Question
Asked Nov 18, 2019
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Expert Answer

Step 1

The rate law formula for the nth order of reaction is 

1
1
(n-1)kt
A [A
n-1
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1 1 (n-1)kt A [A n-1

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Step 2

given data as follow:

rate of reaction
3rd order
the initial concentration [A,] = 0.067 mol dm
the final concentration[A,] 0.015 mol dm
-3
K 6.50 x10 dm'mols
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rate of reaction 3rd order the initial concentration [A,] = 0.067 mol dm the final concentration[A,] 0.015 mol dm -3 K 6.50 x10 dm'mols

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Step 3

Therefore, rate law of 3rd orde...

1
1
(3-1)kt
[A]
3-1
[A
3-1
0
1
t:
|[A] [AJ
1
1
1
2x6.50 x10
2
dm°mol^s(0.015 mol dm3
(0.067 mol dm
t 324.7255x10 sec
= 3247255 sec
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1 1 (3-1)kt [A] 3-1 [A 3-1 0 1 t: |[A] [AJ 1 1 1 2x6.50 x10 2 dm°mol^s(0.015 mol dm3 (0.067 mol dm t 324.7255x10 sec = 3247255 sec

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