NaOH is the base(please elaborate) Thank you! Measure|Sample 1Sample 2 Sample 3 Sample 4Mass of unknown acid1-D000g1-OD0og1- ODOD91-OD0ogFinal buret reading7.68 mL13-46ML19.34 mL | 25.52mL2 mL7.68 mL13-46ML19.34 mLInitial buret readingS.68 mLS.78ML5.88 mLS.98 mLVolume of base usedMolarity of base1-00 M1-00 M1-00 M1.00 MMoles of baseMoles of acid'Molar mass of acid?1Consider the molar ratio between the unknown acid and NaOH in the balanced equation2moles = grams/molar massAverage molar mass:(show calculation)List 2 possible errors and what effect they would have on your final answer.

Calculation; *Moles of base = molarity of base/volume (in L) For sample 1; Moles of base = 1…

Measure |Sample 1Sample 2 Sample 3 Sample 4 Mass of unknown acid 1-D000g 1-OD0og 1- 000og | 1-0000g Final buret reading 7.68 mL 13-46ML 19.34 mL | 25.52mL 2 mL 7.68mL 13-46mL 19.34 mL Initial buret reading Volume of base used S.68 mL S.78ML S.88 mL 5.98 mL Molarity of base 1-00 M 1-00 M 1-00 M 1.00 M Moles of base Moles of acid' Molar mass of acid? 1 Consider the molar ratio between the unknown acid and NaOH in the balanced equation 2 moles = grams/molar mass Average molar mass: (show calculation)

Measure |Sample 1Sample 2 Sample 3 Sample 4 Mass of unknown acid 1-D000g 1-OD0og 1- 000og | 1-0000g Final buret reading 7.68 mL 13-46ML 19.34 mL | 25.52mL 2 mL 7.68mL 13-46mL 19.34 mL Initial buret reading Volume of base used S.68 mL S.78ML S.88 mL 5.98 mL Molarity of base 1-00 M 1-00 M 1-00 M 1.00 M Moles of base Moles of acid' Molar mass of acid? 1 Consider the molar ratio between the unknown acid and NaOH in the balanced equation 2 moles = grams/molar mass Average molar mass: (show calculation)

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter14: Chromatography

Section: Chapter Questions

Problem 9P

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