The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn. Concept Introduction: Ester: The structure of an ester is, The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group Preparation of Esters: Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction. The general preparation of esters is shown below,

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Answer 1

Question

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

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Write the chemical equation for the reaction of ethanoic acid with N-methylethanamine. Which is formula of this rule of reaction?

Answer 2

Question

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

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Answer 3

Question

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

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Answer 4

Question

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

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Answer 5

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

Answer 6

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

Answer 7

Chapter 11, Problem 11D.29E

(a)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of butanoic acid and 2-propanol has to be drawn.

Concept Introduction:

Ester:

The structure of an ester is,

The carbonyl group of the ester is polar and could participate in dipole-dipole attractions. Hydrocarbon chains flank the carbonyl group

Preparation of Esters:

Esters are prepared from the reaction of carboxylic acid and an alcohol, with a loss of water molecule. Esterification is a condensation reaction because a molecule of water is removed during the reaction.

The general preparation of esters is shown below,

Answer 8

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

Answer 10

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

Answer 11

(c)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of hexanoic acid and methylethyl amine has to be drawn.

Concept Introduction:

Amides can be prepared in a reaction between a carboxylic acid and an amine. The acid derivative can be either an acid chloride or an acid anhydride.

The general reaction is,

Answer 12

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

Answer 13

(d)

Interpretation Introduction

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. 11 - Prob. 11A.1AST Ch. 11 - Prob. 11A.1BST Ch. 11 - Prob. 11A.2AST Ch. 11 - Prob. 11A.2BST Ch. 11 - Prob. 11A.3AST Ch. 11 - Prob. 11A.3BST Ch. 11 - Prob. 11A.4AST Ch. 11 - Prob. 11A.4BST Ch. 11 - Prob. 11A.5AST Ch. 11 - Prob. 11A.5BST

Concept explainers

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).

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Chapter 11 Solutions

Concept explainers

Interpretation: The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn. Concept Introduction: Refer to part (a).

Interpretation: The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn. Concept Introduction: Refer to part (d).

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Chapter 11 Solutions

Interpretation:

The product formed from the condensation reaction of ethanoic acid and 1-pentanol has to be drawn.

Concept Introduction:

Refer to part (a).

Interpretation:

The product formed from the condensation reaction of ethanoic acid and propylamine has to be drawn.

Concept Introduction:

Refer to part (d).