The sequences of DNA bases below represent parts of the genes responsible for the production of one type of protein, an enzyme, produced by Botana curus and Species X, Y, and ZUnder each DNA sequence, write the complementary messenger RNA base sequences that each of these gene fragments would produce. Note: Unlike during DNA replication, in the production of messenger RNA, the DNA base “A” specifies the RNA base “U.”. Use the universal genetic code table provided (see Universal Code attachment) to translate the messenger RNA base sequences into sequences of amino acids in the protein produced by each species. Write the sequences of amino acids under the messenger RNA sequences. Codon Chart:AUAU - tyrUAC = tyrUAA - stopUAG - stoPCUUU - pheUUC - pheUGU - cysUGC - cysUGA - stopUGG- trpUCU - serUCC = serUCA- serUCG- serCCU - proCCC- proCCA - proCCG- proACU - thrACC- thrACA - thrUUA - leuUUG- leuCUU - leuCUC - leuCỦA- leuCGU - argCGC- argCGA - argCAU - hisCAC - hisCAA - glnCAG- ginAAU- asnAAC- asnAAA - lysAAG - lysGAU- aspGAC - aspGAACGG = argAGU- serAGC- serAGA - argAGG- argGGU - glyGGC - glyGGA- glyGGG - glyCUG = leuAUU - ileAUC- ileAUA - ileAUG- metGUU = valGUC - valGUA - valGUG - valACG-thrGCU - alaGCC - alaGCA- alaGCG - alagluGAG - gluBotana curusCAC GTG GAC TGA GGA CTC CTCSequence of bases in MRNA producedGUG CAC CUG ACU CCU GAG GAGSequence of amino acids in the proteinSpecies XCAC GTG GAC AGA GGA CAC CTCSequence of bases in MRNA produced Sequence of amino acids in the proteinSpecies YCAC GTG GAC AGA GGA CAC CTCSequence of bases in MRNA producedSequence of amino acids in the proteinSpecies ZCAC GTA GAC TGA GGA CTT CTCSequence of bases in MRNA producedSequence of amino acids in the proteinState how the amino acid sequence you obtained from the gene fragment for Botana curuscompares with the sequences for the other three species.

Given: Botana curus CAC GTG GAC TGA GGA CTC CTC…

Answered: Sequence of amino acids in the protein…

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter9: From Dna To Protein

Section: Chapter Questions

Problem 8SQ

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Question

The sequences of DNA bases below represent parts of the genes responsible for the production of one type of protein, an enzyme, produced by Botana curus and Species X, Y, and Z
Under each DNA sequence, write the complementary messenger RNA base sequences that each of these gene fragments would produce. Note: Unlike during DNA replication, in the production of messenger RNA, the DNA base “A” specifies the RNA base “U.”.
Use the universal genetic code table provided (see Universal Code attachment) to translate the messenger RNA base sequences into sequences of amino acids in the protein produced by each species. Write the sequences of amino acids under the messenger RNA sequences.

Codon Chart:
A
UAU - tyr
UAC = tyr
UAA - stop
UAG - stoP
C
UUU - phe
UUC - phe
UGU - cys
UGC - cys
UGA - stop
UGG- trp
UCU - ser
UCC = ser
UCA- ser
UCG- ser
CCU - pro
CCC- pro
CCA - pro
CCG- pro
ACU - thr
ACC- thr
ACA - thr
UUA - leu
UUG- leu
CUU - leu
CUC - leu
CỦA- leu
CGU - arg
CGC- arg
CGA - arg
CAU - his
CAC - his
CAA - gln
CAG- gin
AAU- asn
AAC- asn
AAA - lys
AAG - lys
GAU- asp
GAC - asp
GAA
CGG = arg
AGU- ser
AGC- ser
AGA - arg
AGG- arg
GGU - gly
GGC - gly
GGA- gly
GGG - gly
CUG = leu
AUU - ile
AUC- ile
AUA - ile
AUG- met
GUU = val
GUC - val
GUA - val
GUG - val
ACG-thr
GCU - ala
GCC - ala
GCA- ala
GCG - ala
glu
GAG - glu
Botana curus
CAC GTG GAC TGA GGA CTC CTC
Sequence of bases in MRNA produced
GUG CAC CUG ACU CCU GAG GAG
Sequence of amino acids in the protein
Species X
CAC GTG GAC AGA GGA CAC CTC
Sequence of bases in MRNA produced

Sequence of amino acids in the protein
Species Y
CAC GTG GAC AGA GGA CAC CTC
Sequence of bases in MRNA produced
Sequence of amino acids in the protein
Species Z
CAC GTA GAC TGA GGA CTT CTC
Sequence of bases in MRNA produced
Sequence of amino acids in the protein
State how the amino acid sequence you obtained from the gene fragment for Botana curus
compares with the sequences for the other three species.

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