Table 4 Volume of Moles of Moles of moles of sodium acètate Log pK, pH Acetic Acid Acetic Sodium moles acetic acid mol Na Ac of Acid (mol) Acetate (mol) Solution HAC mol HAC Added (mL) 2.00 12.5 mol 0.001 mol 0.00008 4.74 4.00 6.25 mol 0.001 mol 0.00016 4.74 6.00 4.17 mol 0.001 mol 0.00024 4.74 8.00 3.13 mol 0.001 mol 0.00032 4.74

Chemistry for Today: General, Organic, and Biochemistry
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Chapter7: Sollutions And Colloids
Section: Chapter Questions
Problem 7.110E
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I need help finding the log and pH.

Table 4
Volume of
Moles of
Moles of
moles of sodium acètate Log
pK,
pH
Acetic Acid Acetic
Sodium
moles acetic acid
mol Na Ac
of
Acid (mol) Acetate
(mol)
Solution
HAC
mol HAC
Added
(mL)
2.00
12.5 mol
0.001 mol
0.00008
4.74
4.00
6.25 mol
0.001 mol
0.00016
4.74
6.00
4.17 mol
0.001 mol
0.00024
4.74
8.00
3.13 mol
0.001 mol
0.00032
4.74
Transcribed Image Text:Table 4 Volume of Moles of Moles of moles of sodium acètate Log pK, pH Acetic Acid Acetic Sodium moles acetic acid mol Na Ac of Acid (mol) Acetate (mol) Solution HAC mol HAC Added (mL) 2.00 12.5 mol 0.001 mol 0.00008 4.74 4.00 6.25 mol 0.001 mol 0.00016 4.74 6.00 4.17 mol 0.001 mol 0.00024 4.74 8.00 3.13 mol 0.001 mol 0.00032 4.74
Expert Solution
Step 1

Calculate the log(mol NaAc/mol HAc) value,

 

            log(mol NaAcmol HAc) = log (0.00008) = -4.1log(mol NaAcmol HAc) =  log (0.00016) = -3.8 log(mol NaAcmol HAc) = log (0.00024) = -3.6log(mol NaAcmol HAc) =  log (0.00032) = -3.5

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