Concept explainers
To find the range and standard deviation of each data set.
Answer to Problem 5CR
Standard deviation and mean for player A are 15.56 and 201 respectively.
Standard deviation and mean for player B 30.32 and 201.
Explanation of Solution
Given information:
Two datasets of bowling scores.
Formula used:
Mean,
Standard deviation,
Calculation:
Store A,
N=10
Substituting values,
Solving,
Mean is 201.0
Standard deviation,
Items | ||
205 | 4 | 16 |
185 | -16 | 256 |
210 | 9 | 81 |
174 | -27 | 729 |
194 | -7 | 49 |
190 | -11 | 121 |
200 | -1 | 1 |
219 | 18 | 324 |
203 | 2 | 4 |
230 | 29 | 841 |
Substituting values,
Hence, standard deviation for store A is 15.56.
Player B,
N=10
Substituting values,
Solving,
Mean is 201.0
Standard deviation,
Items | ||
228 | 27 | 729 |
172 | 29 | 841 |
154 | 47 | 2209 |
235 | 34 | 1156 |
168 | -33 | 1089 |
205 | 4 | 16 |
181 | -20 | 400 |
240 | 39 | 1521 |
235 | 34 | 1156 |
192 | -9 | 81 |
Substituting values,
Hence, standard deviation for player B is 30.32.
Chapter 11 Solutions
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