The mass of a cesium (Cs, atomic number 55) atom is 2.21×10−25 kg, and its radius is R = 2.65×10−10 m. The mass of the atomic nucleus roughly equals the mass of the whole atom. The nuclear density is 2×1017 kg/m3. Calculate the fraction of the volume occupied by the nucleus in a cesium atom. Round your answer to 1 (one) significant figure. The volume of the atom is Vatom = 4 3πR3. You may use the approximation Vatom ≈ 4R3and the relation Vnucleus Vatom = datom dnucleus.

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Asked Oct 2, 2019
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The mass of a cesium (Cs, atomic number 55) atom is 2.21×10−25 kg, and its radius is R = 2.65×10−10 m. The mass of the atomic nucleus roughly equals the mass of the whole atom. The nuclear density is 2×1017 kg/m3. Calculate the fraction of the volume occupied by the nucleus in a cesium atom. Round your answer to 1 (one) significant figure. The volume of the atom is Vatom = 4 3πR3. You may use the approximation Vatom ≈ 4R3and the relation Vnucleus Vatom = datom dnucleus.

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Expert Answer

Step 1

An atom can be considered as the smallest unit of any matter. An atom is composed of certain sub-atomic particles whose position, interaction and charges maintain the neutrality of the atom. These sub-atomic particles are electrons, neutrons and protons.

Step 2

Electrons are negatively charged particles which are arranged in certain energy levels in an atom. These particles have negligible mass and carry -1 charge compare to other particles.

The energy levels in which electrons are placed, called as shell. These sub-atomic particles take part in the chemical reactions of an atom.

Step 3

Mass of atom = 2.21×10−25 kg

Mass of atom = Mass of nucleus

Radius of atom = R = 2.65×10−10 m

Nuclea...

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Mass Volume density 2.21x10kg 2x1017kg/m3 Volume Volume 1.105 x 1042 m'

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