reparation of 0.25N NaOH Objective: Apparatus and Materials: Procedure : Calculate the exact mass of NaOH needed to prepare 1.0L of 0.25N NaOH for standardization. Show your computations. Using the triple beam balance, weigh the desired amount of NaOH. Place the weighed amount of NaOH into the 500 mL volumetric flask and add distilled water until it reaches the mark. Agitate and transfer the solution into the reagent bottle. Add again distilled water to the same volumetric flask until it reaches the mark and pour it to the same reagent bottle, thus having a total volume of 1.0 L. Label the reagent bottle, 0.25N NaOH. Data and Computations: Conclusion:
reparation of 0.25N NaOH Objective: Apparatus and Materials: Procedure : Calculate the exact mass of NaOH needed to prepare 1.0L of 0.25N NaOH for standardization. Show your computations. Using the triple beam balance, weigh the desired amount of NaOH. Place the weighed amount of NaOH into the 500 mL volumetric flask and add distilled water until it reaches the mark. Agitate and transfer the solution into the reagent bottle. Add again distilled water to the same volumetric flask until it reaches the mark and pour it to the same reagent bottle, thus having a total volume of 1.0 L. Label the reagent bottle, 0.25N NaOH. Data and Computations: Conclusion:
Chapter88: Column Chromatography
Section: Chapter Questions
Problem 5P
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Question
Preparation of 0.25N NaOH
- Objective:
- Apparatus and Materials:
- Procedure :
- Calculate the exact mass of NaOH needed to prepare 1.0L of 0.25N NaOH for standardization. Show your computations.
- Using the triple beam balance, weigh the desired amount of NaOH.
- Place the weighed amount of NaOH into the 500 mL volumetric flask and add distilled water until it reaches the mark.
- Agitate and transfer the solution into the reagent bottle.
- Add again distilled water to the same volumetric flask until it reaches the mark and pour it to the same reagent bottle, thus having a total volume of 1.0 L.
- Label the reagent bottle, 0.25N NaOH.
Data and Computations:
Conclusion:
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