Consider the combustion of one mole of methane gas:CH4(gas) + 2O2(gas) --> CO2 (gas) + 2H2O(gas).The system is at standard temperature (298 K) and pressure (105 Pa) both before and after the reaction. 1.) First imagine the process of converting a mole of methane into its elemental consituents (graphite and hydrogen gas). Use the data at the back of this book to find ΔH for this process. 2.) Now imagine forming a mole of CO2 and two moles of water vapor from their elemental constituents. Determine ΔH for this process.     Question: What is the change in the system's energy during this reaction? How would your answer differ if the H2O ended up as liquid water instead of vapor?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Consider the combustion of one mole of methane gas:
CH4(gas) + 2O2(gas) --> CO2 (gas) + 2H2O(gas).
The system is at standard temperature (298 K) and pressure (105 Pa) both before and after the reaction.

1.) First imagine the process of converting a mole of methane into its elemental consituents (graphite and hydrogen gas). Use the data at the back of this book to find ΔH for this process.

2.) Now imagine forming a mole of CO2 and two moles of water vapor from their elemental constituents. Determine ΔH for this process.

 

 

Question: What is the change in the system's energy during this reaction? How would your answer differ if the H2O ended up as liquid water instead of vapor?

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