3.62 A stream of F, G, and H is heated to separate F vapor from G and H liquid.Calculate qheater in kJ/min.F (vapor) T 110.°C20.0 kg/minIheater20.0 wt% F (liq)10.0 wt% G (liq)70.0 wt% H (liq)F (vapor)G (liq)H (liq)liquid-gasseparator110.°Cheater110.°C20.0°C110.°C100. kg/min12.5 wt% G (liq)87.5 wt% H (liq)110.°C80.0 kg/minYou may assume that heating a mixture of F, G, and H is equal to heating F, G,and H separately. Also, you may assume that the parameters in the table below areindependent of temperature.Some properties at 1 atm.Čp (kJ/(kg.°C))Boiling point (°C) Liquid Vapor AĤvap (kJ/kg) AĤfusion (kJ/kg)105.1.601.20380.100.176.2.001.40400.120.Н197.2.401.60420.140.

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Asked Dec 5, 2019
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3.62 A stream of F, G, and H is heated to separate F vapor from G and H liquid.
Calculate qheater in kJ/min.
F (vapor) T 110.°C
20.0 kg/min
Iheater
20.0 wt% F (liq)
10.0 wt% G (liq)
70.0 wt% H (liq)
F (vapor)
G (liq)
H (liq)
liquid-gas
separator
110.°C
heater
110.°C
20.0°C
110.°C
100. kg/min
12.5 wt% G (liq)
87.5 wt% H (liq)
110.°C
80.0 kg/min
You may assume that heating a mixture of F, G, and H is equal to heating F, G,
and H separately. Also, you may assume that the parameters in the table below are
independent of temperature.
Some properties at 1 atm.
Čp (kJ/(kg.°C))
Boiling point (°C) Liquid Vapor AĤvap (kJ/kg) AĤfusion (kJ/kg)
105.
1.60
1.20
380.
100.
176.
2.00
1.40
400.
120.
Н
197.
2.40
1.60
420.
140.
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3.62 A stream of F, G, and H is heated to separate F vapor from G and H liquid. Calculate qheater in kJ/min. F (vapor) T 110.°C 20.0 kg/min Iheater 20.0 wt% F (liq) 10.0 wt% G (liq) 70.0 wt% H (liq) F (vapor) G (liq) H (liq) liquid-gas separator 110.°C heater 110.°C 20.0°C 110.°C 100. kg/min 12.5 wt% G (liq) 87.5 wt% H (liq) 110.°C 80.0 kg/min You may assume that heating a mixture of F, G, and H is equal to heating F, G, and H separately. Also, you may assume that the parameters in the table below are independent of temperature. Some properties at 1 atm. Čp (kJ/(kg.°C)) Boiling point (°C) Liquid Vapor AĤvap (kJ/kg) AĤfusion (kJ/kg) 105. 1.60 1.20 380. 100. 176. 2.00 1.40 400. 120. Н 197. 2.40 1.60 420. 140.

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Expert Answer

Step 1

The basis of the calculation is taken as 100.0 kg/min of the feed entering the heater.

Mass fraction of F, G, and H are:

 

xF = 0.20

xG = 0.10

xH = 0.70

 

Mass flowrate of each of the components (F, G, and H) will thus be,

Note that he mass flowrate of each of the components is same in inlet and outlet to the heater.

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m; = x; ×100 = 0.20×100= 20.0 kg/min mg = xG × 100 = 0.10 ×100 =10.0 kg/min my = xg x100 = 0.70×100 = 70.0 kg/min

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Step 2

Kinetic and potential energy of the system is neglected along with any shaft work which is also neglected. Apply energy balance around the heater as:

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Ireater = AH (1)

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Step 3

Reference temperature, Tref for the given process is taken as 20 ̊C.

For component F, heat of vaporization will be considered as its state changes fr...

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(1.60)đT = 0 kJ/kg Н. in F) piLEdT = ] Iref CledT = [ (2.00)dT = 0 kJ/kg Hgo = н. in G) Clen dT = [° (2.40)đT = 0 kJ/kg I (p(H) ind H)

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