Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 22P
Solution

a.

Total meters in 1 light year.

  9.45×1015 m

Given:

A light year is the distance light travels in one year at speed 2.998×108m/sec

Formula used:

  d=v×t here d is distance, v is velocity and t is time

Calculation:

One year =365 days = 365×24×60×60 Second

So one light year = v×t meters

One light year = 2.998×108×365×24×60×60meter

One light year = 9.45×1015 m

Conclusion:

Therefore, in 1 light year there are 9.45×1015 m

b.

Total AU in 1 light year.

One light year =6.3×104 AU.

Given information:

A light year is the distance light travels in one year at speed 2.998×108m/sec. An astronomical unit (AU) is the average distance from sun to earth , 1.5×108km.

Formula used:

  1AU= 1.5×108km1AU= 1.5×1011m

Calculation:

One light year is equal to 9.45×1015

So, number of AU in 1.00 light year=

  9.45×10151.5×1011=6.3×104

Conclusion:

Therefore, number of AU in 1 light year is 6.3×104

c.

The speed of light in AU/h.

7.20AU/hour

Given:

A light year is the distance light travels in one year at speed 2.998×108m/sec

Formula used:

  1km=1000m

  1hour=3600sec

Calculation:

The speed of light in meter/sec is 2.998×108

In km/sec the speed of light =2.998×1081000=2.998×105 km/sec

In km/hour Speed of light

  =2.998×105×3600 km/hour

One AU is equal to 1.5×108km

So the speed of light in AU/h

  =2.998×105×36001.5×108=1.07928×1091.5×108=7.20 AU/hour

Conclusion:

Therefore, speed of light is 7.2 AU/hour.

Chapter 1 Solutions

Physics: Principles with Applications

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