The following data was generated by running two TLC plates with four compounds-A, B, C &D (two on each plate). Plate 1, dist. traveled by compound A = 4.0 cm, dist. traveled by compound B 6 cm, dist. traveled by solvent 12 cm Plate 2, dist. traveled by compound C = 2.5 cm, dist. traveled by compound D= 5 cm, dist. traveled by solvent = 10 cm Based on the Rf value calculations, the identical compounds are: OC&D B&D O A&C B&C

EBK A SMALL SCALE APPROACH TO ORGANIC L
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Chapter11: Isolation Of Caffeine From Tea Le
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The following data was generated by running two TLC plates with four compounds-A, B, C & D (two on each plate).
Plate 1, dist. traveled by compound A = 4.0 cm, dist. traveled by compound B= 6 cm, dist. traveled by solvent = 12 cm
Plate 2, dist. traveled by compound C=2.5 cm, dist. traveled by compound D= 5 cm, dist. traveled by solvent = 10 cm
Based on the Rf value calculations, the identical compounds are:
OC&D
B &D
O A&C
OB& C
Transcribed Image Text:The following data was generated by running two TLC plates with four compounds-A, B, C & D (two on each plate). Plate 1, dist. traveled by compound A = 4.0 cm, dist. traveled by compound B= 6 cm, dist. traveled by solvent = 12 cm Plate 2, dist. traveled by compound C=2.5 cm, dist. traveled by compound D= 5 cm, dist. traveled by solvent = 10 cm Based on the Rf value calculations, the identical compounds are: OC&D B &D O A&C OB& C
Fractional distillation of a mixture of two compounds gives the following data after the GC analysis and peak integration:
Peak 1 (corresponding to compound 1), area = 70.3 sq units
Peak 2 (corresponding to compound 2), area 28.7 sq units
What was the original percentage composition of the two compounds in the mixture?
O Compound 1 29.0%
Compound 2 = 71.0%
Compound 1=71.0%
Compound 2 = 29.0%
Compound 1 = 41.0%
Compound 2 = 59.0%
Compound 1 =61.5%
Compound 2 = 38.5%
Transcribed Image Text:Fractional distillation of a mixture of two compounds gives the following data after the GC analysis and peak integration: Peak 1 (corresponding to compound 1), area = 70.3 sq units Peak 2 (corresponding to compound 2), area 28.7 sq units What was the original percentage composition of the two compounds in the mixture? O Compound 1 29.0% Compound 2 = 71.0% Compound 1=71.0% Compound 2 = 29.0% Compound 1 = 41.0% Compound 2 = 59.0% Compound 1 =61.5% Compound 2 = 38.5%
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