Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 12, Problem 12.40SP
A solid aluminum shaft, 6 ft in length, is to transmit a torque of 350 lb-ft. The allowable shear stress is 5000 psi and the angle of twist must not exceed
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A 5 ft long solid SAE4340 OQT1000 steel shaft is required to transmit a power of 180 HP. The shaft speed is 3,000 rpm. The allowable shear stress is 50 ksi and the allowable angle of twist per foot of length is 0.04 radians. Determine the minimum diameter that meets the design requirements.
Determine the maximum torque that can be applied to a hollow circular steel shaft of 100mm outer diameter and 80mm inner diameter. The shear stress is limited to 70 MPa, and the angle of twist must not exceed 0.4 degrees in a length of one meter. Use G = 83 GPa for steel.
What is the minimum diameter of a solid steel shaft that will not twist through more than 3˚ in a6-m length when subjected to a torque of 15 KN-m? What maximum shearing stress isdeveloped? Use G=85 GPa.
Chapter 12 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 12 - Determine the internal resisting torque in the...Ch. 12 - Determine the internal resisting torque in the...Ch. 12 - Calculate the maximum shear stress developed in a...Ch. 12 - Calculate the allowable torque for a hollow steel...Ch. 12 - Calculate the allowable torque that may be applied...Ch. 12 - A hollow circular steel shaft has a 100-mm outside...Ch. 12 - Design a solid circular steel shaft to transmit an...Ch. 12 - Calculate the shear stresses at the outer and...Ch. 12 - A hollow shaft is produced by boring a...Ch. 12 - Pulleys C and D are attached to shaft AB, as...
Ch. 12 - Calculate the angle of twist a 3-in-diameter...Ch. 12 - Calculate the angle of twist a 65-mm-diameter...Ch. 12 - Calculate the angle of twist a 4-in.-diameter...Ch. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - A solid steel shaft is to resist a torque of 9000...Ch. 12 - A hollow steel shaft has a 50-mm outside diameter...Ch. 12 - If the shaft of Problem 12.17 were solid, with the...Ch. 12 - An automobile engine develops 90 hp at 3500 rpm....Ch. 12 - Calculate the speed (rpm) at which a...Ch. 12 - Select the diameter of a solid circular steel...Ch. 12 - Select the diameter for a hollow steel shaft that...Ch. 12 - A 6-ft-long solid steel shaft with a diameter of 4...Ch. 12 - The outside and inside diameters of a hollow steel...Ch. 12 - Calculate the maximum shear stress developed in a...Ch. 12 - Write a program that will calculate the allowable...Ch. 12 - Write a program that will generate a table of...Ch. 12 - Rework the program of Problem 12.27 using SI...Ch. 12 - Write a program that will generate a table of...Ch. 12 - Compute the maximum shear stress in the hollow...Ch. 12 - Calculate the allowable torque that may be applied...Ch. 12 - Design a hollow steel shaft to transmit a torque...Ch. 12 - A 32-in.-long solid steel circular shaft, 3 in. in...Ch. 12 - The 65-mm-diameter solid shaft shown is subjected...Ch. 12 - Rework Problem 12.34, changing the diameter of...Ch. 12 - Compute the maximum shear stress in the circular...Ch. 12 - Determine the allowable torque a hollow steel...Ch. 12 - A 1.00-m-long steel wire, 4 mm in diameter, is...Ch. 12 - Select the outside and inside diameters for a...Ch. 12 - A solid aluminum shaft, 6 ft in length, is to...Ch. 12 - A 25-mm-diameter solid shaft with an allowable...Ch. 12 - Compute a. the maximum shear stress developed in a...Ch. 12 - What horsepower can a solid steel shaft 6 in. in...Ch. 12 - Calculate the maximum power that may be...Ch. 12 - A small ski lift has a main cable driving wheel 11...Ch. 12 - A 32-mm-diameter solid shaft transmits 100 kW of...Ch. 12 - A solid steel shaft is to transmit power of 58 kW...Ch. 12 - Select the diameter for a solid steel shaft that...Ch. 12 - A solid steel shaft is to transmit 100 hp at a...Ch. 12 - Two shafts-one a hollow steel shaft with an...Ch. 12 - A 112 -in.-diameter solid steel shaft is 40 ft in...Ch. 12 - A solid steel shaft is to transmit 120 hp. The...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A solid steel shaft will not twist through more than 3° in a 6.0 m length when subjected to a torque of 12 kN·m. What maximum shearing stress is developed? Use G = 83 GPaarrow_forwardDetermine the minimum diameter that can be used for a solid circular steel shaft which is limited to an allowable shear stress of 70 MPa and a maximum angle of twist of 1.5o (degrees) per meter length. Applied maximum torque is 25 KN-m and the overall shaft length is 1.25 meters. Shear modulus = G= 80 GPa Note: When using torsion stress formulas, you must convert the angle of twist from degrees to radians.arrow_forwardA solid circular shaft is subjected to a torque of 21,334 in-lb. Calculate the diameter required if the allowable twist is 1.7° per foot, and the material is steel alloy which has a modulus of rigidity of 12,000,000 psi.arrow_forward
- Determine the diameter of a solid steel shaft which will transmit 112.5 kW at 200 rpm. Also determine the length of the shaft if the twist must not exceed 1.5o over the entire length. The maximum shear stress is limited to 55 N/mm2. Take the value of modulus of rigidity = 8 x 104 N/mm2.arrow_forwardDetermine the distribution of shear stress in the following circular shafts that are subject to a maximum torque of 7.5 Nm by calculating the polar second moment of area.arrow_forwardCalculate the maximum permissible torque on a hollow shaft if the maximum allowable shearing stress is 83 MPa. D=75mm and d=60mm. A)4788 Nm B)4316 Nm C)4059 Nm D)4532 Nmarrow_forward
- A 5 ft long solid SAE4340 OQT1000 steel shaft is required to transmit a power of 180 HP. The shaft speed is 3,000 rpm. The allowable shear stress is 50 ksi and the allowable angle of twist per foot of length is 0.04 radians. Determine the minimum diameter that meets the design requirements. Note- Shear modulus for steel is given in imagesarrow_forwardA solid shaft in a rolling mill transmits 30 hp at 100 rpm. Find the diameter in mm of the shaft so as not to exceed a shearing stress of 42 MPa and an angle of twist of more than 5 degrees in a length of 3 meters. G = 83 GPaarrow_forwardcomplete solution A solid steel shaft must not twist through more than 30 in a 6-m length whented to a torque of 12 kN • m. (a) Find the diameter of the smallest shaft thatcan be used. (b) What is the maximum shear stress in the shaft of this diameter? UseG = 83 GPa for steel.arrow_forward
- A hollow circular shaft with the ratio of internal and external diameters of 0.6 is required to transmit 870 kW at 120 rpm, the maximum torque being 20% greater than the mean. Determine the dimensions of the shaft if the maximum shearing stress and twist in a length of 3m are limited to 60Mpa and 1.4°respectively. The G= 80Gpa.arrow_forward200 HP is delivered by a solid circular shaft at 1000 rpm rotational speed. If a hollow shaft is used having an inside diameter equal to the diameter of the solid shaft, determine what must be the outside diameter of this shaft if the angular twist of the hollow and solid shaft is to be equal? The allowable maximum shearing stress is 20,000 psi.arrow_forwardA composite shaft is comprised of an inner solid steel shaft 1/6 ft in diameter slipped over with a hollow bronze shaft of 1/4 ft outer dimater and 1/6 ft inner diameter and of the same length as the steel shaft. The two shafts are then fastened rigidly together at their ends. For steel, G = 12 × 106 psi, and for bronze, G = 6 × 106 psi. What torque can be applied to the composite shaft without exceeding a shearing stress of 12,000 psi in the steel or 8,000 psi in the bronze?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Everything About COMBINED LOADING in 10 Minutes! Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=N-PlI900hSg;License: Standard youtube license