5. A DNA sequence of "ACG" will code for the amino acid. (LS1-1) *Second mRNA baseUUCUUAU 1UUUUPheUUCUUGU 1TyrCysUCCSerUCAUACUGCPheGly(G)Leu(F) (L)GluUAA Stop UGA Stop AUUALeuUUGAsp (E)(D)Ser(S)UCGUAG Stop UGG TrpTyrAGUCAla(Y)CAU 1HisCACCUUCCUCGU(A)CGCCCProССАCUCCys (C)LeuArgCGAVal(V)G UCUAСААGlnUTrp (W),CUGCCGCAGCGGArg (R)GACULeuAUUACUAAUAGU(L)AsnSer (S)ACSerAUC IleACCAACAGCC/AThrLys (K)UGAUAACAProAAALysAAGAGAArgAGGAşn(N),(P)AUG Met orstartACGHisThr(H)(T)GlnGUUGCUGAUGGU(Q)lleAspArg(R)(1)GCCAlaGCAGUCGẠCGGCValGUAGlyGGAGAAGluGAGGUGGCGGGGCysThrТyrProIt will not code for an amino acidFirst mRNA base (5' end of codon)Third mRNA base (3' end of codon)

Name: 5. A DNA sequence of "ACG" will code for the amino acid. (LS1-1) *Sec
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Description: 5. A DNA sequence of "ACG" will code for the amino acid. (LS1-1) *Second mRNA baseUUCUUAU 1UUUUPheUUCUUGU 1TyrCysUCCSerUCAUACUGCPheGly(G)Leu(F) (L)GluUAA Stop UGA Stop AUUALeuUUGAsp (E)(D)Ser(S)UCGUAG Stop UGG TrpTyrAGUCAla(Y)CAU 1HisCACCUUCCUCGU(A)

Each codon in mRNA is made up of three nucleotides, and each codon indicates a certain amino acid…

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5. A DNA sequence of "ACG" will code for the amino acid (LS1- 1) * Second mRNA base U UUU Phe UCU UAU Tyr UAC UGU Cys UGC UCC Ser UCA UUC Phe Gly (G) Leu (F) (L) Glu UUA UAA Stop UGA Stop A Asp (E) (D) Ser (S) Tyr (Y) Leu UUG UCG UAG Stop UGG Trp GUC Ala CAU 1 His CAC CUU CCU CGU (A) A A GU CỤC CCC Pro ССА CGC Arg CGA Cys (C) Leu Val (V) CỦA СА Gin CAG G Trp (W) CUG CCG CGG Arg (R) G A C Leu AUU ACU AGU Ser AAC AGC AAU (L) Asn A C Ser (S) AUC Ile ACC Thr ACA C Lys (K) AAA Lys AAG UGA Pro (P) AUA AGA Arg AGG Asn (N) AUG Met or start ACG The (T) His (H) GAU 1 Asp Gln (Q) GUU GCU GGU lle (1) Arg (R) GUC Val GUA GCC Ala GCA GAÇ GGC Gly GGA GAA 7 Glu GUG GCG GAG GGG Сys Thr Тyr Pro It will not code for an amino acid First MRNA base (5' end of codon) Third mRNA base (3' end of codon)

5. A DNA sequence of "ACG" will code for the amino acid (LS1- 1) * Second mRNA base U UUU Phe UCU UAU Tyr UAC UGU Cys UGC UCC Ser UCA UUC Phe Gly (G) Leu (F) (L) Glu UUA UAA Stop UGA Stop A Asp (E) (D) Ser (S) Tyr (Y) Leu UUG UCG UAG Stop UGG Trp GUC Ala CAU 1 His CAC CUU CCU CGU (A) A A GU CỤC CCC Pro ССА CGC Arg CGA Cys (C) Leu Val (V) CỦA СА Gin CAG G Trp (W) CUG CCG CGG Arg (R) G A C Leu AUU ACU AGU Ser AAC AGC AAU (L) Asn A C Ser (S) AUC Ile ACC Thr ACA C Lys (K) AAA Lys AAG UGA Pro (P) AUA AGA Arg AGG Asn (N) AUG Met or start ACG The (T) His (H) GAU 1 Asp Gln (Q) GUU GCU GGU lle (1) Arg (R) GUC Val GUA GCC Ala GCA GAÇ GGC Gly GGA GAA 7 Glu GUG GCG GAG GGG Сys Thr Тyr Pro It will not code for an amino acid First MRNA base (5' end of codon) Third mRNA base (3' end of codon)

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter15: From Dna To Protein

Section: Chapter Questions

Problem 12TYK: Discuss Concepts The normal form of a gene contains the nucleotide sequence: When this gene is...

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