Mechanics of Materials - With Access
7th Edition
ISBN: 9781259279881
Author: BEER
Publisher: MCG
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Textbook Question
Chapter 1, Problem 61RP
For the assembly and loading of Prob. 1.60, determine (a) the average shearing stress in the pin at C, (b) the average bearing stress at C in member BC, (c) the average bearing stress at B in member BC.
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Chapter 1 Solutions
Mechanics of Materials - With Access
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- In the structure shown, an 8 mm diameter pin is used at A, and 12 mm diameter pins are used at B and D. Knowing that the allowable shearing stress is 120 MPa at all connections and that the allowable normal stress and bearing stress is 240 MPa in each of the two links joining B and D, determine the allowable load Parrow_forwardA rectangular block of a material with a modulus of rigidity G= 90 ksi is bonded to two rigid horizontal plates. The lower plate is fixed, while the upper plate is subjected to a horizontal force P . Knowing that the upper plate moves through 0.04 in. under the action of the force, determine (a) the average shearing strain in the material and (b) the force Pexerted on the upper plate.arrow_forwardPART 2: Determine the shear force acting at each of the following locations: (a) x = 0+ ft (i.e., just to the right of support A) (b) x = 14.0 ft (i,e., at point B.) (c) x = 20.5- ft (i.e., just to the left of the support C) (d) x = 20.5+ ft (i.e., just to the right of the support (C) (e)x=27.5ft Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers: Correct (a) V= 105.823 kips (b)V= -48.177 kips (c) V= -119.677 kips (d)V= 88 kips (e) V= 10.9998 kips PART 3: Determine the bending moment acting at each of the following locations: (a) x = 14.0- ft (i.e., just to the left of point B.) (b) x = 14.0+ ft(i.e., just to the right of point B.) (c) x = 20.5 ft (i.e. at point C) (d)x=27.5ft Note that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2. My Answers: Correct (a) M = 403.522 kips-ft (b) M = 193.522 kips-ft (c) M = -352.0035 kips-ft (d) M =…arrow_forward
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