# (a) If 300 lb of air and 24.0 lb of carbon are fed to a reactor at 600 ° and after complete combustion no material remains in the reactor, how many pounds of carbon will have been removed? How many pounds of oxygen? HOW many pounds total?(b) How many moles of carbon and oxygen enter? How many leave the reactor?(c) How many total moles enter the reactor and how many leave the reactor?

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(a) If 300 lb of air and 24.0 lb of carbon are fed to a reactor at 600 ° and after complete combustion no material remains in the reactor, how many pounds of carbon will have been removed? How many pounds of oxygen? HOW many pounds total?
(b) How many moles of carbon and oxygen enter? How many leave the reactor?
(c) How many total moles enter the reactor and how many leave the reactor?

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Step 1

Part (a)

Moles of Carbon fed to the reactor is written as equation (1).

Moles of Air fed to the reactor is written as equation (2).

Percentage of Oxygen present in the air is 0.21%. Thus, moles of Oxygen fed to the reactor is written as equation (3).

Step 2

The reaction that takes place in the reactor is written below. Only Oxygen present in the air reacts with the carbon. Nitrogen does not react.

According to the stoichiometry of the reaction, 1 lb-mol C reacts with 1 lb-mol O2. Thus, 2 lb-mol C reacts  with 2 lb-mol O2. Since, there is complete reaction of Carbon (C) in the reactor, all the carbon is removed from the reactor.

Mass of C removed from the reactor = 24.0 lb

Mass of O2 reacted in the reactor = (2*32) = 64.0 lb

Total mass removed from the reactor = (24+64) = 88.0 lb

Step 3

Part (b)

Moles of C fed to the reactor is, nc = 2 lb-mol

Moles of O2 fed to the reactor is, nO2 = 2.17 lb-mol

Moles of N2 fed to the reactor is, nN2 = 8.17 lb-mol

Since, all the carbon is reacted, no carbon is left in the products.

Moles of C leaving the reac...

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### Chemical Engineering 