Write a recursive function called digit_count() that takes a positive integer as a parameter and returns the number of digits in the integer. Hint: The number of digits increases by 1 whenever the input number is divided by 10. Ex: If the input is: 345 the function digit_count() returns and the program outputs: 3 # TODO: Write recursive digit_count() function here. if __name__ == '__main__': num = int(input())
Write a recursive function called digit_count() that takes a positive integer as a parameter and returns the number of digits in the integer. Hint: The number of digits increases by 1 whenever the input number is divided by 10. Ex: If the input is: 345 the function digit_count() returns and the program outputs: 3 # TODO: Write recursive digit_count() function here. if __name__ == '__main__': num = int(input())
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 1TF
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Write a recursive function called digit_count() that takes a positive integer as a parameter and returns the number of digits in the integer. Hint: The number of digits increases by 1 whenever the input number is divided by 10.
Ex: If the input is:
345
the function digit_count() returns and the
3
# TODO: Write recursive digit_count() function here.
if __name__ == '__main__':
num = int(input())
digit = digit_count(num)
print(digit)
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