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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 11, Problem 39E
Textbook Problem
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Convert 725 mm Hg to the following:

a . torr b . atm c . in . Hg d . psi e . N/m 2

Interpretation Introduction

Interpretation:

The conversion of 725 mm Hg into the given units is to be represented.

Concept Introduction:

Pressure is a physical quantity that can be measured in different units based on the metric system or SI system.

Unit conversion is defined as the process, in which multiple steps are there, that is used to convert the unit of measurement for the same given quantity. It is determined by multiplying with a conversion factor.

The fraction in which the numerator and the denominator are the same quantities, but are determined in different units is known as the conversion factor.

Explanation of Solution

a) Torr

The conversion of mm Hg into torr is as follows:

1 mm Hg= 1 torr

To convert mm of Hg into torr, multiply mm Hg by 1torrmm Hg, which is a conversion factor.

Pressure in torr = 7.25×102mm Hg×1torrmm Hg=7.25×102 torr

Hence, the pressure in torr is 7.25×102 torr.

b) Atm.

The conversion of mm Hg into atm is as follows:

1 mm Hg =1760 atm

Pressure in atm=7.25×102mm Hg×atm760mm  Hg=0.954 atm

Thus, the pressure in atm is 0.954 atm.

c) In. Hg.

The conversion of mm Hg into in. Hg is as follows:

25.4 mm of Hg = 1 in. of Hg

To convert mm Hg into in Hg, multiply mm Hg by 125.4 in. Hgmm Hg, which is a conversion factor.

Pressure in in. Hg = 7.25×102mmhg×in. Hg25.4mmhgPressure in in

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