Answer the following: DNA fragment A is 3' AGC CCG CTC CGA GGC TAA AAG CGT 5' 1. is % of guanine in DNA fragment A 2. is the 4th codon in the complement of DNA fragment A from the 5' end 3. is the 3rd codon in the mRNA copied from DNA fragment A from the 3' end 4. is the N-terminal amino acid of the peptide produced 5. is the C-terminal amino acid of the peptide produced
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Answer the following:
DNA fragment A is 3' AGC CCG CTC CGA GGC TAA AAG CGT 5'
1. is % of guanine in DNA fragment A
2. is the 4th codon in the complement of DNA fragment A from the 5' end
3. is the 3rd codon in the mRNA copied from DNA fragment A from the 3' end
4. is the N-terminal amino acid of the peptide produced
5. is the C-terminal amino acid of the peptide produced
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- Using Figures 8.7 and 8.9 as a guide, draw a dinucleotide composed of C and A. Next to this, draw the complementary dinucleotide in an antiparallel fashion. Connect the dinucleotides with the appropriate hydrogen bonds. FIGURE 8.9 The two polynucleotide chains in DNA run in opposite directions. The left strand runs 5 to 3, and the right strand runs 3 to 5. The base sequences in each strand are complementary. An A in one strand pairs with a T in the other strand, and a C in one strand is paired with a G in the opposite strand. FIGURE 8.7 Nucleotides can be joined together to form chains caled polynucleotides. Polynucleotides are polar molecules with a 5 end (at the phosphate group) and a 3 end (at the sugar group). An RNA polynucleotide is shown at the left, and a DNA polynucleotide is shown at the right.Answer the ff. DNA fragment A is 3' AGC CCG CTC CGA GGC TAA AAG CGT 5' A. is the 3rd amino acid in the peptide produced from the N-terminal B. is the 2nd amino acid in the peptide produced from the C-terminal C. is the anticodon present in the tRNA that carried the 5th amino acid from the N-terminal D. is the anticodon present in the tRNA that carried the 3rd amino acid from the C-terminal E. is the % of adenine in the DNA complement of DNA fragment AAnswer the following whether it is TRUE or FALSE: 1. For each DNA segment 3'-ACCTGCCTACCCG-5' the sequence of the mRNA molecule synthesized is 5'-TGGACGGATGGGC-3' 2. In the template strand TACCGAGGTATGTAC, the coding strand is 5'-ATGGCTCCATACATG-3'. 3. In the template strand TACCGAGGTATGTAC, the coding strand is 5'-AUGGCUCCAUACAUG-3'. 4. The template strand is the strand of DNA used for RNA synthesis. 5. Transcription forms a messenger RNA molecule with a sequence that is identical to the DNA template from which it is prepared.
- Examine the following sequence of DNA3’-CTA – TAC – TTA – CGC – GTA – CAT – GCG – TGA – CCC - ACG – ACT – AGG-5’Write out the complementary DNA sequence (identify 3’ and 5’ ends)Write out the complementary mRNA sequenceWrite out the peptide sequence this DNA encodesThe following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all groups and translate. FIND THE POSSIBLE MUTATIONS Group D 5’-GGCAATGGGTTTGTGCAATTCTAACAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTGTCAAAAATTAAG-5’ Group E 5’-GGCAATGGGTTTTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAAACGTTAAGATTTTCAAAAATTAAGAnswer the following questions. A) Write the protein that catalyzes the formation of phosphodiester bonds. B) Write the protein that breaks the covalent bonds. C) A mutated strain of E. coli normally replicates DNA at 25ºC, but replication immediately stops when the temperature is raised to 37ºC. Which protein is functional at higher temperature? Probably not, please write. D) Write down the enzyme that catalyzes the binding of an amino acid to tRNA in the formation of aminoacyl tRNA. E) Write down the enzyme that is mostly responsible for the synthesis of the chain that begins to form during DNA replication in E. coli
- Define the following terms:a. DNAb. RNAc. double helixd. genomee. transcription5’-GTCGTATAGTGA-3’ 3’-CAGCATATCACT-5’ if this is the dna sequence is the RNA sequence this 3’-GTCGTATAGTGA-5’, give reason if it not correctGive the corresponding strand of the DNA having the sequence of:a. 5’ ATGGCTAGGATCGGTAACTGCGATCGATCAGCATGACTAG-3’b. 3’ TACCAGGATAATTCGAGGTACTACGACTAGGAT-5’c. 5’ AACATGATCTGGTCCATTAGCTTGTTCAATAATTAGC-3’
- The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all groups and translate. FIND THE POSSIBLE MUTATIONS Group B - MUTATION 5’-GGCAATGGGTTTGTGAAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACTTTAAGATTTTCAAAAATTAAG-5’ Group C- 5’-GGCAATGGGTTTGTGCAATTCTAAGAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTCTCAAAAATTAAG-5’Given Sequence: 3’-TACGGTCCGGATTCGGTAGCTAGCATC-5’ Provide: Complementary Strand: Transcript Amino Acid Sequence 2.Given Sequence: 5’-GGGCATATGCCGTTTACCGGTTTGACTAAATAACCA-3’ Provide: Complementary Strand: Transcript Amino Acid Sequence 3.Given Sequence: 3’-AAC CAA TAC GTG AGG ATA CCA AGT AAC ACT CCC-5’ Provide: Complementary Strand: Direct Transcript: Transcript for Translation: Amino Acid Sequence:The following are DNA fragments containing a small gene. The top strand is the coding strand. Transcribe all 5 groups and translate. Group A 5’-GGCAATGGGTTTGTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTTTCAAAAATTAAG-5’ Group B 5’-GGCAATGGGTTTGTGAAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACTTTAAGATTTTCAAAAATTAAG-5’ Group C 5’-GGCAATGGGTTTGTGCAATTCTAAGAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTCTCAAAAATTAAG-5’ Group D 5’-GGCAATGGGTTTGTGCAATTCTAACAGTTTTTAATTC-3’ 3’-CCGTTACCCAAACACGTTAAGATTGTCAAAAATTAAG-5’ Group E 5’-GGCAATGGGTTTTGCAATTCTAAAAGTTTTTAATTC-3’ 3’-CCGTTACCCAAAACGTTAAGATTTTCAAAAATTAAG