Lewis structure for crotonaldehyde is to be drawn. Concept introduction: In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

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Answer 1

Question

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

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Answer 2

Question

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

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Answer 3

Question

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

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Answer 4

Question

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

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Answer 5

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

Answer 6

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

Answer 7

Chapter 1, Problem 1.25P

Interpretation Introduction

Interpretation:

Lewis structure for crotonaldehyde is to be drawn.

Concept introduction:

In order to draw a Lewis structure for a molecule, start by counting the total number of valence electrons in a molecule. The number of valence electrons by each atom is the same as its group number. Generally, the condensed formula depicts the connectivity of atoms. For the given skeleton of the molecule, distribute the remaining electrons as lone pairs. In doing so, start with the outer atoms and work inwards. Try to achieve an octet on each atom other than hydrogen. If there is an atom with less than an octet, increase the atom’s share of electrons by converting lone pairs from neighboring atoms into bonding pairs thereby creating double or triple bonds. For an uncharged atom, carbon atoms will have maximum four bonds, Nitrogen will have three bonds and one lone pair, while oxygen will have two bonds and two lone pairs. Hydrogen always contributes to one bond. The number of bonds in case of halogen is one, while there will be three lone pairs of electrons on halide atoms.

Answer 8

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Answer 11

Ch. 1 - Prob. 1.1P Ch. 1 - Prob. 1.2P Ch. 1 - Prob. 1.3P Ch. 1 - Prob. 1.4P Ch. 1 - Prob. 1.5P Ch. 1 - Prob. 1.6P Ch. 1 - Prob. 1.7P Ch. 1 - Prob. 1.8P Ch. 1 - Prob. 1.9P Ch. 1 - Prob. 1.10P

Solution Summary: The author illustrates the Lewis structure for crotonaldehyde by counting the total number of valence electrons in a molecule.

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