Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
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Chapter 10.6, Problem 43E

a.

To determine

A rectangular equation to model the shape of the clock.

a.

Expert Solution
Check Mark

Explanation of Solution

Given information:

The radius of the clock is 6 inches.

Calculations:

The shape of a clock is a circle.

The rectangular equation of a circle is,

   (xa) 2 + (yb) 2 = r 2 Where,(a,b) shows the coordiantes of the center and r shows the radius.

Let the clock starts at origin, therefore

  (a,b)=(0,0)

Thus the equation becomes,

  x2+y2=r2

The radius of the clock is 6 inches. .

Thus the equation becomes,

  x2+y2=62

b.

To determine

The parametric equations describing the motion of the tip as it moves from 12 o’clock noon to 12 o’clock noon.

b.

Expert Solution
Check Mark

Explanation of Solution

Given information:

The radius of the clock is 6 inches.

Calculations:

The shape of a clock is a circle.

The rectangular equation of a circle is,

   (xa) 2 + (yb) 2 = r 2 Where,(a,b) shows the coordiantes of the center and r shows the radius.

Let the clock starts at origin, therefore

  (a,b)=(0,0)

Thus the equation becomes,

  x2+y2=r2

The radius of the clock is 6 inches. .

Thus the equation becomes,

  x2+y2=62

Now the parametric equation of the circle is

  let,x=6sint.y=6cost.Therefore,x2+y2 (6sint) 2 + (6cost) 2 = 6 2 ( (sint) 2 + (cost) 2 )=62 Thus LFS=RHS.

Thus the parametric equation of the tip of the point is

  x=6sint.y=6cost0t4π

c.

To determine

The graph of the motion of the clock.

c.

Expert Solution
Check Mark

Explanation of Solution

The shape of a clock is a circle.

The rectangular equation of a circle is,

   (xa) 2 + (yb) 2 = r 2 Where,(a,b) shows the coordiantes of the center and r shows the radius.

Let the clock starts at origin, therefore

  (a,b)=(0,0)

Thus the equation becomes,

  x2+y2=r2

The radius of the clock is 6 inches. .

Thus the equation becomes,

  x2+y2=62

Now the parametric equation of the circle is

  let,x=6sint.y=6cost.Therefore,x2+y2 (6sint) 2 + (6cost) 2 = 6 2 ( (sint) 2 + (cost) 2 )=62 Thus LFS=RHS.

Thus the parametric equation of the tip of the point is

  x=6sint.y=6cost0t4π

The graph of the equation is shown below.

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.6, Problem 43E

Chapter 10 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 10.1 - Prob. 11CFUCh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.1 - Prob. 33ECh. 10.1 - Prob. 34ECh. 10.1 - Prob. 35ECh. 10.1 - Prob. 36ECh. 10.1 - Prob. 37ECh. 10.1 - Prob. 38ECh. 10.1 - Prob. 39ECh. 10.1 - Prob. 40ECh. 10.1 - Prob. 41ECh. 10.1 - Prob. 42ECh. 10.1 - Prob. 43ECh. 10.1 - Prob. 44ECh. 10.2 - Prob. 1CFUCh. 10.2 - Prob. 2CFUCh. 10.2 - Prob. 3CFUCh. 10.2 - Prob. 4CFUCh. 10.2 - Prob. 5CFUCh. 10.2 - Prob. 6CFUCh. 10.2 - Prob. 7CFUCh. 10.2 - Prob. 8CFUCh. 10.2 - Prob. 9CFUCh. 10.2 - Prob. 10CFUCh. 10.2 - Prob. 11CFUCh. 10.2 - Prob. 12CFUCh. 10.2 - Prob. 13CFUCh. 10.2 - Prob. 14CFUCh. 10.2 - Prob. 15ECh. 10.2 - 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