluminum alloy bar of square cross Stress (MPa) Strain section (13 mm x 13 mm) is loaded in 55 0.0006 0.0015 tension by axial forces P. 117 186 0.0024 Stress-strain data obtained from a 241 296 0.0032 0.0040 tension test of the same alloy are 345 0.0046 0.0052 0.0058 0.0062 listed in the table. 400 427 441 (a) What is the modulus of elasticity 448 0.0065 E of the aluminum? 0.0073 0.0081 461 469 (b) What is the maximum load P if the stress in the bar is not to exceed the proportional limit?

Stress Vs Strain on Aluminium 120.00 100.00 80.00 60.00 40.00 20.00 0.00 -20.00 -40.00 Strain (mm/mm) Stress (MPa) 0000'0 0.0105 0.0211 0.0316 0.0422 0.0527 0.0633 0.0738 .0854 0.0855 0.0856 6.0857

1. A cylindrical specimen of a metal object with a radius of 3.8E-2 m and a gauge length of 20.31 mm is pulled in tension. Use the load-elongation characteristics tabulated below to answer the following questions; Load Length (N) (mm) 20.31 20.38 12 20.45 18 20.51 24 20.55 30 20.61 36 20.64 42.8 20.68 48.9 20.72 55.2 20.76 60 20.79 65.8 20.84 70.7 20.87 77.3 20.93 83.1 20.98 88.6 22.15 91.58 23.24 91.68 25.41 0 6 Change in length Length (x10-2 m) (m) Computed strain Computed stress (N/m²) (a) Compute the cross-sectional area of brass. (3

In a tensile test of stainless steel, the following data were obtained: Load (N) 7,200 11,250 13.500 16,200 18.900 Elongation (mm) 0.0 0.505 2.03 5.08 20,200 15.24 20,700 13,200 24.90 10.16 21.80 The dimensions of the cylindrical specimen were initial length L₁ = 50.8 mm and initial arca A₁ - 35.8 mm² and the area at fracture was Ar 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength

I have plotted stress strain curve as shown in attached pictures. I want to know that: What does the slope represent and what does it indicate? Can you find what is the material used? How to find it?

A specimen with cylindrical shape was subjected to tensile test. Please plot the stress vs. strain curve for the specimen and calculate Young's modulus. Diameter of test specimen, do = 11.600 mm Length of test specimen, lo = 50.500 mm Load vs. elongation data for the test specimen Load (N) Length (mm) 7.150 50.594 14.840 50.768 22.760 50.942 30.220 51.116 33.980 51.290 37.900 51.464 41.120 51.892 44.220 52.320 45.540 52.748 47.120 53.684 46.760 54.620 45.280 55.550 44.620 56.238 41.700 56.920 36.220 57.602

Calculate the total tensile strength (mitotic tensile strength test experiment) for the information in the table below 23 D mm Time sec Load KN 54 15 14 52 15 14 3. 57 16 15.5 55 13 18 53 15 14 6. 58 20 19 7 50 17 8 56 19 21

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The stress-strain curve for a material is shown below. The modulus of toughness for this material is most closely equal to: σ (ksi) 105 90 75 60 8 45 30 15 0 0 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0 0.001 0.002 0.003 0.004 0.005 0.006 0.007 28 ksi 16 ksi 38 ksi 22 ksi € (in./in.)

stress 0.02 0.018 0.016 0.014 0.012 0.01 0.008 0.006 0.004 0.002 0.05 0.1 0.15 0.2 0.25 0.3 0.35 Determine : 1- Stress, Stratn care 2. elastic Zone 3. yield sbresscoys 4- plastic Zone 5- UItimate Stress Cous 6- Elongation 7- propotionaL stress cops 8-fructurc stress coF)

The following data are taken from a 20mm in diameter bar of length 250mm, the following results were recorded. Assume that the curve of the stress-strain diagram is linear from the origin to the first point. P (load in kN) 8(elongation in mm) 112 0.2 154 0.3 167 0.4 0.5 174 181 0.8 Determine the a. Stress at 187 kN load in MPa b. Strain at 167 kN load in mm/mm (expressed in scientific notation) c. Modulus of elasticity in MPa d. Modulus of resilience in N-mm/mm e. Modulus of toughness in N-mm/mm 234 oo OOO O0

Analyse the differences between the 2 attached stress-strain curves for 0.9% carbon steel and 0.15% carbon steel.

I need handwritten solution if u skip any part then i swear, it's simple do all otherwise skip

Table B2: Stress-strain data for uniaxial compression test on Sample Normal stress Uniaxial strain (%) Lateral strain (%) (MPa) 0.0 0.0000 0.0000 5.0 0.0319 -0.0150 10.0 0.0720 -0.0275 15.0 0.1025 -0.0425 20.0 0.1450 -0.0600 25.0 0.1755 -0.0725 30.0 0.2150 -0.0875 35.0 0.2455 -0.1025 41.0 0.2815 -0.1125 46.0 0.3125 -0.1209 52.0 0.3515 -0.1285 58.0 0.4000 -0.1325 (f) Based on the plotted curve, calculate the average/tangent Young's modulus and Poisson's ratio for this sample, at 50 % UCS?

Problem :- The following data was obtained tensile test on a specimen of 6 mm diameter and gauge length Lo=30 mm: load(KN) 0 40 80 95 90 135 150.2 145 130 120 elongation(mm) 0 0.022 0.13 0.25 0.55 2.01 3.88 4.12 5.22 6 Plot engineering and True (stress-strain) curves, then determine the (oy, ɛy), (ou, ɛu), (of, , ef), ductility, modulus of elasticity. Then select on the drawing ((strain hardening (n)) , (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region)?

400 350 300 250 200 150 100 50 0.002 0.004 0.006 0.008 0.01 Strain Stress (MPa)

Please do a-c and for c there is 3 parts aswell. Thank You. Also part c is the most important one so please prioritize that one.

A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of 38.1 mm is pulled in tension. Use the load-elongation characteristics tabulated below. The modulus of resilience (Ur) is the area under the engineering stress-strain curve. Compute the Ur.

a. Plot the stress strain diagram b. Find the modulus of elasticity, ultimate stress and fracture stress and explain each term. Define modulus of toughness and find the same for the above specimen. Load (kN) Elongation (mm) 11.1 31.9 0.0175 0.0600 37.8 0.1020 40.9 0.1650 43.6 53.4 62.3 64.5 0.2490 1.0160 3.0480 6.3500

Help me please

And **The modulus of elasticity** (MPa) I need a clear step by step answer please :)

The stress-strain diagram for a steel alloy having an original diameter of 0.80 in. and a gage length of 2 in. is shown in the figure below. (Figure 1) Figure ☛ (ksi) 80 70 60 50 40 30 20 10 0 0 004 0.08 0.12 0.16 0.20 0.24 0.28 0 0.0005 0.001 0.0015 0.002 0.0025 0.0030.0035 1 of 1 € (in./in.) Determine the modulus of elasticity for the material. Express your answer to three significant figures and include appropriate units. Expprox Value Submit Part B Submit Py = Value Part C Request Answer Determine the load on the specimen that causes yielding. Express your answer to three significant figures and include appropriate units. μà μà P₁ = Request Answer Units Value Units Determine the ultimate load the specimen will support. Express your answer to three significant figures and include appropriate units. MIC ? Units www ? www ?

A tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1) Figure Load (kip) Elongation (in.) 0 0 1.50 0.0005 4.60 0.0015 8.00 0.0025 11.00 11.80 11.80 12.00 16.60 20.00 21.50 19.50 18.50 0.0035 0.0050 0.0080 0.0200 0.0400 0.1000 0.2800 0.4000 0.4600 1 of 1 Part C Determine approximately the ultimate stress. Express your answer to two significant figures and include the appropriate units. Ju = Submit Part D OR= Submit μÅ Value Request Answer Determine approximately the rupture stress. Express your answer to two significant figures and include the appropriate units. Provide Feedback Value [ID] ? Request Answer Units Units ?

A tension test was performed on a steel specimen having an original diameter of 0.503 in. and gauge length of 2.00 in. The data is listed in the table below. (Figure 1) Figure Load (kip) Elongation (in.) 0 0 1.50 0.0005 4.60 0.0015 8.00 11.00 11.80 11.80 12.00 16.60 20.00 21.50 19.50 18.50 0.0025 0.0035 0.0050 0.0080 0.0200 0.0400 0.1000 0.2800 0.4000 0.4600 1 of 1 Part A Determine approximately the modulus of elasticity. Express your answer to two significant figures and include the appropriate units. E = Submit ▾ Part B σy = μA Submit Value Request Answer Determine approximately the yield stress. Express your answer to two significant figures and include the appropriate units. μà Value [IMG] ? Request Answer Units Units www. ?

4. The following data were obtained from a standard tensile stress test on a mild steel specimen. Graph the result and determine proportional limit stress and Young's Modulus. STRESS (Mpa) STRAIN (1 x 104) 69 3.6 138 6.8 207 10.2 276 13.0 345 18.4 414 27.2 462 41.8 552 71.0

A cylindrical specimen of brass that has a diameter of 20 mm, a tensile modulus of 110 GPa, and a Poisson's ratio of 0.35 is pulled in tension with a force of 40, 000 N. If the deformation is totally elastic and the original length is 120 mm, what is the shear modulus. G. of the specimen in GPa? A 20.74 40.74 50.74 30.74

The stress-strain diagram for a steel alloy having an original diameter of 0.80 in. and a gage length of 2 in. is shown in the figure below. (Figure 1) Figure (ksi) 80 70 60 50 40 30 20 10 0 0 0.04 0.08 0.12 0.16 0.20 0.24 0.28 0 0.0005 0.001 0.0015 0.002 0.0025 0.0030.0035 (in./in.) 1 of 1 Part A Determine the modulus of elasticity for the material. Express your answer to three significant figures and include appropriate units. Eapprox= Value Submit Part B Py = Submit Determine the load on the specimen that causes yielding. Express your answer to three significant figures and include appropriate units. Part C Request Answer P₁ = HA Value Request Answer Units Value Units WX ? p Determine the ultimate load the specimen will support. Express your answer to three significant figures and include appropriate units. Units ? ?

A cylindrical specimen of 1018 steel having a diameter of 6.35 mm and a gauge length of 38.1 mm is pulled in tension. Use the load-elongation characteristics tabulated below. Plot the data as engineering stress versus engineering strain .