Consider the circuit shown in Fig. Q.4. The value ofR= 3.6 N, L =12.68 mH, Vdc= 12V and the sourcevoltage is given by the expression as below: vs (t) =29 + 25 sin ( wit) + 10 sin ( w2t) V Fig. Q. 4 Where,w1= 360 t, and w2= 480 t Determine: a. Averageload current b. RMS value of the load current c.Power dissipated inside the inductor d. Powerdissipated inside the resistor e. Power absorbed bythe dc sourceVsVácFig. Q. 4

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Consider the circuit shown in Fig. Q.4. The value of R= 3.6 N, L =12.68 mH, Vdc= 12V and the source voltage is given by the expression as below: vs (t) = 29 + 25 sin ( w1t) + 10 sin ( w2t) V Fig. Q. 4 Where, w1= 360 Tt, and w2= 480 r Determine: a. Average load current b. RMS value of the load current c. Power dissipated inside the inductor d. Power dissipated inside the resistor e. Power absorbed by the dc source Vs Vác Fig. Q. 4

Consider the circuit shown in Fig. Q.4. The value of R= 3.6 N, L =12.68 mH, Vdc= 12V and the source voltage is given by the expression as below: vs (t) = 29 + 25 sin ( w1t) + 10 sin ( w2t) V Fig. Q. 4 Where, w1= 360 Tt, and w2= 480 r Determine: a. Average load current b. RMS value of the load current c. Power dissipated inside the inductor d. Power dissipated inside the resistor e. Power absorbed by the dc source Vs Vác Fig. Q. 4

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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