Consider the below java code: import java.io.*; public class Main { public static void main(String[] args) { int values[] = { 20, 30, 40, 60, 70, 80, 90, 100 }; try (Random AccessFile file = new RandomAccessFile ("integersText.dat", "rw")) { int k; for (int i = 0; i < values.length; i++) { file.writeInt (values[i]); } file.seek (0); k file.readInt (); System.out.println (k); file.seek (4); k file.readInt (); System.out.println (k); for (int i = 0; i < values.length; i+= 2) { file.seek (81) } k file.readInt (); System.out.printf("%d ", k); System.out.println(); } catch (IOException e) { System.out.println("An IO Exception is caught!"); } finally ( System.out.println("File access done successfully."); } When the above code is executed, what output is generated?

Find error  #include<bits/stdc++.h> using namespace std; class Solution{     public:     bool isPossible(vector<int>ank,int n,int mid)    {        int count=0;        for(int i=0;i<rank.size())        {            int val= (-1 + sqrt(1+(8*mid)/rank[i]))/2;             count+=val;         }                return count>=n;     }    int findMinTime(int N, vector<int>&A, int L){        int low=*min_element(A.end()),high=1000000;        int ans=high;        while(low<=high)        {            int mid=low+(high)/2;                        if(isPossible(A,mid))            {                ans=mid;                 high=mid;             }            else            low=mid;         }        return ans;    } };   int main() {  int t;  cin>>t;  while(t--)  {      int l;      cin >> l;      vector<int>arr(l);      for(int i = 0; i < l; i++){          cin >> arr[i];      }      Solution ob;      int ans = ob.findMin(n, *arr, l);      cout…

Correct my codes in java // Arraysimport java.util.Scanner;public class Assignment1 {public static void main (String args[]){Scanner sc=new Scanner (System.in);System.out.println("Enter mark of student");int n=sc.nextInt();int a[]=new int [n];int i;for(i=0;i<n;i++){System.out.println("Total marks of student in smster");a[i]=sc.nextInt();}int sum=0;for(i=0;i<n;i++){sum=sum+a[i];}System.out.println("Total marks is :");for (i=0;i<n;i++);{System.out.println(a[i]);}System.out.println();}}

public class arrayOutput ( public static void main (String [] args) { final int NUM ELEMENTS = 3; int[] userVals = new int [NUM_ELEMENTS]; int i; } Type the program's output userVals [0] = 2; userVals [1] = 6; userVals [2] = 8; for (i = userVals.length - 1; i >= 0; −−1) { System.out.println(userVals [1]); } C.C. ? ? ??

JAVA Language:  Transpose Rotate.  Question:  Modify Transpose.encode() so that it uses a rotation instead of a reversal. That is, a word like “hello” should be encoded as “ohell” with a rotation of one character. (Hint: use a loop to append the letters into a new string)         import java.util.*;            public class TestTranspose {        public static void main(String[] args) {          String plain = "this is the secret message";   // Here's the message           Transpose transpose = new Transpose();          String secret = transpose.encrypt(plain);          System.out.println("\n ********* Transpose Cipher Encryption *********");          System.out.println("PlainText: " + plain);    // Display the results          System.out.println("Encrypted: " + secret);          System.out.println("Decrypted: " + transpose.decrypt(secret));// Decrypt        }      }            abstract class Cipher {        public String encrypt(String s) {          StringBuffer result = new…

JavaTimer.java: import java.util.Arrays;import java.util.Random; public class JavaTimer { // Please expand method main() to meet the requirements.// You have the following sorting methods available:// insertionSort(int[] a);// selectionSort(int[] a);// mergeSort(int[] a);// quickSort(int[] a);// The array will be in sorted order after the routines are called!// Be sure to re-randomize the array after each sort.public static void main(String[] args) {// Create and initialize arraysint[] a = {1, 3, 5}, b, c, d;// Check the time to sort array along startTime = System.nanoTime();quickSort(a);long endTime = System.nanoTime();long duration = (endTime - startTime) / 1000l;// Output resultsSystem.out.println("Working on an array of length " + a.length + ".");System.out.println("Quick sort: " + duration + "us.");}// Thanks to https://www.javatpoint.com/insertion-sort-in-javapublic static void insertionSort(int array[]) {int n = array.length;for (int j = 1; j < n; j++) {int key = array[j];int…

import java.util.Scanner; public class LabProgram {    public static void main(String[] args) {        Scanner scnr = new Scanner(System.in);         int n = scnr.nextInt();        int[] arr = new int[n];         for (int i = 0; i < n; i++) {            arr[i] = scnr.nextInt();        }         for (int i = n - 1; i >= 0; i--) {            System.out.print(arr[i]);             if (i > 0) {                System.out.print(",");            }        }    }}