D-glucose C6H1206 (Mass of molecular ion: 180) 100 MS-NU-9127 80- 60 40 25 50 75 100 12 m/z Source Temperature: 200 °C Sample Temperature: 140 °C Direct, 75 ev Relative Intensity 20
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- the % retention of the unnatural base pair drops from 100% to ~50% over the course of 75 hours after an initial pulse of unnatural dNTPs. Suggest at least two mechanistic explanations for the lack of retention – four sentences max.The maximum safe [Ba2+]=1.5x10-5M. Maintaining 1.0x10-3M levels for each of the anions below would ensure that this level is achieved except (Ksp of BaF2=1.7x10-6, BaCO3=5.9x10-9, BaC2O4=7.4x10-14, and BaSO4=1.1x10-10) A SO42- B C2O42+ C CO32- D F-Can someone explain and number 1,2,3,4,5 etc how the attached is a [1,5] sigmatropic migration?
- Please determine Hvap using these: P2- 3.7kpaP1- 19.2kpa T2-276.65KT1-330.15KBased on the chromatograms, Symmetry C18 (top) is less selective than Symmetry Shield RP18 (bottom) for the analytes given, true or false?For a tungsten carbene (catalyst) binding to THF (ligand) at 25 oC in per-deuterotoluene solvent, the chemical shift of the unbound catalyst alpha hydrogen was determined to be 794.6 Hz and the peak for the fully bound catalyst alpha hydrogen was observed at 842.4 Hz. Furthermore, the binding constant (or formation constant) Kf was found to be 15.40 M-1. Given the following initial concentrations of catalyst and ligand, calculate the percent THF bound you would expect to see at 25 oC. Record your answer to the nearest tenths of a percent, as a number with no units (Ex. 3.4% ----> enter "3.4") Co = 1.000 M Lo = 0.1000 M
- INORGANIC Chemistry Starting product was [(Me5dien)CoCl2] and reacted with NaSCN to produce [(Me5dien)Co(SCN)2] Using the graphs attached, the IR data tells you that the binding mode is N coordination. How does the IR data agree (or disagree) with the peak shifts (Uv-Vis spect) IR Product 1, [(Me5dien)CoCl2] 29041.04, 2812.76, 2761.62 cm-1 (carbon bond) 1457.35 cm-1 (CH2) 1263.91 cm-1 (possibly C-N stretch) Product 2, [(Me5dien)Co(SCN)2] 2968.54-2870.67 cm-1 (C-C) 2059.41 cm-1 (N=C=S) 1470.28 cm-1 (CH2) Uv-vis [(Me5dien)CoCl2] Peak A: 531.8 nm, 0.722 Abs Peak B: 609.7 nm, 0.666 Abs [(Me5dien)Co(SCN)2] Peak A: 510.20 nm, 0.357 Abs Peak B: 608.20 nm, 0.401 AbsCould someone explain what this is saying? I would like a better understanding. FIGURE D CPP32 (Caspase-3) protease activity. Aliquots of cell lysates (50μL) were incubated with an equal volume (50 μL) of the reactionbuffer and 5 μL of 7-amino-4-trifluoromethyl coumarin (AFCDEVD) for 1 hour at 37˚C (Clontech). The shift in fluorescenceemission of AFC-DEVD, on its proteolysis to free AFC by theprotease, was detected in a fluorometer, using a 400 nm excitationfilter and 505 nm emission filter.Give one advantage of the proposed HPLC identification test over the current UV-Visible Spectroscopy method of Amiloride Hydrochloride.
- Is the product pure? how do you know? here is the results: Starting mass of benzyl 1.0883g Collected mass of product 0.8957g Product melting point 135˚C Mixture melting point (product mixed with benzoin) 114˚C Mixture melting point (product mixed with meso-hydrobenzoin) 135˚CA protein consists of two types of peptide chains (A and B) with an unknown stoichiometry (AxBy). When you ran this protein directly on reversed phase-HPLC with UV monitor set at 280 nm, two peaks were resolved. Mass spec determined that the peaks represented Chain A and Chain B, respectively. The peak area is 500,000 for Peak A (Chain A) and 100,000 for Peak B (Chain B). The molecular masses of Chain A and Chain B are 25,000 and 5000, respectively. The extinction coefficients for Chain A and Chain B are 1 mL/mg.cm and 0.5 mL/mg.cm, respectively. Please calculate x/y.The time taken for the unretained species was 0.5 min.a) Calculate the capacity factor (k') for compound X and compound Z.b) Determine the resolution (Rs) of compound Y and Z.
