Genetic Analysis: An Integrated Approach (2nd Edition)
Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 11, Problem 20P

A eukaryote with a diploid number of 2n = 6 carries the chromosomes shown below and labeled (a) to (f).

Chapter 11, Problem 20P, A eukaryote with a diploid number of 2n=6 carries the chromosomes shown below and labeled (a) to

Carefully examine and redraw these chromosomes in any valid metaphase I alignment. Draw and label the metaphase plate, and label each chromosome by its assigned letter.

Explain how you determined the correct alignment of homologous chromosomes on opposite sides of the metaphase plate.

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in metaphase 1 of meiosis, the homologous chromosomes line up side by side along the equator so that crossing over can occur between the homologous pairs and the homologous chromosomes can be pulled to opposite poles during anaphase 1. in mitosis, by contrast, homologous chromosomes line up single file along the equator. what benefits are derived from these two different ways that homologous chromosomes are positioned at metaphase in meiosis and mitosis?
A wild-type chromosome has the following segments: A B C • D E F G H I Researchers have found individuals that are heterozygous for each of the following chromosome mutations. For each mutation, sketch how the wild-type and mutated chromosomes would pair in prophase I of meiosis, showing all chromosome strands. a. A B C • D E F D E F G H I b. A B C • D H I c. A B C • D G F E H I d. A B E D • C F G H I
Rice has a chromosome number of 2n = 24. If different aneuploids are available in rice, identifythe specific aneuploidy that shows the following chromosomal configurations at diakinesis ormetaphase I. Also provide the formula and chromosome number of the different aneuploids. Complete the table. Chromosome configuration at diakinesis or metaphase I Specific Type of Aneuploidy Formula (e.g. 2n+1) Chromosome number (2n=24) Types of gametes n, n+1, n+2, n-1, n-2) a. 1 III + 11 II         b. 1 IV + 11 II         c. 1 I + 11 II         d. 11 II         e. 2 I + 10 II
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