Digestion of a DNA sample with Decll, which is a “4-cutter" enzyme that produces blunt (rather than "sticky") ends, generated numerous DNA fragments, including a 15 bp piece whose sequence is indicated below (note that only one of the DNA strands is specified). 5' TCTGAATTCCGTAGA 3' Based on this information, the recognition sequence for the Decll enzyme must be 5' 3'. [specify using single letters]

Digestion of a DNA sample with Decll, which is a “4-cutter" enzyme that produces blunt (rather than "sticky") ends, generated numerous DNA fragments, including a 15 bp piece whose sequence is indicated below (note that only one of the DNA strands is specified). 5' TCTGAATTCCGTAGA 3' Based on this information, the recognition sequence for the Decll enzyme must be 5' 3'. [specify using single letters]

Biochemistry

6th Edition

ISBN:9781305577206

Author:Reginald H. Garrett, Charles M. Grisham

Publisher:Reginald H. Garrett, Charles M. Grisham

Chapter29: Transcription And The Regulation Of Gene Expression

Section: Chapter Questions

Problem 5P

See similar textbooks

Similar questions

Heteroduplex DNA Formation in Recombination From the information in Figures 28.17 and 28.18, diagram the recombinational event leading to the formation of a heteroduplex DNA region within a bacteriophage chromosome.
Functional Consequences of Y-Family DNA Polymerase Structure The eukaryotic translesion DNA polymerases fall into the Y family of DNA polymerases. Structural studies reveal that their fingers and thumb domains are small and stubby (see Figure 28.10). In addition, Y-family polymerase active sites are more open and less constrained where base pairing leads to selection of a dNTP substrate for the polymerase reaction. Discuss the relevance of these structural differences. Would you expect Y-family polymerases to have 3-exonuclease activity? Explain your answer.
Homologous Recombination, Heteroduplex DNA, and Mismatch Repair Homologous recombination in E. coli leads to the formation of regions of heteroduplex DNA. By definition, such regions contain mismatched bases. Why doesnâ€™t the mismatch repair system of E. coli eliminate these mismatches?
Agarose gels with different average pore sizes areneeded to separate DNA molecules of different sizeclasses. For example, optimal separation of 1100 bpand 1200 bp fragments would require a gel with alarger average pore size than optimal separation of8500 bp and 8600 bp fragments. How do you thinkthat scientists prepare gels of different average poresizes? (Hint: Agarose gels are made in a mannersimilar to gelatin desserts such as JELL-O.)
Indicate the size in kilobases (kb) of DNA fragment(s) that you would expect to see if you cut a circular plasmid with BamHI recognition sites are at positions 2000bp and 3000bp and the plasmid if 5500bp total?
The restriction endonuclease PstI cuts DNA symmetrically on both strands at the sequence: CTGCAG GACGTC On the resulting DNA fragments are left 3’ overhanging ends of 4 nucleotides. PstI cleavesthe phosphodiester backbone with a-type specificity. In short-hand notation, showing theidentity of phosphates on the ends, draw the two fragments that result from PstI digestion ofthe following double-strand ed oligonucleotide: 5’-pAATTGCTACTGCAGAACCGG-3’ 3’-TTAACGATGACGTCTTGGCCp-5’
In the Sanger (dideoxy) method for DNA sequencing, a small amount of a dideoxynucleoside triphosphate—say, ddCTP—is added to the sequencing reaction along with a larger amount of the corresponding dCTP. What resultwould be observed if the dCTP were omitted?
Not just generic "degradation" or even shorter DNA fragments, what specific structure change in double-stranded DNA does the hyperchromicity effect show?
What two basepair changes can occur when G tautomerizes to the enol form? Recall that the tautomerization can occur when G is a free dNTP prior to DNA replication or when G is incorporated into dsDNA just before DNA replication. Draw both of these bp changes out. Are they transitions or transversions?
DNA photolyases convert the energy of light in the nearultraviolet or visible region (300– 500 nm) into chemical energy to break the cyclobutane ring of pyrimidine dimers. In the absence of substrate, these photoreactivating enzymes do not absorb light of wavelengths longer than 300 nm. Why is the substrateinduced absorption band advantageous?
Biochemist Erwin Chargaff was the first to note that, in DNA, [A] = [T] and [G]= [C], equalities now called Chargaff’s rule. Using this rule, determine the percentages of all the bases in DNA that is 20% thymine.
Ethanol (CH3-CH2-OH) is miscible in water because it is able to form hydrogen bonds with itself and other molecules. However, its structure only allows it to form 1-2 hydrogen bonds. This is one reason why even low concentrations of ethanol in solution are lethal for cells. Based on this information, explain why we can use high concentrations of ethanol to precipitate DNA out of solution. Also, describe/predict the effects of increasing concentrations of ethanol in (and around) a cell on macro-molecular interactions (i.e. on weak bonds). Finally, it is possible to select for yeast that are tolerant to increased concentrations of ethanol. Give an example of a physiological change in yeast cells that might make them resistant to ethanol.