BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

Solutions

Chapter
Section
BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
6 views

A tank contains a mixture of 52 . 5 g of oxygen gas and 65 . 1 g of carbon dioxide gas at 27  ° C . The total pressure in the tank is 9.21 am. Calculate the partial pressure (in arm) of each gas in the mixture.

Interpretation Introduction

Interpretation:

The partial pressure of oxygen and carbon dioxide gas should be calculated.

Concept Introduction:

Dalton’s law of partial pressure: In a container for mixture of gases, the total pressure is equal to the sum of partial pressures of all the gases present in the container. The partial pressure is the pressure exerted by a gas if it is the only gas present in the container.

Let a mixture of three gases with partial pressures P1, P2 and P3, the total pressure of the gas will be sum of these partial pressures as follows:

PT=P1+P2+P3

This is the Dalton’s law of partial pressure.

The behaviour of gases is assumed to be ideal thus, partial pressure of gases can be calculated from an ideal gas equation as follows:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature of the gas.

The pressure exerted by an ideal gas depends on the number of gas particles, this does not depend on the nature of particles of gas. The two important things concluded from it will be:

  1. The volume of gases is important.
  2. The forces in between the particles of gas is not important.
Explanation

Calculation:

First calculate the number of moles of each gas as follows:

n=mM

Since, molar mass of O2 is 32 g/mol thus, number of moles will be:

nO2=52.5 g32 g/mol=1.64 mol

Similarly, molar mass of CO2 is 44.01 g/mol thus, number of moles will be:

nCO2=65.1 g44.01 g/mol=1.48 mol

Thus, total number of moles will be:

nT=nO2+nCO2

Putting the values,

nT=1.64 mol+1.48 mol=3.12 mol

From total pressure and number of moles, volume can be calculated using the ideal gas equation as follows:

PT=nTRTV

First convert the temperature from C to K as follows:

0 C=273.15 K

Thus,

27 C=(25+273.15) K=300.15 K

Putting the values,

9.21 atm=(3.12 mol)(0.082 L atm K1 mol1)(300.15 K)V

Thus,

V=(3

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 13 Solutions

Show all chapter solutions add
Sect-13.6 P-13.10SCSect-13.8 P-1CTSect-13.10 P-13.11SCSect-13.10 P-1CTSect-13.10 P-13.12SCCh-13 P-1ALQCh-13 P-2ALQCh-13 P-3ALQCh-13 P-4ALQCh-13 P-5ALQCh-13 P-6ALQCh-13 P-7ALQCh-13 P-8ALQCh-13 P-9ALQCh-13 P-10ALQCh-13 P-11ALQCh-13 P-12ALQCh-13 P-13ALQCh-13 P-14ALQCh-13 P-15ALQCh-13 P-16ALQCh-13 P-17ALQCh-13 P-18ALQCh-13 P-19ALQCh-13 P-20ALQCh-13 P-21ALQCh-13 P-22ALQCh-13 P-23ALQCh-13 P-1QAPCh-13 P-2QAPCh-13 P-3QAPCh-13 P-4QAPCh-13 P-5QAPCh-13 P-6QAPCh-13 P-7QAPCh-13 P-8QAPCh-13 P-9QAPCh-13 P-10QAPCh-13 P-11QAPCh-13 P-12QAPCh-13 P-13QAPCh-13 P-14QAPCh-13 P-15QAPCh-13 P-16QAPCh-13 P-17QAPCh-13 P-18QAPCh-13 P-19QAPCh-13 P-20QAPCh-13 P-21QAPCh-13 P-22QAPCh-13 P-23QAPCh-13 P-24QAPCh-13 P-25QAPCh-13 P-26QAPCh-13 P-27QAPCh-13 P-28QAPCh-13 P-29QAPCh-13 P-30QAPCh-13 P-31QAPCh-13 P-32QAPCh-13 P-33QAPCh-13 P-34QAPCh-13 P-35QAPCh-13 P-36QAPCh-13 P-37QAPCh-13 P-38QAPCh-13 P-39QAPCh-13 P-40QAPCh-13 P-41QAPCh-13 P-42QAPCh-13 P-43QAPCh-13 P-44QAPCh-13 P-45QAPCh-13 P-46QAPCh-13 P-47QAPCh-13 P-48QAPCh-13 P-49QAPCh-13 P-50QAPCh-13 P-51QAPCh-13 P-52QAPCh-13 P-53QAPCh-13 P-54QAPCh-13 P-55QAPCh-13 P-56QAPCh-13 P-57QAPCh-13 P-58QAPCh-13 P-59QAPCh-13 P-60QAPCh-13 P-61QAPCh-13 P-62QAPCh-13 P-63QAPCh-13 P-64QAPCh-13 P-65QAPCh-13 P-66QAPCh-13 P-67QAPCh-13 P-68QAPCh-13 P-69QAPCh-13 P-70QAPCh-13 P-71QAPCh-13 P-72QAPCh-13 P-73QAPCh-13 P-74QAPCh-13 P-75QAPCh-13 P-76QAPCh-13 P-77QAPCh-13 P-78QAPCh-13 P-79QAPCh-13 P-80QAPCh-13 P-81QAPCh-13 P-82QAPCh-13 P-83QAPCh-13 P-84QAPCh-13 P-85QAPCh-13 P-86QAPCh-13 P-87QAPCh-13 P-88QAPCh-13 P-89QAPCh-13 P-90QAPCh-13 P-91QAPCh-13 P-92QAPCh-13 P-93QAPCh-13 P-94QAPCh-13 P-95QAPCh-13 P-96QAPCh-13 P-97QAPCh-13 P-98QAPCh-13 P-99QAPCh-13 P-100QAPCh-13 P-101QAPCh-13 P-102QAPCh-13 P-103APCh-13 P-104APCh-13 P-105APCh-13 P-106APCh-13 P-107APCh-13 P-108APCh-13 P-109APCh-13 P-110APCh-13 P-111APCh-13 P-112APCh-13 P-113APCh-13 P-114APCh-13 P-115APCh-13 P-116APCh-13 P-117APCh-13 P-118APCh-13 P-119APCh-13 P-120APCh-13 P-121APCh-13 P-122APCh-13 P-123APCh-13 P-124APCh-13 P-125APCh-13 P-126APCh-13 P-127APCh-13 P-128APCh-13 P-129APCh-13 P-130APCh-13 P-131APCh-13 P-132APCh-13 P-133APCh-13 P-134APCh-13 P-135APCh-13 P-136APCh-13 P-137APCh-13 P-138APCh-13 P-139APCh-13 P-140APCh-13 P-141APCh-13 P-142APCh-13 P-143APCh-13 P-144APCh-13 P-145APCh-13 P-146APCh-13 P-147APCh-13 P-148APCh-13 P-149APCh-13 P-150CPCh-13 P-151CPCh-13 P-152CPCh-13 P-153CPCh-13 P-154CPCh-13 P-155CPCh-13 P-156CPCh-13 P-157CP

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Compare and contrast solids, liquids, and gases.

Chemistry: An Atoms First Approach

Diets with sufficient protein may provide more satiety than diets that are low in protein.

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Why does a stars life expectancy depend on its mass?

Horizons: Exploring the Universe (MindTap Course List)

Match the term listed in Column A with its definition from Column B

Nutrition Through the Life Cycle (MindTap Course List)

True or false? DNA barcoding can identify an individual as belonging to a particular species.

Biology: The Unity and Diversity of Life (MindTap Course List)

How many significant figures are in the following numbers? (a) 78.9 0.2 (b) 3.788 109 (c) 2.46 106 (d) 0.005...

Physics for Scientists and Engineers, Technology Update (No access codes included)