   Chapter 11.2, Problem 41E ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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# Use the drawing provided to show that the area of the isosceles triangle is A = s 2 sin θ cos θ To determine

To find:

To show that the area of the isosceles triangle is A=s2sinθcosθ by using the following figure, Explanation

Consider the following figure,

Let us put the name for the isosceles triangle ia ABC and altitude is AD¯

We know that BD=DC=base2

Assume that BD=DC=xunits

General formula for cosine ratio and sin ratio is given below,

From the above figure shows that the s is the value of hypotenuse since it is opposite to right angle.

Then DC is the length of the leg opposite to θ.

Therefore,

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