Could you help solve this ? EXERCISEUnit ConversionDrag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on aunit to remove it from its position.1 cm³ Cu9 g Cu9.5 x 1021 atoms Cu1g Cu%D1 kg1000 g1 cm31 mL1 L1000 cm³amount=840,units=kg,targetUnits=Lamount=80,units=g,targetUnits=atomsamount=480000000,units=atoms,targetUnits=LA piece of copper has a mass of 840 kg. What is the volume of the sample, in units of liters?In the boxes above, enter the correct setup that would be used to solve this problem.int unit convers_t 0_0Submit

Answered: Image /qna-images/answer/01272b2f-5333-4297-ba0d-16a0cccd1603.jpg

EXERCISE Unit Conversion Drag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on a unit to remove it from its position. 1 cm Cu 9 g Cu 9.5 x 1021 1 g Cu atoms Cu 1 kg 1000 g 1 cm 1 mL 1L 1000 cm3 amount-840,units=kg,targetUnits=L amount=80,units-g,targetUnits-atoms amount=480000000,units=atoms,targetUnits=L A piece of copper has a mass of 840 kg. What is the volume of the sample, in units of liters? In the boxes above, enter the correct setup that would be used to solve this problem.

EXERCISE Unit Conversion Drag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on a unit to remove it from its position. 1 cm Cu 9 g Cu 9.5 x 1021 1 g Cu atoms Cu 1 kg 1000 g 1 cm 1 mL 1L 1000 cm3 amount-840,units=kg,targetUnits=L amount=80,units-g,targetUnits-atoms amount=480000000,units=atoms,targetUnits=L A piece of copper has a mass of 840 kg. What is the volume of the sample, in units of liters? In the boxes above, enter the correct setup that would be used to solve this problem.

General Chemistry - Standalone book (MindTap Course List)

11th Edition

ISBN:9781305580343

Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

Chapter3: Calculations With Chemical Formulas And Equaitons

Section3.4: Elemental Analysis: Percentages Of Carbon, Hydrogen And Oxygen

Problem 3.2CC

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A compound is 27.29% carbon by mass and the remainder is oxygen. If the molecular mass of the compound is 88.02 amu, what is the molecular formula of the compound? Relative atomic masses: C = 12.011; O = 15.999 Input answer following the format for aluminum sulfide, Al2S3:Al2S3 Answer: ?
A lab scenario determined that a sample was 75.42 g C, 6.64g H, 8.38g N and 9.56g O. The molecular mass of the compound is 334.45 grams. What is the molecular formula of the molecule? Show all work! subscript on the C subscript on the H subscript on the N subscript on the O Blank 1: Blank 2: Blank 3: Blank 4:
Multiple Choice: How many atoms of carbon-14 are in the average human body given the following four facts: 1. Carbon makes up 23% of the human body by weight. 2. The average human body has a mass of 150 kg. 3. There are approximately 83 moles in every kg of carbon. 4. One in every trillion atoms of carbon is carbon-14. a. 1,89 X 10 (exponent 15) b. 1,72 X 10 (exponent 15) c. 1,89 X 10 (exponent 16) d. 1,72 X 10 (exponent 16)
Show work using conversion factors Answer Key:#37a CaCO3 + 2HCl --> CaCl2 + H2O + CO2 #37b 36.46 g/mol HCl #37c 100.09 g/mol CaCO3 #37d 1.250 moles CO2 #37e 4.92 mole HCl #37f 7.1422 moles HCl ( fixed 10/14/2020) #37g 143 g CO2
Practice Exercise 2The density of the organic compound benzene is 0.879 g/mL.Calculate the mass in grams of 1.00 qt of benzene.
Data Trial 1 Trial 2 Mass of empty crucible with lid 26.698g 26.687g Mass of Mg metal, crucible, and lid 27.060g 27.046g Mass of MgO, crucible, and lid 27.291g 27.273g Determine the average percent yield of MgO for the two trials. ( I average the percent yield of the two trials) 98.55% (Just write out how you got it)
so the questions are answer but I have some questions so how they got 2I- and how they got 2.22x10-8 in the bottom like I want to know the process of finding 2.22x10-8? so How they knew to put H2O on both side and CN-and the math process to find o.6 and how they got 1.929x10-5?
1. How many milliliters of 53.40(±0.06) (w/w) % NaOH with a density of 1.52(±0.01)g/mL will you need to prepare 1.000 L of 0.200 M NaOH? Keep 1 extra sig fig in your answer (4). 2. If the uncertainty in delivering NaOH is ±0.01 mL, calculate the absolute uncertainty in molarity (0.200 M). Assume there is negligible uncertainty in the formula mass of NaOH and in the final volume (1.000 L) Hint: You will need to calculate the molarity of the 53.40% NaOH. One way to solve this is to assume that you have 100.00 grams of the initial NaOH solution. Determine how many grams are NaOH. Convert that value to moles NaOH. Using the density, determine the volume of your 100.00 grams of solution.
Balancing equation: HCl + KMnO4 ==> KCl + MnCl2 + H2O + Cl2 CuSCN + KIO3+ HCl ==> CuSO4 + KCl + HCN + ICl + H2O HIO3 + FeI2 + HCl ==> FeCl3 + ICl + H2O
Methane CHis a simple organic molecule that is used as a fuel—it is the major component of natural gas. The bottom of the ocean contains large amounts of methane hydrate (also called methane ice or methane clathrate), enough that it has been suggested as a major source of fuel. The methane hydrate contains 6 moles water for each mole of methane.What percentage of methane hydrate is methane? blank1 - Numeric Answer % What percentage is water? blank2 - Numeric Answer %
Trial 1 Trial 2 Trial 3 Vinegar Volume (mL) 5.00 5.00 5.00 Final buret reading of NaOH(mL) 42.60 42.00 41.90 Initial buret reading of NaOH(mL) 3.70 3.10 2.98 Volume of NaOH dispensed (mL) Average volume of NaOH in liters (L): Average moles of NaOH (mol NaOH): Average moles of acetic acid (mol CH3COOH): Average molarity of acetic acid (M): Average mass of acetic acid (g CH3COOH): Average mass of vinegar (g): % (m/m) CH3COOH in vinegar:
Equation: M1V1=M2V2

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General Chemistry - Standalone book (MindTap Cour…

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ISBN:

9781305580343

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Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell

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Cengage Learning