6.00 mL of 5.00 x 10°3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 9.00 mL of 7.00 x 10-3 M KSCN (7.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2*] was found to be 2.00 x 10-3 M (2.00 times 10 to the minus 3rd power M) at equilibrium. How many initial moles of SCN" (SCN minus) are present in the solution? Express your answer as a decimal number (no exponents).

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section17.5: Precipitation Reactions
Problem 17.12CYU: Solid Pbl2 (Ksp = 9.8 109) is placed in a beaker of water. After a period of time, the lead(II)...
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6.00 mL of 5.00 × 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe
(NO3)3) is added to 9.00 mL of 7.00 x 10-3 M KSCN (7.00 times 10 to the minus 3rd
power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was
found to be 2.00 x 10-3 M (2.00 times 10 to the minus 3rd power M) at equilibrium.
How many initial moles of SCN" (SCN minus) are present in the solution? Express
your answer as a decimal number (no exponents).
Your Answer:
Answer
units
Transcribed Image Text:6.00 mL of 5.00 × 10-3 M Fe(NO3)3 (5.00 times 10 to the minus 3rd power M Fe (NO3)3) is added to 9.00 mL of 7.00 x 10-3 M KSCN (7.00 times 10 to the minus 3rd power M KSCN) along with 7.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-3 M (2.00 times 10 to the minus 3rd power M) at equilibrium. How many initial moles of SCN" (SCN minus) are present in the solution? Express your answer as a decimal number (no exponents). Your Answer: Answer units
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