Consider the setting of Exercise 1. The residuals corresponding to the LSQ line, HR = 133.72 – 280.8 BA, are he graph below. Residuals Versus the Order of the Data (response is HR) 30 20 10
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- A manufacturer producing cocacola drinks wanted to set the specification of production to achieve process capability. He set his Upper Control Limit (UCL) = 0.03, proportion of defective items as 0.02. Calculate the number of sample observations (n) to be used to ensure 99.74 of the value.A worker with a weight of 65 kg and a body surface area of 1.74 , performs physical work activities in several work environments as shown in the following table. The work activities of these workers require energy and a measured metabolic rate of 400 W/m2. During their work activities, the worker wears a coverall made of polyolefin and wears a headgear (1) Calculate the average WBGT of the work environment. (2) Perform an analysis related to the heat stress experienced by the worker, if the worker performs his work activities for 75% of his total working time and the rest is rest, (note: use TLV from ACGIH and ISO 7243)In response to concerns about nutritional contents of fast foods, McDonald’s announced that it would use a new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s. If it turns out that 65 individuals in the sample can taste the difference between the two oils, would you question McDonald’s claim? Explain why or why not.
- In response to concerns about nutritional contents of fast foods, McDonald’s announced that it would use a new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s Find the Distribution of X.In response to concerns about the nutritional contents of fast foods, McDonald’s announced that it would use new cooking oil for its french fries that would decrease substantially trans fatty acid levels and increase the amount of more beneficial poly-unsaturated fat. The company claimed that 97 out of 100 people cannot detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion). Let X denote the number of individuals who can taste the difference between the two oils in a random sample of 1000 individuals who have purchased fries at McDonald’s. Use the normal approximation with continuity correction to find the probability that at most 5% can taste the difference between the two oils.A survey of 28 employed workers found that the correlation coefficient between the number of years of post-secondary education and current annual income in dollars is -0.38. The researchers hypothesize a positive relationship between number of years of post-secondary education and annual income. What can the researchers conclude with α = 0.05? a) Obtain/compute the appropriate values to make a decision about H0. critical value= test statistic= b) effect size= C) 1)There is a significant positive relationship between years of post-secondary education and current annual income. 2)There is a significant negative relationship between years of post-secondary education and current annual income. 3) There is no significant relationship between years of post-secondary education and current annual income.
- A tax accountant would like to test the claim that the proportion of individuals who owe when filing their taxes is less than 0.20. If the z− test statistic was calculated as z=−2.11, does the tax accountant have enough evidence to reject the null hypothesis? Assume α=0.005. Move the blue dot to choose the appropriate test (left-, right, or two-tailed). Then, use the graph below to show the test statistic, p-value, and the rejection region to make a conclusion about the hypothesis test. powered by Move the blue dot to choose the appropriate test α=0.01 α=0.025 α=0.05 α=0.1 Significance level = 0.01 Select the correct answer below: There is enough evidence to suggest the proportion of individuals who owe when filing their taxes is less than 0.20. There is not enough evidence to suggest the proportion of individuals who owe when filing their taxes is less than 0.20. There is enough evidence to suggest the proportion of individuals who owe when filing their taxes is greater than 0.20.…a sample of 4 students was taken and information about daily pocket money in tl (Y) and spending in tl (x) was collectedA series of tests of fire prevention sprinkler systems that use a foaming agent to quell the fire were performed to determine how long it took (in seconds) for the sprinklers to be activated after the detection of a fire by the system. The system has been designed so that the true average activation time is supposed to be at most 25 seconds. Do the data strongly indicate that the design specifications have not been met? The data for the test are given below: 27 41 22 27 23 35 30 33 24 27 28 22 24
- A researcher interested in exercise endurance in older adults with coronary heart disease measured the endurance of 450 older adults during an exercise routine on a scale of 0-10. He obtained a mean (SD) rating of 6.2 (3.4). Compute the 85% C. I: _____________.In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1197 and the standard deviation was 164.9. Further research suggests that the population mean score on this test for high school seniors is 1022. Does the t-value for the original sample fall between - to 95 and to o5? Assume that the population of test scores for high school seniors is normally distributed. The t-value of t= V fall between - to 95 and to 95 because to g5 =. (Round to two decimal places as needed.)Here sample 10 people in a high school to try to predict GPA in 10th grade from GPA in 9th grade. here determine that SSE = 5.8. Compute the standard error of the estimate?