To find the heat effect per mole of NaOH neutralized. Concept Introduction: First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions. The reaction is as given below, NaOH(s) + HCl(g) → NaCl(s) + H 2 O (l) The heat effect, Q is found for the reaction, NaOH.8 H 2 O + HCl.9 H 2 O → NaCl.8 H 2 O

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Answer 1

Question

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

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Answer 2

Question

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Expert Solution & Answer

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Answer 3

Question

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Expert Solution & Answer

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Answer 4

Question

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Expert Solution & Answer

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Answer 5

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Answer 6

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Answer 7

Chapter 11, Problem 11.31P

Interpretation Introduction

Interpretation:

To find the heat effect per mole of NaOH neutralized.

Concept Introduction:

First we find heat of formation of NaCl, NaOH and HCl. Then we find the heat of individual reactions.

The reaction is as given below,

NaOH(s) + HCl(g) → NaCl(s) + H₂O (l)

The heat effect, Q is found for the reaction,

NaOH.8 H₂O + HCl.9 H₂O → NaCl.8 H₂O

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 11 - Prob. 11.1P Ch. 11 - Prob. 11.2P Ch. 11 - Prob. 11.3P Ch. 11 - Prob. 11.4P Ch. 11 - Prob. 11.5P Ch. 11 - Prob. 11.6P Ch. 11 - Prob. 11.7P Ch. 11 - Prob. 11.8P Ch. 11 - Prob. 11.9P Ch. 11 - Prob. 11.10P

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Chapter 11 Solutions