Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
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Question
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Chapter 10.5, Problem 12CFU

(a)

To determine

To graph: The function s=v0t−16t2+3 for the given initial velocity.

(a)

Expert Solution
Check Mark

Answer to Problem 12CFU

  The graph

Explanation of Solution

Given information: Sports: In 1998, Sammy Sosa of the Chicago Cubs was in a home run race with Mark McGwire of the St. Louis Cardinals. One day, Mr. Sosa popped a baseball straight up at an initial velocity v0 of 56 feet per second. Its distance s above the ground after t seconds is described by s=v0t−16t2+3 .

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.5, Problem 12CFU , additional homework tip 1

Calculation:

  y=−16x2+56x+3

The graph:

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.5, Problem 12CFU , additional homework tip 2

(b)

To determine

To find: The maximum height achieved by the ball.

(b)

Expert Solution
Check Mark

Answer to Problem 12CFU

  52 feet

Explanation of Solution

Given information: Sports: In 1998, Sammy Sosa of the Chicago Cubs was in a home run race with Mark McGwire of the St. Louis Cardinals. One day, Mr. Sosa popped a baseball straight up at an initial velocity v0 of 56 feet per second. Its distance s above the ground after t seconds is described by s=v0t−16t2+3 .

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.5, Problem 12CFU , additional homework tip 3

Calculation:

  y=−16t2+56t+3

Maximum at vertex: (−562(−16),f(−562(−16)))=(74,52)

Maximum height: 52 feet.

(c)

To determine

To find: How many seconds, to the nearest tenth, is it in the air, if the ball is allowed to fall to the ground.

(c)

Expert Solution
Check Mark

Answer to Problem 12CFU

  3.6 seconds

Explanation of Solution

Given information: Sports: In 1998, Sammy Sosa of the Chicago Cubs was in a home run race with Mark McGwire of the St. Louis Cardinals. One day, Mr. Sosa popped a baseball straight up at an initial velocity v0 of 56 feet per second. Its distance s above the ground after t seconds is described by s=v0t−16t2+3 .

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.5, Problem 12CFU , additional homework tip 4

Calculation:

  y=−16t2+56t+3

Quadratic Formula:

  x=−56±562−4(−16)(3)2(−16)≃3.6

Thus, 3.6 seconds.

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Chapter 10.5, Problem 11CFU
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Chapter 10.5, Problem 13E

Chapter 10 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 10.1 - Prob. 1CFUCh. 10.1 - Prob. 2CFUCh. 10.1 - Prob. 3CFUCh. 10.1 - Prob. 4CFUCh. 10.1 - Prob. 5CFUCh. 10.1 - Prob. 6CFUCh. 10.1 - Prob. 7CFUCh. 10.1 - Prob. 8CFUCh. 10.1 - Prob. 9CFUCh. 10.1 - Prob. 10CFU
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Prob. 18ECh. 10.6 - Prob. 19ECh. 10.6 - Prob. 20ECh. 10.6 - Prob. 21ECh. 10.6 - Prob. 22ECh. 10.6 - Prob. 23ECh. 10.6 - Prob. 24ECh. 10.6 - Prob. 25ECh. 10.6 - Prob. 26ECh. 10.6 - Prob. 27ECh. 10.6 - Prob. 28ECh. 10.6 - Prob. 29ECh. 10.6 - Prob. 30ECh. 10.6 - Prob. 31ECh. 10.6 - Prob. 32ECh. 10.6 - Prob. 33ECh. 10.6 - Prob. 34ECh. 10.6 - Prob. 35ECh. 10.6 - Prob. 36ECh. 10.6 - Prob. 37ECh. 10.6 - Prob. 38ECh. 10.6 - Prob. 39ECh. 10.6 - Prob. 40ECh. 10.6 - Prob. 41ECh. 10.6 - Prob. 42ECh. 10.6 - Prob. 43ECh. 10.6 - Prob. 44ECh. 10.6 - Prob. 45ECh. 10.6 - Prob. 46ECh. 10.6 - Prob. 47ECh. 10.6 - Prob. 48ECh. 10.6 - Prob. 49ECh. 10.6 - Prob. 50ECh. 10.6 - Prob. 51ECh. 10.6 - Prob. 52ECh. 10.6 - Prob. 53ECh. 10.6 - Prob. 54ECh. 10.6 - Prob. 55ECh. 10.6 - Prob. 56ECh. 10.7 - Prob. 1CFUCh. 10.7 - Prob. 2CFUCh. 10.7 - Prob. 3CFUCh. 10.7 - Prob. 4CFUCh. 10.7 - Prob. 5CFUCh. 10.7 - Prob. 6CFUCh. 10.7 - Prob. 7CFUCh. 10.7 - Prob. 8CFUCh. 10.7 - Prob. 9CFUCh. 10.7 - Prob. 10CFUCh. 10.7 - Prob. 11CFUCh. 10.7 - Prob. 12CFUCh. 10.7 - Prob. 13ECh. 10.7 - Prob. 14ECh. 10.7 - Prob. 15ECh. 10.7 - Prob. 16ECh. 10.7 - Prob. 17ECh. 10.7 - Prob. 18ECh. 10.7 - Prob. 19ECh. 10.7 - Prob. 20ECh. 10.7 - Prob. 21ECh. 10.7 - Prob. 22ECh. 10.7 - Prob. 23ECh. 10.7 - Prob. 24ECh. 10.7 - Prob. 25ECh. 10.7 - Prob. 26ECh. 10.7 - Prob. 27ECh. 10.7 - Prob. 28ECh. 10.7 - Prob. 29ECh. 10.7 - Prob. 30ECh. 10.7 - Prob. 31ECh. 10.7 - Prob. 32ECh. 10.7 - Prob. 33ECh. 10.7 - Prob. 34ECh. 10.7 - Prob. 35ECh. 10.7 - Prob. 36ECh. 10.7 - Prob. 37ECh. 10.7 - Prob. 38ECh. 10.7 - Prob. 39ECh. 10.7 - Prob. 40ECh. 10.7 - Prob. 41ECh. 10.7 - Prob. 42ECh. 10.7 - Prob. 43ECh. 10.7 - Prob. 44ECh. 10.7 - Prob. 45ECh. 10.7 - Prob. 46ECh. 10.7 - Prob. 47ECh. 10.7 - Prob. 48ECh. 10.7 - Prob. 49ECh. 10.7 - Prob. 50ECh. 10.7 - Prob. 51ECh. 10.7 - Prob. 52ECh. 10.7 - Prob. 53ECh. 10.7 - Prob. 54ECh. 10.7 - Prob. 55ECh. 10.7 - Prob. 56ECh. 10.7 - Prob. 57ECh. 10.7 - Prob. 58ECh. 10.7 - Prob. 59ECh. 10.8 - Prob. 1CFUCh. 10.8 - Prob. 2CFUCh. 10.8 - Prob. 3CFUCh. 10.8 - Prob. 4CFUCh. 10.8 - Prob. 5CFUCh. 10.8 - Prob. 6CFUCh. 10.8 - Prob. 7CFUCh. 10.8 - Prob. 8CFUCh. 10.8 - Prob. 9CFUCh. 10.8 - Prob. 10CFUCh. 10.8 - Prob. 11CFUCh. 10.8 - Prob. 12CFUCh. 10.8 - Prob. 13ECh. 10.8 - Prob. 14ECh. 10.8 - Prob. 15ECh. 10.8 - Prob. 16ECh. 10.8 - Prob. 17ECh. 10.8 - Prob. 18ECh. 10.8 - Prob. 19ECh. 10.8 - Prob. 20ECh. 10.8 - Prob. 21ECh. 10.8 - Prob. 22ECh. 10.8 - Prob. 23ECh. 10.8 - Prob. 24ECh. 10.8 - Prob. 25ECh. 10.8 - Prob. 26ECh. 10.8 - Prob. 27ECh. 10.8 - Prob. 28ECh. 10.8 - Prob. 29ECh. 10.8 - Prob. 30ECh. 10.8 - Prob. 31ECh. 10.8 - Prob. 32ECh. 10.8 - Prob. 33ECh. 10.8 - Prob. 34ECh. 10.8 - Prob. 35ECh. 10.8 - Prob. 36ECh. 10.8 - Prob. 37ECh. 10.8 - Prob. 38ECh. 10.8 - Prob. 39ECh. 10.8 - Prob. 40ECh. 10.8 - Prob. 41ECh. 10.8 - Prob. 42ECh. 10.8 - Prob. 43ECh. 10.8 - Prob. 44ECh. 10.8 - Prob. 45ECh. 10.8 - Prob. 46ECh. 10.8 - Prob. 47ECh. 10.8 - Prob. 48ECh. 10.8 - Prob. 49ECh. 10.8 - Prob. 50ECh. 10.8B - Prob. 1GCECh. 10.8B - Prob. 2GCECh. 10.8B - 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