Chemistry
Chemistry
13th Edition
ISBN: 9781259911156
Author: Raymond Chang Dr., Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 10, Problem 10.10QP

Predict the geometry of the following molecules and ion using the VSEPR model: (a) CH3I, (b) ClF3, (c) H2S, (d) SO3, (e) SO 4 2 .

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

  • The first step is to draw the correct Lewis structure for the molecule.
  • Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
  • Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  1will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  2will have shape like trigonal planar, typeChemistry, Chapter 10, Problem 10.10QP , additional homework tip  3will have shape like tetrahedral or square planar, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  4will have trigonal bipyramidal and Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  5will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(a)

Tetrahedral geometry

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (a)

Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  6

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 14.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 14 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 6 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (a) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral that is four atoms gets bonded with the central atom in the given molecule.

There exist no lone pair on carbon central atom then the molecular geometry for this molecule is tetrahedral.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

  • The first step is to draw the correct Lewis structure for the molecule.
  • Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
  • Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  7will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  8will have shape like trigonal planar, typeChemistry, Chapter 10, Problem 10.10QP , additional homework tip  9will have shape like tetrahedral or square planar, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  10will have trigonal bipyramidal and Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  11will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(b)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (b)

Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  12

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 28.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 6 has to be subtracted with 28 as each bond contains two electrons with it and there are three bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (b) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal bipyramidal that is the chlorine atom contains three fluorine atoms and two lone pair of electrons with it hence the geometry for the molecule is T-shaped.

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

  • The first step is to draw the correct Lewis structure for the molecule.
  • Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
  • Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  13will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  14will have shape like trigonal planar, typeChemistry, Chapter 10, Problem 10.10QP , additional homework tip  15will have shape like tetrahedral or square planar, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  16will have trigonal bipyramidal and Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  17will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(c)

Bent shaped

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (c)

Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  18

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 8.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 4 has to be subtracted with 8 as each bond contains two electrons with it and there are two bonds in the skeletal structure.

Finally, the 4 electrons got after subtractions has to be equally distributed over Sulphur atom such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (c) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since two lone pair of electrons present over Sulphur atom and the molecular geometry for the molecule is bent.

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

  • The first step is to draw the correct Lewis structure for the molecule.
  • Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
  • Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  19will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  20will have shape like trigonal planar, typeChemistry, Chapter 10, Problem 10.10QP , additional homework tip  21will have shape like tetrahedral or square planar, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  22will have trigonal bipyramidal and Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  23will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(d)

Trigonal planar

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (d)

Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  24

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 24.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 24 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 16 electrons got after subtractions has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (d) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type trigonal planar and the molecular geometry is also trigonal planar since there are no lone pair of electrons over the central Sulphur atom.

(e)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation: For the given set of molecules the molecular geometry around the central metal should be predicted using VSEPR model.

Concept Introduction:

Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).

VSEPR Theory:

As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions. The steps involved in the theory in describing the geometry is as follows,

  • The first step is to draw the correct Lewis structure for the molecule.
  • Then, the electron domain around the central atom should be counted and the geometry that matches with that type of domain in VSEPR should be determined.
  • Finally, the geometry is predicted by using the orientation of atoms.

The molecules with considering the domains of type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  25will tend to have shape like linear or bent if the central atom have lone pair of electrons with it, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  26will have shape like trigonal planar, typeChemistry, Chapter 10, Problem 10.10QP , additional homework tip  27will have shape like tetrahedral or square planar, type Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  28will have trigonal bipyramidal and Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  29will have shape like octahedral respectively.

Lewis structure for any molecule is drawn by using the following steps,

First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined

The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.

Finally, the electrons which got after subtractions has to be equally distributed such that each atom contains eight electrons in its valence shell.

Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.

Answer to Problem 10.10QP

(e)

Tetrahedral

Explanation of Solution

To predict: The geometry for the given molecule.

Draw the Lewis structure for the molecule (e)

Chemistry, Chapter 10, Problem 10.10QP , additional homework tip  30

First the skeletal structure for the given molecule is drawn then the total number of valence electrons in the molecule is 30.

The next step is to subtract the electrons present in the total number of bonds present in the molecule with the total valence electrons such that 8 has to be subtracted with 30 as each bond contains two electrons with it and there are four bonds in the skeletal structure.

Finally, the 22 electrons got after subtractions plus the two electrons due to the charge -2 has to be equally distributed over oxygen atoms such that each atom contains eight electrons in its valence shell.

Determine the molecular geometry for the molecule (e) using VSEPR.

The electron domain for the given molecule is obtained by viewing the Lewis structure which is of type tetrahedral since there are four atoms around the central atom and the molecular geometry is also tetrahedral due to the absence of lone pair over the central atom

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Chapter 10 Solutions

Chemistry

Ch. 10.4 - Describe the hybridization state of Se in SeF6.Ch. 10.4 - How many orbitals does a set of sp3d hybrid...Ch. 10.4 - What is the hybridization of P in PH4+?Ch. 10.4 - What is the hybridization of Xe in XeF4Ch. 10.5 - Describe the bonding in the hydrogen cyanide...Ch. 10.5 - How many pi bonds are present in CS2?Ch. 10.5 - Which of the following pairs of atomic orbitals on...Ch. 10.6 - One way to account for the fact that an O2...Ch. 10.7 - Which of the following species has a longer bond...Ch. 10.7 - Calculate the bond order of F2+.Ch. 10.7 - Determine if N2+ is diamagnetic or paramagnetic.Ch. 10.7 - Estimate the bond enthalpy (kJ/mol) of the H2+...Ch. 10.8 - Describe the bonding in the nitrate ion (NO3) in...Ch. 10 - How is the geometry of a molecule defined and why...Ch. 10 - Sketch the shape of a linear triatomic molecule, a...Ch. 10 - How many atoms are directly bonded to the central...Ch. 10 - Discuss the basic features of the VSEPR model....Ch. 10 - Prob. 10.5QPCh. 10 - Prob. 10.6QPCh. 10 - Predict the geometries of the following species...Ch. 10 - Predict the geometries of the following species:...Ch. 10 - Predict the geometry of the following molecules...Ch. 10 - Predict the geometry of the following molecules...Ch. 10 - Predict the geometry of the following molecules...Ch. 10 - Predict the geometries of the following ions: (a)...Ch. 10 - Describe the geometry around each of the three...Ch. 10 - Which of the following species are tetrahedral?...Ch. 10 - Prob. 10.15QPCh. 10 - Prob. 10.16QPCh. 10 - Prob. 10.17QPCh. 10 - The bonds in beryllium hydride (BeH2) molecules...Ch. 10 - Referring to Table 10.3, arrange the following...Ch. 10 - The dipole moments of the hydrogen halides...Ch. 10 - List the following molecules in order of...Ch. 10 - Does the molecule OCS have a higher or lower...Ch. 10 - Which of the molecules (a) or (b) has a higher...Ch. 10 - Prob. 10.24QPCh. 10 - What is valence bond theory? 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