Standard Normal Distribution. In Exercises, assume that randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph and find the probability of the given scores. If using technology instead of Table, round answers to four decimal places.Greater than 0 TABLE A-2(continued) Cumulative Area from the LEFT.00.01.02.03.04.05.06.07.08.09.5279.5675.60640.0.5000.5040.5080.5120.5160.5199.5239.5319.53590.1.5398.5438.5478.5517.5557.5596.5636.5714.57535832.60260.2.5793.5871.5910.5948.5987.6103.6141.84611.0.8413.8438.8485.8508.8531.8554.8577.8599.8621.8729.87908980.9147.92921.1.8643.8665.8686.8708.8749.8770.8810.8830.888889071.2.88498869.8925894489628997.90151.3.9032.9049.9066.9082.90999115.9131.9162.9177.9236.9306.93191.4.9192.9207.9222.9251.9265.9279

The test score z is greater than zero represents the probability of the bone density test score to…

Answered: TABLE A-2 (continued) Cumulative Area…

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Exponential And Logarithmic Functions

Section5.5: Exponential And Logarithmic Models

Problem 3ECP: Estimate the age of a newly discovered fossil for which the ratio of carbon-14 to carbon-12 is...

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Standard Normal Distribution. In Exercises, assume that randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph and find the probability of the given scores. If using technology instead of Table, round answers to four decimal places.

Greater than 0

TABLE A-2
(continued) Cumulative Area from the LEFT
.00
.01
.02
.03
.04
.05
.06
.07
.08
.09
.5279
.5675
.6064
0.0
.5000
.5040
.5080
.5120
.5160
.5199
.5239
.5319
.5359
0.1
.5398
.5438
.5478
.5517
.5557
.5596
.5636
.5714
.5753
5832
.6026
0.2
.5793
.5871
.5910
.5948
.5987
.6103
.6141
.8461
1.0
.8413
.8438
.8485
.8508
.8531
.8554
.8577
.8599
.8621
.8729
.8790
8980
.9147
.9292
1.1
.8643
.8665
.8686
.8708
.8749
.8770
.8810
.8830
.8888
8907
1.2
.8849
8869
.8925
8944
8962
8997
.9015
1.3
.9032
.9049
.9066
.9082
.9099
9115
.9131
.9162
.9177
.9236
.9306
.9319
1.4
.9192
.9207
.9222
.9251
.9265
.9279

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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