Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List)
6th Edition
ISBN: 9781337115186
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: Cengage Learning
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Textbook Question
Chapter 10.3, Problem 19E
Consider the following hypothesis test.
The following data are from matched samples taken from two populations.
- a. Compute the difference value for each element.
- b. Compute
- c. Compute the standard deviation sd.
- d. Conduct a hypothesis test using α = .05. What is your conclusion?
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The effectiveness of a new bug repellent is tested on 1616 subjects for a 10 hour period. (Assume normally distributed population.) Based on the number and location of the bug bites, the percentage of surface area exposed protected from bites was calculated for each of the subjects. The results were as follows:
?⎯⎯⎯=92x¯=92, ?=13 s=13
The new repellent is considered effective if it provides a percent repellency of at least 9090. Using ?=0.05α=0.05, construct a hypothesis test with null hypothesis ?≤90μ≤90 and alternative hypothesis ?>90μ>90 to determine whether the mean repellency of the new bug repellent is greater than 9090 by computing the following:
(a) the degree of freedom
(b) the test statistic
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A. There is not sufficient evidence to reject the null hypothesis that ?≤90μ≤90. Our results do not provide enough evidence that the new bug repellent is effective. B. We can reject the null hypothesis that ?≤90μ≤90. Our results indicate that…
A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCi/L of radon. The resulting readings were as follows: 104.3 89.6 89.9 95.6 95.2 90.0 98.8 103.7 98.3 106.4 102.0 91.1
a)Does this data suggest that the population mean reading under these conditions differs from 100? State and test the appropriate hypotheses using =.05.
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Chapter 10 Solutions
Modern Business Statistics with Microsoft Office Excel (with XLSTAT Education Edition Printed Access Card) (MindTap Course List)
Ch. 10.1 - The following results come from two independent...Ch. 10.1 - 2. Consider the following hypothesis test.
The...Ch. 10.1 - 3. Consider the following hypothesis test.
The...Ch. 10.1 - 4. Condé Nast Traveler conducts an annual survey...Ch. 10.1 - 5. The USA Today reports that the average...Ch. 10.1 - Hotel Price Comparison. Suppose that you are...Ch. 10.1 - Consumer Reports uses a survey of readers to...Ch. 10.1 - Increases in Customer Satisfaction. Will improving...Ch. 10.2 - The following results are for independent random...Ch. 10.2 - Consider the following hypothesis test:
The...
Ch. 10.2 - Consider the following data for two independent...Ch. 10.2 - Prob. 12ECh. 10.2 - Annual Cost of College. The increasing annual cost...Ch. 10.2 - Are nursing salaries in Tampa, Florida, lower than...Ch. 10.2 - Hotel prices worldwide are projected to increase...Ch. 10.2 - Effect of Parents’ Education on Student SAT...Ch. 10.2 - Comparing Financial Consultant Ratings....Ch. 10.2 - Researchers at Purdue University and Wichita State...Ch. 10.3 - Consider the following hypothesis test.
The...Ch. 10.3 - The following data are from matched samples taken...Ch. 10.3 - Prob. 21ECh. 10.3 - The price per share of stock for a sample of 25...Ch. 10.3 - Credit Card Expenditures. Bank of America’s...Ch. 10.3 - Domestic Airfare. The Global Business Travel...Ch. 10.3 - Prob. 25ECh. 10.3 - PGA Tour Scores. Scores in the first and fourth...Ch. 10.3 - Price Comparison of Smoothie Blenders. A personal...Ch. 10.4 - Consider the following results for independent...Ch. 10.4 - Prob. 29ECh. 10.4 - Corporate Hiring Outlook. A Businessweek/Harris...Ch. 10.4 - Impact of Pinterest on Purchase Decisions. Forbes...Ch. 10.4 - Mislabeled Fish. Researchers with Oceana, a group...Ch. 10.4 - Minnesota had the highest turnout rate of any...Ch. 10.4 - Oil wells are expensive to drill, and dry wells...Ch. 10.4 - In a test of the quality of two television...Ch. 10.4 - Winter visitors are extremely important to the...Ch. 10.4 - Prob. 37ECh. 10 - Prob. 38SECh. 10 - SUV Lease Payments. Statista reports that the...Ch. 10 - Prob. 40SECh. 10 - Kitchen Versus Bedroom Remodeling Costs. The...Ch. 10 - Effect of Siblings on SAT Scores. In Born...Ch. 10 - Country Financial, a financial services company,...Ch. 10 - Prob. 44SECh. 10 - Prob. 45SECh. 10 - News Access Via Computer. The American Press...Ch. 10 - For the week ended January 15, 2009, the bullish...
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- Consider the following hypothesis test: H0: mu >= 20 Halpha:mu < 20 A sample of 50 provided a sample mean of 19.4 . The population standard deviation is 2 . d. Using alpha=.05, what is the critical value for the test statistic (to 3 decimals)? Enter negative value as negative number.arrow_forwardConsider the hypothesis statement shown below using α=0.01 and the data to the right from two independent samples. H0: μ1−μ2=0 H1: μ1−μ2≠0 a) Calculate the appropriate test statistic and interpret the result. b) Calculate the p-value and interpret the result. x1 = 237 x2 = 258 σ1 = 48 σ2 = 55 n1 = 43 n2 = 37arrow_forwardThe desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…arrow_forward
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