 # At 15°C and a partial pressure of 2.14 atm, the solubility of an unknown gas in a liquid is 15.6 g/L. What is the solubility of the gas in the liquid when the partial pressure of the gas is 24.6 atm? What would happen to the solubility of the gas if the temperature of the liquid were increased? ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343 ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

#### Solutions

Chapter
Section
Chapter 12, Problem 12.123QP
Textbook Problem

## At 15°C and a partial pressure of 2.14 atm, the solubility of an unknown gas in a liquid is 15.6 g/L. What is the solubility of the gas in the liquid when the partial pressure of the gas is 24.6 atm? What would happen to the solubility of the gas if the temperature of the liquid were increased?

Expert Solution
Interpretation Introduction

Interpretation:

Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated.

Concept Introduction:

Solubility of a gas in liquid is explained by Henry’s law which states –

“At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.”

It is expressed as,

S α P

Where,

S = SolubilityP = Partial pressure

Introducing proportionality constant,

S = kHP

Where,

kH is Henry’s constant.

Solubility of a same gas at two different pressures can be calculated as,

S2S1 = kHP2kHP1 = P2P1

### Explanation of Solution

The solubility of an unknown gas S1, at partial pressure, P1 2.14 atm is 15.6 g/L .

Let S2 be the solubility of gas at partial pressure P2 24.6 atm

Then,

S2S1 =P2P1S2 = S1×P2P1 = (15

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