Concept explainers
A mixture contains the following five pure substances:
Cl2, C2Cl6, H2CO3, H2SO4, and HC1.
- a. How many different kinds of diatomic molecules are present in the mixture?
- b. How many different kinds of atoms are present in the mixture?
- c. How many total atoms are in a mixture sample containing four molecules of each component?
- d. How many total carbon atoms are present in a mixture sample containing three molecules of each component?
(a)
Interpretation:
The number of diatomic molecules that is present in the mixture has to be given.
Concept Introduction:
The composition of a chemical compound can be presented in a very precise was with the use of chemical formula. Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.
Answer to Problem 1.88EP
In the given mixture of five molecules, two diatomic molecules are present.
Explanation of Solution
Given molecules in mixture are
Diatomic molecule is the one that contains a total of two atoms in it. Looking into the above chemical formulas, the molecule that contains two atoms in it is found to be
(b)
Interpretation:
The different kind of atoms that is present in the mixture has to be given.
Concept Introduction:
The composition of a chemical compound can be presented in a very precise was with the use of chemical formula. Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.
Answer to Problem 1.88EP
Five kinds of atoms are present in the mixture.
Explanation of Solution
Given molecules in mixture are
Looking into the molecules in the given mixture, it is found that there are five kind of atoms present in the given molecules and they are
(c)
Interpretation:
The total number of atoms that is present in the mixture that contains four molecules of each component has to be given.
Concept Introduction:
The composition of a chemical compound can be presented in a very precise was with the use of chemical formula. Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.
Answer to Problem 1.88EP
There are a total of 100 atoms present.
Explanation of Solution
Given molecules in mixture are
Number of atoms in
Number of atoms in
Number of atoms in
Number of atoms in
Number of atoms in
The total number of atoms that is present in mixture which contains one molecule of each component can be found by summing up the number of atoms in all molecules. This gives the total number of atoms as 25.
If the mixture contains four molecules of each component, then the total number of atoms can be found as shown below,
Therefore, there are 100 atoms present in the mixture that contains four molecules of each component.
(d)
Interpretation:
The total number of carbon atoms that is present in the mixture that contains three molecules of each component has to be given.
Concept Introduction:
The composition of a chemical compound can be presented in a very precise was with the use of chemical formula. Chemical formula uses chemical symbols of the elements that is present in the compound and numerical subscripts that represent how many number of atoms of each element is present in the compound.
Answer to Problem 1.88EP
There are a total of 9 carbon atoms present.
Explanation of Solution
Given molecules in mixture are
Number of atoms in
Number of atoms in
Number of atoms in
Number of atoms in
Number of atoms in
The total number of carbon atoms that is present in mixture which contains one molecule of each component can be found by summing up the number of carbon atoms in all molecules. This gives the total number of carbon atoms as 3.
If the mixture contains three molecules of each component, then the total number of carbon atoms can be found as shown below,
Therefore, there are 9 carbon atoms present in the mixture that contains three molecules of each component.
Want to see more full solutions like this?
Chapter 1 Solutions
General, Organic, and Biological Chemistry
- Which of the following will be homogeneous mixture? (A) All of them (B) N2 and Ar (C) C2H5OH and H2O (D) NH4Cl and H2O (E) C6H6 and C7H8arrow_forwardSome mixtures do not have the same composition, properties, and appearance throughout. Why?arrow_forwardAn example of a homogeneous mixture is: 2.65 g Citric acid (H3C6H5O4) 0.023 M KSCN (aq) 15.0 g SiO2 (sand) 0.064g Na (s) Which one?arrow_forward
- the mole is a common unit of measurement in chemistry you mat not be faniliar with mikes but one of the advantages of simensional analysis is that you can work with any units as long as you know equivalent measurements one mole of water is equivalent to 18 grams of water a mug of water was measured to contain 290 grams of water how many moles of water is thisarrow_forwardAn air conditioner compressor contains pure CClF3, also known as the refrigerant R-13. CClF3 has a density of 1.53x10^-3 g/L when unpressurized. If the volume of the unpressurized compressor is 0.500 L, how many molecules of CClF3 are in the compressor? a) 4.41x10^18 b) 8.82x10^18 c) 4.60x10^20 d) 1.04x10^2arrow_forwardIs this correct? ( just check to see if the calculations are correct) H2+I2 -->2H Ke= [HI]2/ [H2][I2] HI= sqrt Ie [H2] [I2] = sqrt 49.5 * 0.2000 mol/5.00L * 0.200 mol/ 5.00 L HI= 0.0706 mol/L H2= 0.1244 mol/L I2= 0.1244 mol/Larrow_forward
- 1. ____N2 + 3H2 ____NH32. ____ KClO3 ____ KCl + 3 O23. ____NaCl + ____F2 2NaF + ____Cl24. ____H2 + ____O2 2H2O5. 2 AgNO36. ____ AlBr37. ____CH48. ____C3H89. ____ C8H18 + 25 O2 ____ CO210. ____ FeCl3 + ____ NaOH ____ Fe(OH)3 + 3 NaClarrow_forwardYou have two distinct gaseous compounds made from element X and element Y.The mass percents are as follows: Compound I: 30.43% X, 69.57% Y Compound II: 63.64% X, 36.36% Y In their natural standard states, element X and element Y exist as gases. (Monatomic? Diatomic? Triatomic? That is for you to determine.) When you react "gas X" with "gas Y" to make the products, you get the following data (all at the same pressure and temperature): 1 volume "gas X" + 2 volumes "gas Y" → 2 volumes compound I 2 volumes "gas X" + 1 volume "gas Y" → 2 volumes compound II Assume the simplest possible formulas for reactants and products in the chemical equations above. Then, determine the relative atomic masses of element X and element Y.arrow_forwardBE’s are: C=O 799, C–H 413, O–H 467, O–O 498, H–H 432 kJ/mol CO2(g) + 4H2(g) → CH4(g) + 2H2O(g) ΔHrxn° = ___ kJ (from ΔHf°s) ΔHrxn°(BE) = ___ kJ (from BEs) = (2x799+432-4x413-4x467) CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ΔHrxn° = ___ kJ (from ΔHf°s) ΔHrxn°(BE) = ___ kJ (from BEs) ...Calculate ΔHrxn°s from both!arrow_forward
- About Sampling, tick only the incorrect alternative(s). Choose one or more: A) Identifying the nature of a substance present in an unknown sample is called qualitative analysis. The process of measuring how much a constituent is present in a substance is called quantitative analysis. B) A type of error that is known due to procedures that cause a measure to be too large or too small is called a random error, such as reading a scale. C) Sample preparation is the process in which a representative sample is converted into a form suitable for chemical analysis. This usually means dissolving the sample. For a sample with low analyte concentration it may need to be diluted before being analyzed. D) Sampling is the process used to collect a representative sample for analysis. As real abnormals, as regulators are used in real experiments, they also typically prepare some degree of sample preparation to remove substances that do not interfere with the analysis of the desired analyte and…arrow_forwardA 45.00 mL portion of olive oil (d=0.917 kg/L) was added to a mixture weighing 250g. By mass, the mixture contains 56.9% water (d=0.99704 g/mL), 23.1% salt, 15.0% of suspended solids, and 5.0% sugar. a. Determine mass of components of original mixture. b. Find the percent composition (% w/w) of the final mixture. c. Propose a method of separating the components of the final mixture.arrow_forwardWhat are the correct number of sig figs? What is the final answer meant to look like?arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning