To find the heat effect for isothermal process at 300 K Concept Introduction: We find the enthalpy of H 2 SO 4 of pure and 25-wt-% from the H-x diagram of H 2 SO 4 Then we find the enthalpy of total solution and then find Q using the below equation, Q = m 3 H 3 − m 2 H 2 − m 1 H 1 Where, Mass of H 2 SO 4 (100 -wt-%) = m 1 Mass of H 2 SO 4 , (25-wt-%) = m 2 Mass of Total Solution = m 3 Enthalpy of H 2 SO 4 (100-wt-%) = H 1 Enthalpy of H 2 SO 4 (25-wt-%) = H 2 Enthalpy of % of H 2 SO 4 in total solution = H 3

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Answer 1

Question

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

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Answer 2

Question

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

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Answer 3

Question

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

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Answer 4

Question

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

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Answer 5

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

Answer 6

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

Answer 7

Chapter 11, Problem 11.18P

Interpretation Introduction

Interpretation:

To find the heat effect for isothermal process at 300 K

Concept Introduction:

We find the enthalpy of H₂SO₄of pure and 25-wt-% from the H-x diagram of H₂SO₄

Then we find the enthalpy of total solution and then find Q using the below equation,

Q=m3H3−m2H2−m1H1

Where,

Mass of H₂SO₄(100 -wt-%) = m₁

Mass of H₂SO₄_, (25-wt-%) = m₂

Mass of Total Solution = m₃

Enthalpy of H₂SO₄(100-wt-%) = H₁ Enthalpy of H₂SO₄(25-wt-%) = H₂

Enthalpy of % of H₂SO₄ in total solution = H₃

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 11 - Prob. 11.1P Ch. 11 - Prob. 11.2P Ch. 11 - Prob. 11.3P Ch. 11 - Prob. 11.4P Ch. 11 - Prob. 11.5P Ch. 11 - Prob. 11.6P Ch. 11 - Prob. 11.7P Ch. 11 - Prob. 11.8P Ch. 11 - Prob. 11.9P Ch. 11 - Prob. 11.10P

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Chapter 11 Solutions