CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<
CHEMISTRY FOR TODAY+OWLV2 24 MO>IP<
9th Edition
ISBN: 9780357107317
Author: Seager
Publisher: CENGAGE L
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Chapter 12, Problem 12.18E
Interpretation Introduction

(a)

Interpretation:

Whether the alkene (CH3CH2CH2CH=CH2) could exist as cis-trans isomers or not is to be predicted. The structural formulas and names of both the cis- and the trans- isomers are to be stated if the corresponding alkene shows isomerism.

Concept introduction:

Those compounds which have the same molecular formula but have different arrangements of atoms are known as isomers. The phenomenon is called isomerism. The isomers are generally classified as structural isomers and stereoisomers. Stereoisomers are further divided into two categories diastereomers and enantiomers.

Expert Solution
Check Mark

Answer to Problem 12.18E

The alkene (CH3CH2CH2CH=CH2) will not have cis-trans isomers.

Explanation of Solution

The alkene is CH3CH2CH2CH=CH2.

A compound shows cis-trans isomerism when the substituent groups on the carbon atoms that are connected via double bond are different. The alkene has the same substituted groups on a carbon atom that is on the right-hand side of the double bond. Therefore; it will not have cis-trans isomerism.

Conclusion

The alkene (CH3CH2CH2CH=CH2) will not have cis-trans isomers.

Interpretation Introduction

(b)

Interpretation:

Whether the alkene (CH3CH2CH=CHCH2CH3) could exist as cis-trans isomers or not is to be predicted. The structural formulas and names of both the cis- and the trans- isomers are to be stated if the corresponding alkene shows isomerism.

Concept introduction:

Those compounds which have the same molecular formula but have different arrangements of atoms are known as isomers. This phenomenon is called isomerism. The isomers are generally classified as structural isomers and stereoisomers. Stereoisomers are further divided into two categories diastereomers and enantiomers.

Expert Solution
Check Mark

Answer to Problem 12.18E

The alkene (CH3CH2CH=CHCH2CH3) will have cis-trans isomers. The structures of cis-trans isomers of the alkene are shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.18E , additional homework tip  1

Explanation of Solution

The alkene is CH3CH2CH=CHCH2CH3.

A compound shows cis-trans isomerism when the substituents groups on the carbon atoms that are connected via double bond are different. The alkene has two different substituted groups on carbon atoms that are connected via a double bond. Therefore, it will show cis-trans isomerism. In the cis isomer, same substituted groups are on the same side of a ring or double bonds, whereas in the trans isomer same substituted groups are on a different side of a ring or double bond. Therefore, the structures of cis-trans isomers of the alkene are shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.18E , additional homework tip  2

Figure 1

Conclusion

The alkene (CH3CH2CH=CHCH2CH3) will have cis-trans isomers. The structures of cis-trans isomers of the alkene are shown in Figure 1.

Interpretation Introduction

(c)

Interpretation:

Whether the alkene ((CH3)2C=CHCH2CH3) could exist as cis-trans isomers or not is to be predicted. The structural formulas and names of both the cis- and the trans- isomers are to be stated if the corresponding alkene shows isomerism.

Concept introduction:

Those compounds which have the same molecular formula but have different arrangements of atoms are known as isomers. The phenomenon is called isomerism. The isomers are generally classified as structural isomers and stereoisomers. Stereoisomers are further divided into two categories diastereomers and enantiomers.

Expert Solution
Check Mark

Answer to Problem 12.18E

The alkene ((CH3)2C=CHCH2CH3) will not have cis-trans isomers.

Explanation of Solution

The structure of the alkene ((CH3)2C=CHCH2CH3) is shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.18E , additional homework tip  3

Figure 2

A compound shows cis-trans isomerism when the substituents groups on the carbon atoms that are connected via double bond are different. The alkene has the same substituted groups on a carbon atom that is on the left-hand side of the double bond. Therefore, it will not have cis-trans isomerism.

Conclusion

The alkene ((CH3)2C=CHCH2CH3) will not have cis-trans isomers.

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Chapter 12 Solutions

CHEMISTRY FOR TODAY+OWLV2 24 MO>IP<

Ch. 12 - Prob. 12.11ECh. 12 - Prob. 12.12ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - What type of orbital overlaps to form a pi bond in...Ch. 12 - Prob. 12.15ECh. 12 - Explain the difference between geometric and...Ch. 12 - Draw structural formulas and give IUPAC names for...Ch. 12 - Prob. 12.18ECh. 12 - Which of the following alkenes can exist as...Ch. 12 - Draw structural formulas for the following:...Ch. 12 - Prob. 12.21ECh. 12 - In what ways are the physical properties of...Ch. 12 - Prob. 12.23ECh. 12 - Prob. 12.24ECh. 12 - Complete the following reactions. Where more than...Ch. 12 - Prob. 12.26ECh. 12 - Prob. 12.27ECh. 12 - What reagents would you use to prepare each of the...Ch. 12 - What is an important commercial application of...Ch. 12 - Prob. 12.30ECh. 12 - Terpin hydrate is used medicinally as an...Ch. 12 - Prob. 12.32ECh. 12 - Prob. 12.33ECh. 12 - Prob. 12.34ECh. 12 - Prob. 12.35ECh. 12 - Much of todays plumbing in newly built homes is...Ch. 12 - Prob. 12.37ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - How many sigma bonds and how many pi bonds make up...Ch. 12 - Prob. 12.40ECh. 12 - Explain why geometric isomerism is not possible in...Ch. 12 - Give the common name and major uses of the...Ch. 12 - Describe the physical and chemical properties of...Ch. 12 - Prob. 12.44ECh. 12 - Prob. 12.45ECh. 12 - Prob. 12.46ECh. 12 - Prob. 12.47ECh. 12 - Prob. 12.48ECh. 12 - Limonene, which is present in citrus peelings, has...Ch. 12 - A disubstituted cycloalkane such as a exhibits...Ch. 12 - Prob. 12.51ECh. 12 - Prob. 12.52ECh. 12 - Give an IUPAC name for the following as...Ch. 12 - Give an IUPAC name for the following as...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Prob. 12.59ECh. 12 - Write structural formulas for the following:...Ch. 12 - Prob. 12.61ECh. 12 - Prob. 12.62ECh. 12 - Prob. 12.63ECh. 12 - Prob. 12.64ECh. 12 - Prob. 12.65ECh. 12 - Prob. 12.66ECh. 12 - Prob. 12.67ECh. 12 - Prob. 12.68ECh. 12 - Prob. 12.69ECh. 12 - Prob. 12.70ECh. 12 - Prob. 12.71ECh. 12 - Prob. 12.72ECh. 12 - Prob. 12.73ECh. 12 - Prob. 12.74ECh. 12 - Prob. 12.75ECh. 12 - Prob. 12.76ECh. 12 - Prob. 12.77ECh. 12 - Prob. 12.78ECh. 12 - Prob. 12.79ECh. 12 - Prob. 12.80ECh. 12 - Prob. 12.81ECh. 12 - Prob. 12.82ECh. 12 - Prob. 12.83ECh. 12 - The compound CH2=CHCH2CH2CH3 is an example of: a....Ch. 12 - The correct structural for ethyne is: a. HC=CH b....Ch. 12 - Prob. 12.86E
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