CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<
CHEMISTRY FOR TODAY+OWLV2 24 MO>IP<
9th Edition
ISBN: 9780357107317
Author: Seager
Publisher: CENGAGE L
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Chapter 12, Problem 12.4E
Interpretation Introduction

(a)

Interpretation:

The IUPAC name for the compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is but-2-ene.

Explanation of Solution

The compound is given as CH3CH=CHCH3. The parent chain is butene, that is, it consists of four carbon atoms and a double bond between the second and the third carbon atoms as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  1

Figure 1

Therefore, the name of the compound is but-2-ene.

Conclusion

The name of compound is but-2-ene.

Interpretation Introduction

(b)

Interpretation:

The IUPAC name for compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of the given compound is 3-ethyl-pent-2-ene.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  2

Figure 2

The parent chain is pentene, that is, it consists of five carbon atoms and a double bond between the second and the third carbon atoms. An ethyl group is present as a substituent on the third carbon atom as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  3

Figure 3

Therefore, the name of compound is 3-ethyl-pent-2-ene.

Conclusion

The name of compound is 3-ethyl-pent-2-ene.

Interpretation Introduction

(c)

Interpretation:

The IUPAC name for the given compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is 4, 4-dimethyl-hex-2-yne.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  4

Figure 4

The parent chain is hexyne, that is, it consists of six carbon atoms and a triple bond between the second and the third carbon atoms. Two methyl groups are present as a substituent on the fourth carbon atom as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  5

Figure 5

Therefore, the name of compound is 4, 4-dimethyl-hex-2-yne.

Conclusion

The name of compound is 4, 4-dimethyl-hex-2-yne.

Interpretation Introduction

(d)

Interpretation:

The IUPAC name for the given compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is 4-methyl-cyclopent-1-ene.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  6

Figure 6

The parent chain is cyclopentene, that is, it consists of five carbon atoms in a ring and a double bond between the first and the second carbon atoms. A methyl group is present as a substituent on the fourth carbon atom as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  7

Figure 7

Therefore, the name of compound is 4-methyl-cyclopent-1-ene.

Conclusion

The name of compound is 4-methyl-cyclopent-1-ene.

Interpretation Introduction

(e)

Interpretation:

The IUPAC name for compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is 6-bromo-2-methyl-hept-3-yne.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  8

Figure 8

The parent chain is heptyne, that is, it consists of seven carbon atoms and a triple bond between the third and the fourth carbon atoms. A methyl group and a bromine group are present as substituents on the second and the sixth carbon atoms respectively as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  9

Figure 9

Therefore, the name of the given compound is 6-bromo-2-methyl-hept-3-yne.

Conclusion

The name of compound is 6-bromo-2-methyl-hept-3-yne.

Interpretation Introduction

(f)

Interpretation:

The IUPAC name for the given compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is 1-ethyl-2, 3-dimethylcycloprop-1-ene.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  10

Figure 10

The parent chain is cyclopropene, that is, it consists of three carbon atoms and a double bond between the first and the second carbon atoms. An ethyl group and two methyl groups are present as a substituent on the first, second and the third carbon atoms respectively as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  11

Figure 11

Therefore, the name of compound is 1-ethyl-2, 3-dimethylcycloprop-1-ene.

Conclusion

The name of compound is 1-ethyl-2, 3-dimethylcycloprop-1-ene.

Interpretation Introduction

(g)

Interpretation:

The IUPAC name for compound is to be stated.

Concept introduction:

The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are shown below.

• First identify the longest carbon chain.

• The next step is to identify the groups attached to the longest chain.

• Identify the position, location, and number of the substituents bonded to the carbon chain.

• Use prefix di, tri, tetra if same type of substituents are present.

• Name the substituents in alphabetical order.

Expert Solution
Check Mark

Answer to Problem 12.4E

The name of compound is 6-methyl-hepta-2, 4-diene.

Explanation of Solution

The compound is given as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  12

Figure 12

The parent chain is heptadiene, that is, it consists of seven carbon atoms and double bonds between the first, second and the fourth, fifth carbon atoms. A methyl group is present as a substituent on the sixth carbon atom as shown below.

CHEMISTRY FOR TODAY+OWLV2  24 MO>IP<, Chapter 12, Problem 12.4E , additional homework tip  13

Figure 13

Therefore, the name of compound is 6-methyl-hepta-2, 4-diene.

Conclusion

The name of compound is 6-methyl-hepta-2, 4-diene.

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Chapter 12 Solutions

CHEMISTRY FOR TODAY+OWLV2 24 MO>IP<

Ch. 12 - Prob. 12.11ECh. 12 - Prob. 12.12ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - What type of orbital overlaps to form a pi bond in...Ch. 12 - Prob. 12.15ECh. 12 - Explain the difference between geometric and...Ch. 12 - Draw structural formulas and give IUPAC names for...Ch. 12 - Prob. 12.18ECh. 12 - Which of the following alkenes can exist as...Ch. 12 - Draw structural formulas for the following:...Ch. 12 - Prob. 12.21ECh. 12 - In what ways are the physical properties of...Ch. 12 - Prob. 12.23ECh. 12 - Prob. 12.24ECh. 12 - Complete the following reactions. Where more than...Ch. 12 - Prob. 12.26ECh. 12 - Prob. 12.27ECh. 12 - What reagents would you use to prepare each of the...Ch. 12 - What is an important commercial application of...Ch. 12 - Prob. 12.30ECh. 12 - Terpin hydrate is used medicinally as an...Ch. 12 - Prob. 12.32ECh. 12 - Prob. 12.33ECh. 12 - Prob. 12.34ECh. 12 - Prob. 12.35ECh. 12 - Much of todays plumbing in newly built homes is...Ch. 12 - Prob. 12.37ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - How many sigma bonds and how many pi bonds make up...Ch. 12 - Prob. 12.40ECh. 12 - Explain why geometric isomerism is not possible in...Ch. 12 - Give the common name and major uses of the...Ch. 12 - Describe the physical and chemical properties of...Ch. 12 - Prob. 12.44ECh. 12 - Prob. 12.45ECh. 12 - Prob. 12.46ECh. 12 - Prob. 12.47ECh. 12 - Prob. 12.48ECh. 12 - Limonene, which is present in citrus peelings, has...Ch. 12 - A disubstituted cycloalkane such as a exhibits...Ch. 12 - Prob. 12.51ECh. 12 - Prob. 12.52ECh. 12 - Give an IUPAC name for the following as...Ch. 12 - Give an IUPAC name for the following as...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Prob. 12.59ECh. 12 - Write structural formulas for the following:...Ch. 12 - Prob. 12.61ECh. 12 - Prob. 12.62ECh. 12 - Prob. 12.63ECh. 12 - Prob. 12.64ECh. 12 - Prob. 12.65ECh. 12 - Prob. 12.66ECh. 12 - Prob. 12.67ECh. 12 - Prob. 12.68ECh. 12 - Prob. 12.69ECh. 12 - Prob. 12.70ECh. 12 - Prob. 12.71ECh. 12 - Prob. 12.72ECh. 12 - Prob. 12.73ECh. 12 - Prob. 12.74ECh. 12 - Prob. 12.75ECh. 12 - Prob. 12.76ECh. 12 - Prob. 12.77ECh. 12 - Prob. 12.78ECh. 12 - Prob. 12.79ECh. 12 - Prob. 12.80ECh. 12 - Prob. 12.81ECh. 12 - Prob. 12.82ECh. 12 - Prob. 12.83ECh. 12 - The compound CH2=CHCH2CH2CH3 is an example of: a....Ch. 12 - The correct structural for ethyne is: a. HC=CH b....Ch. 12 - Prob. 12.86E
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