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EBK ORGANIC CHEMISTRY
6th Edition
ISBN: 8220103151757
Author: LOUDON
Publisher: MAC HIGHER
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Question
Chapter 10, Problem 10.27P
Interpretation Introduction
Interpretation:
The balanced half-reaction for the given reaction has to be stated. The correct terms corresponding to the blanks are to be stated.
Concept introduction:
A
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Students have asked these similar questions
2. Calculate the AG* of the reaction:
-
N₂H4(1) + H₂
2NH3(g)
using the following data:
N₂H4(1) + CH₂O()→ CH₂O(g) + N₂(g) + 3H₂(g)
N2(g) + 3H2(g) → 2NH3(0)
→
CH40(1) CH₂O(g) + H₂(g)
AG = -85.6kJ
AG = -32.9kJ
AG = -63.74k]
6.) Predict the product of the following chemical reactions and state where the product (waste) should the
waste should be disposed:
Example:
OH
1. NaBH,, ethanol
CH,CH,CH,CH
CH;CH,CH,CH
2. H3O*
H
Butanal
1-Butanol
Waste: G704 (Non-halogenated organic solvents)
1. NaBH4, ethanol
a.) Cyclohexanecarbaldehyde 2. H,O*
b.) Sodium Flouride + 3-iodo-3-methylpentane
→ (hint: substitution or elimination?)
H30*
c.) Benzoic acid + Phenol
РСС
d.) 3-pentanol
H2CrO4
e.) Cyclohexylmethanol
6.) Predict the product of the following chemical reactions and state where the product (waste) should the
waste should be disposed:
Example:
он
1. Nallif, ethanol
2. 10
CH,CH,CH,CH
CH,CH,CH,CH
H
Butanal
1-Butanol
Waste: G704 (Non-halogenated organic solvents)
1. Nalil, ethanal
a.) Cyclohexanecarbaldehyde 2 110
b.) Sodium Flouride + 3-iodo-3-methylpentane
(hìnt: substitution or elimination?)
H,O
c.) Benzoic acid + Phenol
PCC
d.) 3-pentanol
H.CrO>
e.) Cyclohexylmethanol
Chapter 10 Solutions
EBK ORGANIC CHEMISTRY
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Prob. 10.26PCh. 10 - Prob. 10.27PCh. 10 - Prob. 10.28PCh. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Prob. 10.31PCh. 10 - Prob. 10.32PCh. 10 - Prob. 10.33PCh. 10 - Prob. 10.34PCh. 10 - Prob. 10.35PCh. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39APCh. 10 - Prob. 10.40APCh. 10 - Prob. 10.41APCh. 10 - Prob. 10.42APCh. 10 - Prob. 10.43APCh. 10 - Prob. 10.44APCh. 10 - Prob. 10.45APCh. 10 - Prob. 10.46APCh. 10 - Prob. 10.47APCh. 10 - Prob. 10.48APCh. 10 - Prob. 10.49APCh. 10 - Prob. 10.50APCh. 10 - Prob. 10.51APCh. 10 - Prob. 10.52APCh. 10 - Prob. 10.53APCh. 10 - Prob. 10.54APCh. 10 - Prob. 10.55APCh. 10 - Prob. 10.56APCh. 10 - Prob. 10.57APCh. 10 - Prob. 10.58APCh. 10 - Prob. 10.59APCh. 10 - Prob. 10.60APCh. 10 - Prob. 10.61APCh. 10 - Prob. 10.62APCh. 10 - Prob. 10.63APCh. 10 - Prob. 10.64APCh. 10 - Prob. 10.65APCh. 10 - Prob. 10.66APCh. 10 - Prob. 10.67APCh. 10 - Prob. 10.68APCh. 10 - Prob. 10.69APCh. 10 - Prob. 10.70AP
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